a y x 2/7 = 49/2
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a) \(\left(x^2+7\right)\left(x^2-49\right)< 0\)
\(\left(x^2+7\right)\left(x-7\right)\left(x+7\right)< 0\)
\(\Leftrightarrow\hept{\begin{cases}x-7>0\\x+7< 0\end{cases}}\) hoặc \(\hept{\begin{cases}x-7< 0\\x+7>0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x>7\\x< -7\end{cases}}\) hoặc \(\hept{\begin{cases}x< 7\\x>-7\end{cases}}\)
\(\Leftrightarrow-7< x< 7\)
vậy....
a, Vì x^2+7 > 0
=> x^2-49 < 0
=> x^2 < 49
=> -7 < x < 7
b, => x^2-7 >= 0 ; x^2-49 >= 0 hoặc x^2-7 < = 0 ; x^2 - 49 < = 0
=> x^2 > 49 hoặc x^2 < 7
=> x > 7 hoặc x < - 7 hoặc - \(\sqrt{7}< x< \sqrt{7}\)
Tk mk nha
a) \(\frac{x}{2}-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)
\(\frac{x}{2}-\frac{11}{5}=\frac{8}{7}\)
\(\frac{x}{2}=\frac{8}{7}+\frac{11}{5}\)
\(\frac{x}{2}=\frac{117}{35}\)
\(x=\frac{117}{35}\times2\)
\(x=\frac{234}{35}\)
b) \(\frac{y}{5}+\frac{9}{2}=\frac{6}{7}.\frac{36}{49}\)
\(\frac{y}{5}+\frac{9}{2}=\frac{216}{343}\)
\(\frac{y}{5}=\frac{216}{343}-\frac{9}{2}\)
\(\frac{y}{5}=\frac{-2655}{686}\)
\(y=\frac{-2655}{686}.5\)
\(y=\frac{-13275}{686}\)
ra kết quả to quá bn ạ! Bn xem lại giúp mk nha!
a) Tích của 2 thừa số bằng 0
=> x - 2 = 0 hoặc x + 1 = 0
=> x = 2 hoặc x = -1
a.\(9.\left(x+5\right)^2-\left(x-7\right)^2\)
\(=3^2.\left(x+5\right)^2-\left(x-7\right)^2\)
\(=\left(x+8\right)^2-\left(x-7\right)^2\)
\(=\left(x+8-x+7\right)\left(x+8+x-7\right)\)
\(=15\left(2x+1\right)\)
\(=30x+15\)
b.\(49\left(y-4\right)^2-9\left(y-2\right)^2\)
\(=7^2.\left(y-4\right)^2-3^2\left(y-2\right)^2\)
\(=\left(y+3\right)^2-\left(y+1\right)^2\)
\(=\left(y+3-y-1\right)\left(y+3+y+1\right)\)
\(=2\left(2y+4\right)\)
\(=4y+8\)
a./ \(=\left[3\left(x+5\right)\right]^2-\left(x-7\right)^2=\left(3x+15-x+7\right)\left(3x+15+x-7\right)=\left(2x+22\right)\left(4x+8\right).\)
\(=8\left(x+11\right)\left(x+2\right).\)
b./ \(=\left[7\left(y-4\right)\right]^2-\left[3\left(y-2\right)\right]^2=\left(7y-28+3y-6\right)\left(7y-28-3y+6\right)=\left(10y-34\right)\left(4y-22\right)\)
\(=4\left(5y-17\right)\left(2y-11\right)\)
\(\dfrac{a}{y}\times\dfrac{2}{7}=\dfrac{49}{2}\)
\(\dfrac{a}{y}=\dfrac{49}{2}\div\dfrac{2}{7}\)
\(\dfrac{a}{y}=\dfrac{49}{2}\times\dfrac{7}{2}\)
\(\dfrac{a}{y}=\dfrac{343}{4}\)
\(\dfrac{a}{y}\) chắc là bằng \(\dfrac{343}{4}\)