x+3/2 (x-1/2)=5/6 giải hộ mình ạ
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`-2/5 : x=1/2`
`=> x= -2/5 : 1/2`
`=> x= -2/5 xx 2`
`=>x= -4/5`
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`7/6 : x = 7/4`
`=>x= 7/6 : 7/4`
`=>x=7/6 xx 4/7`
`=>x= 28/42`
`=>x=2/3`
ĐKXĐ: \(x\ne\left\{-3;-2;-1;0\right\}\)
\(\dfrac{1}{x\left(x+1\right)}+\dfrac{1}{\left(x+1\right)\left(x+2\right)}+\dfrac{1}{\left(x+2\right)\left(x+3\right)}=\dfrac{x}{x\left(x+3\right)}\)
\(\Leftrightarrow\dfrac{1}{x}-\dfrac{1}{x+1}+\dfrac{1}{x+1}-\dfrac{1}{x+2}+\dfrac{1}{x+2}-\dfrac{1}{x+3}=\dfrac{x}{x\left(x+3\right)}\)
\(\Leftrightarrow\dfrac{1}{x}-\dfrac{1}{x+3}=\dfrac{x}{x\left(x+3\right)}\)
\(\Leftrightarrow\dfrac{3}{x\left(x+3\right)}=\dfrac{x}{x\left(x+3\right)}\)
\(\Leftrightarrow x=3\)
\(3\left(x-1\right)^2-3x\left(x-5\right)=1\)
⇔ \(3\left(x^2-2x+1\right)-3x\left(x-5\right)=1\)
⇔ \(3x^2-6x+3-3x^2+15x=1\)
⇔ \(9x+3=1\)
⇔ \(9x=1-3\)
⇔ \(9x=-2\)
⇔ \(x=\dfrac{-2}{9}\)
\(a,10.a^6+20a^5=10a^5\left(a+2\right)\)
\(b,5x^2-10xy+5y^2=5\left(x^2-2xy+y^2\right)=5\left(x-y\right)^2\)
\(c,3ab^3+6ab^2-18ab=3ab\left(b^2+2b-1\right)\)
\(d,15x^3y^2+10x^2y^2-20x^2y^3=5x^2y^2\left(3x+2-4y\right)\)
\(e,a^2\left(x-1\right)-b\left(1-x\right)=a^2\left(x-1\right)+b\left(x-1\right)=\left(x-1\right)\left(a^2+b\right)\)
\(f,x\left(x-5\right)-4\left(5-x\right)=x\left(x-5\right)+4\left(x-5\right)=\left(x-5\right)\left(x+4\right)\)
(mk sửa lại thứ tự là a,b,c,d,e,f nha)
chúc bn học tốt
\(1,10a^6+20a^5=10a^5\left(a+10\right)\)
\(2,5x^2-10xy+5y^2=5\left(x^2-2xy+y^2\right)\)
\(=5\left(x-y\right)^2\)
\(3,3ab^3+6ab^2-18ab\)
\(=3ab\left(b^2+2b-6\right)\)
\(4,15x^3y^2+10x^2y^2-20x^2y^3\)
\(=5x^2y^2\left(3x+2-4y\right)\)
\(5,a^2\left(x-1\right)-b\left(1-x\right)\)
\(=a^2\left(x-1\right)+b\left(x-1\right)\)
\(=\left(x-1\right)\left(a^2+b\right)\)
\(6,x\left(x-5\right)-4\left(5-x\right)\)
\(=x\left(x-5\right)+4\left(x-5\right)\)
\(=\left(x+4\right)\left(x-5\right)\)
`(1 xx 2 xx 3 xx 4)/(3 xx 4 xx 5 xx 6)`
`= (1 xx 2)/(5 xx 6)`
`= 2/12`
`= 1/6`
=>x+3/2x-3/4=5/6
=>5/2x=19/12
=>x=19/30