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(8x3-1): (1-2x)
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Bài 2:
a: =x(x^2-25)
=x(x-5)(x+5)
b: =x(x-2y)+3(x-2y)
=(x-2y)(x+3)
c: =(2x-3)(4x^2+6x+9)+2x(2x-3)
=(2x-3)(4x^2+8x+9)
a ) \(\left(4x^2+4xy+y^2\right):\left(2x+y\right)\)
\(=\left(2x+y\right)^2:\left(2x+y\right)\)
\(=2x+y\)
b ) \(\left(27x^3+1\right):\left(3x+1\right)\)
\(=\left(3x+1\right)\left(9x^2-3x+1\right):\left(3x+1\right)\)
\(=9x^2-3x+1\)
c ) \(\left(x^2-6xy+9y^2\right):\left(3y-x\right)\)
\(=\left(x-3y\right)^2:\left(3y-x\right)\)
\(=\left(3y-x\right)^2:\left(3y-x\right)\)
\(=3y-x\)
d ) \(\left(8x^3-1\right):\left(4x^2+2x+1\right)\)
\(=\left(2x-1\right)\left(4x^2+2x+1\right):\left(4x^2+2x+1\right)\)
\(=2x-1\)
:D
`-1/3x^5y^2:(-2xy)-(x^2+2x+1):(x+1)`
`=-1/3:(-2).(x^5:x).(y^2:y)-(x+1)^2:(x+1)`
`=-1/6x^4y-(x+1)`
`=-1/6x^4y-x-1`
\(\dfrac{-1}{3}x^5y^2:\left(-2xy\right)-\left(x^2+2x+1\right):\left(x+1\right)\)
\(=\dfrac{1}{6}x^4y-x-1\)
\(a,\left(8x^3-1\right):\left(2x-1\right)\)
\(=\left[\left(2x-1\right)\left(4x^2+2x+1\right)\right]:\left(2x-1\right)\)
\(=4x^2+2x+1\)
+ Thương: \(4x^2+2x+1\)
+ Dư: \(0\)
(8x3 - 1):(1 -2x) = (2x-1)(4x2 + 2x + 1):(1-2x) = - (4x2 + 2x + 1)