Chung minh cac phan so nay bang nhau:\(\frac{25}{53};\frac{2525}{5353};\frac{252525}{535353}\)
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a) \(3\left(x-4\right)-\left(8-x\right)=12\)
\(3x-12-8+x=12\)
\(4x=12+12+8\)
\(4x=32\)
\(x=8\)
b) \(4\left(x-5\right)-\left(x-7\right)=-19\)
\(4x-20-x+7=-19\)
\(3x=-19+20-7\)
\(3x=-6\)
\(x=-2\)
c) \(7\left(x-3\right)-5\left(3-x\right)=11x-5\)
\(7\left(x-3\right)+5\left(x-3\right)=11x-5\)
\(\left(x-3\right).12=11x-5\)
\(12x-36-11x+5=0\)
\(x-31=0\)
\(x=31\)
Lời giải:
\(\frac{x^2-4x+4}{4-x^2}=\frac{x^2-2.2.x+2^2}{2^2-x^2}=\frac{(x-2)^2}{(2-x)(2+x)}=\frac{(2-x)^2}{(2-x)(2+x)}=\frac{2-x}{2+x}\) (đpcm)
\(\frac{x^3-9x}{15-5x}=\frac{x(x^2-9)}{5(3-x)}=\frac{x(x-3)(x+3)}{5(3-x)}=\frac{-x(3-x)(x+3)}{5(3-x)}=\frac{-x(x+3)}{5}=\frac{-x^2-3x}{5}\) (đpcm)
A LÀ 1/7,2/7,3/7,4/7,5/7
B LÀ 10/5,9/5,8/5,7/5,6/5
C LÀ 2/5,16/20,24/30,32/40,40/50
D LÀ 1/6,2/5,3/4,2/5/1/6
Ta có : \(\frac{77}{99}=\frac{77:11}{99:11}=\frac{7}{9};\frac{777}{999}=\frac{777:111}{999:111}=\frac{7}{9}\)
Mà : \(\frac{7}{9}=\frac{7}{9}=\frac{7}{9}\)
Vậy : \(\frac{7}{9}=\frac{77}{99}=\frac{777}{999}\)
Ta tách : \(\frac{77}{99}=\frac{77:11}{99:11}=\frac{7}{9}\)
\(\frac{777}{999}=\frac{777:111}{999:111}=\frac{7}{9}\)
\(\Rightarrow\frac{77}{99}=\frac{777}{999}\)
\(\frac{25}{53}\)\(=\frac{25}{53}\)
\(\frac{2525}{5353}=\frac{25.101}{53.101}=\frac{25}{53}\)
\(\frac{252525}{535353}=\frac{25.10101}{53.10101}=\frac{25}{53}\)
\(=>\frac{25}{53}=\frac{2525}{5353}=\frac{252525}{535353}\)