Giải hộ e với ạ
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
19 tháng 12 2021
a: Xét ΔABE và ΔACD có
AB=AC
\(\widehat{A}\) chung
AE=AD
Do đó: ΔABE=ΔACD
19 tháng 12 2021
\(a,\left\{{}\begin{matrix}AB=AC\\AD=AE\\\widehat{BAC}\text{ chung}\end{matrix}\right.\Rightarrow\Delta ABE=\Delta ACD\left(c.g.c\right)\\ b,\Delta ABE=\Delta ACD\\ \Rightarrow\widehat{AEB}=\widehat{ADC}\\ \Rightarrow180^0-\widehat{AEB}=180^0-\widehat{ADC}\\ \Rightarrow\widehat{BDC}=\widehat{CEB}\)
giải hộ e với ạ
CM
0
DT
Đỗ Thanh Hải
CTVVIP
18 tháng 4 2021
Writing 1
1 I and my family have just returned from a trip to Da Lat
2 It was about 30 kilometers from my house, so we went there by bus
3 Da Lat was beautiful and clean
4 The people were friendly and the weather was cool and cloudy
5 We felt happy and excited after the trip
Writing 2
1 Thank you so much for the flowers you sent me last week
2 They were beautiful and they really help cheering me up
3 I came out of the hospital on Monday morning
4 Now I am sad. Will you come to my place next weekend?
HP
27 tháng 9 2021
a. \(4\dfrac{1}{4}-2\dfrac{5}{8}+2\dfrac{3}{5}=\dfrac{17}{4}-\dfrac{21}{8}+\dfrac{13}{5}=\dfrac{169}{40}\)
b. \(4\dfrac{4}{9}:2\dfrac{2}{3}+3\dfrac{1}{6}=\dfrac{40}{9}:\dfrac{8}{3}+\dfrac{19}{6}=\dfrac{5}{3}+\dfrac{19}{6}=\dfrac{29}{6}\)
c. \(3\dfrac{1}{5}+2\dfrac{3}{5}-2\dfrac{4}{5}=\dfrac{16}{5}+\dfrac{13}{5}-\dfrac{14}{5}=\dfrac{16+13-14}{5}=\dfrac{15}{5}=3\)
d. \(5\dfrac{1}{7}-2\dfrac{4}{5}:1\dfrac{1}{5}=\dfrac{36}{7}-\dfrac{14}{5}:\dfrac{6}{5}=\dfrac{36}{7}-\dfrac{7}{3}=\dfrac{59}{21}\)
e. \(2\dfrac{3}{5}+1\dfrac{1}{4}.2\dfrac{2}{3}=\dfrac{13}{5}+\dfrac{5}{4}.\dfrac{8}{3}=\dfrac{13}{5}+\dfrac{10}{3}=\dfrac{89}{15}\)
g. \(4\dfrac{1}{3}.1\dfrac{1}{2}+5\dfrac{2}{7}=\dfrac{13}{3}.\dfrac{3}{2}+\dfrac{37}{7}=\dfrac{13}{2}+\dfrac{37}{7}=\dfrac{165}{14}\)
21 tháng 10 2021
Bài 1:
\(a.8,6\\ b.54,76\\ c.43,562\\ d.13,035\\ e.0,101\\ g.55,555\)
9:
a: S
b: Đ
10: =-6*2/3=-4