5/12........7/18
= , > , <
K
Khách
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Những câu hỏi liên quan
2 tháng 3 2019
Điền dấu >,<,=:
A) \(\frac{7}{12}\) >\(\frac{7}{13}\)
B) \(\frac{10}{18}\) < \(\frac{11}{18}\)
C) \(\frac{5}{8}\) = \(\frac{10}{16}\)
G
20 tháng 2 2020
\(\frac{5}{6}\times\frac{7}{12}+\frac{5}{12}\times\frac{5}{6}+\frac{1}{6}\)
= \(\frac{35}{72}+\frac{25}{36}+\frac{1}{6}\)
= \(\frac{97}{72}\)
\(\left(\frac{8}{15}\times\frac{3}{4}\times\frac{5}{4}\right):\frac{7}{8}\)
= \(\frac{1}{2}:\frac{7}{8}\)
=\(\frac{4}{7}\)
HOK TỐT ^^
A
0
KH
28 tháng 2 2018
a) \(x=\dfrac{1}{4}+\dfrac{2}{13}\)
\(x=\dfrac{13}{52}+\dfrac{8}{52}\)
⇒ \(x=\dfrac{21}{52}\)
b) \(\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}\)
\(\dfrac{x}{3}=\dfrac{14}{21}+\dfrac{-3}{21}\)
\(\dfrac{x}{3}=\dfrac{11}{21}\)
⇒ \(x=\dfrac{11.3}{21}=\dfrac{33}{21}\)
⇒ \(x=\dfrac{11}{7}\)
c) \(\dfrac{-8}{3}+\dfrac{1}{3}< x< \dfrac{-2}{7}+\dfrac{-5}{7}\)
\(\dfrac{-17}{7}< x< -1\)
⇒ \(-17< x< -7\)
⇒ \(x\in\left\{-16;-15,....;-6\right\}\)
d) \(\dfrac{1}{6}+\dfrac{2}{5}\)
\(=\dfrac{5}{30}+\dfrac{12}{30}\)
\(=\dfrac{17}{30}\)
e) \(\dfrac{3}{5}+\dfrac{-7}{4}\)
\(=\dfrac{12}{20}+\dfrac{-35}{20}\)
\(=\dfrac{-23}{20}\)
f) \(\dfrac{4}{13}+\dfrac{-12}{30}\)
\(=\dfrac{4}{13}+\dfrac{-2}{5}\)
\(=\dfrac{20}{65}+\dfrac{-26}{65}\)
\(=\dfrac{-6}{65}\)
g) \(\dfrac{-3}{29}+\dfrac{16}{58}\)
\(=\dfrac{-6}{58}+\dfrac{16}{58}\)
\(=\dfrac{10}{58}\)
h) \(\dfrac{8}{40}+\dfrac{-36}{45}\)
\(=\dfrac{1}{5}+\dfrac{-4}{5}\)
\(=\dfrac{-3}{5}\)
j) \(\dfrac{-8}{18}+\dfrac{15}{27}\)
\(=\dfrac{-2}{9}+\dfrac{5}{9}\)
\(=\dfrac{3}{9}\)
\(=\dfrac{1}{3}\)
PH
0
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>
k nha
5/12 > 7/18