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3 tháng 8 2016

25% - 1 1/2 + 0,5 . 12/5

= 1/4 - 3/2 + 1/2 . 12 /5

= 1/4 - 3/2 + 6/5

= -5/4 + 6/5

= -1/20

3 tháng 8 2016

25% - 1 1/2 + 0.5 x 12/5

= 0.25 - 1.5 + 0.5 x 2.4

= 0.25 - 1.5 + 1.2

= 0.25 - 2.7

= -2.45

19 tháng 4 2019

\(25\%-2\frac{1}{3}+0,5.\frac{12}{5}\)

\(=\frac{1}{4}-\frac{7}{3}+\frac{1}{2}.\frac{12}{5}\)

\(=\frac{1}{4}-\frac{7}{3}+\frac{6}{5}\)

\(=\frac{1}{4}+\frac{-7}{3}+\frac{6}{5}\)

\(=\frac{15}{60}+\frac{-140}{60}+\frac{72}{60}\)

\(=\frac{-53}{60}\)

10 tháng 5 2016

\(a,\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)

\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}=\frac{-7}{25}-\frac{18}{25}=-1\)

\(b,\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{12}=\frac{5}{7}.\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)=\frac{5}{7}.\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)

\(=\frac{5}{7}.0=0\)

10 tháng 5 2016

c)\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}=\frac{27}{5}.\frac{30}{7}+\frac{40}{7}.\frac{27}{5}=\frac{27}{5}.\left(\frac{30}{7}+\frac{40}{7}\right)\)

\(=\frac{27}{5}.10=27.2=54\)

\(d,75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2=\frac{3}{4}-\frac{3}{2}+\frac{1}{2}.\frac{12}{5}-\frac{1}{4}\)

\(=\left(\frac{3}{4}-\frac{1}{4}\right)-\frac{3}{2}+\frac{6}{5}=\frac{1}{2}-\frac{3}{2}+\frac{6}{5}=-1+\frac{6}{5}=\frac{-5}{5}+\frac{6}{5}=\frac{1}{5}\)

\(\frac{5}{7}\times\frac{1}{3}-\frac{5}{7}\times\frac{1}{4}-\frac{5}{7}\times\frac{1}{2}\)

\(=\frac{5}{7}\times\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{2}\right)\)

\(=\frac{5}{7}\times\left(\frac{4}{12}-\frac{3}{12}-\frac{6}{12}\right)\)

\(=\frac{5}{7}\times\left(\frac{4-3-6}{12}\right)\)

\(=\frac{5}{7}\times\frac{-5}{12}\)

\(=\frac{5\times\left(-5\right)}{7\times12}\)

\(=\frac{-25}{84}\)

3 tháng 5 2019

\(\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{2}\)

\(\frac{5}{7}.\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{2}\right).1\)

\(=\frac{5}{7}.\frac{-5}{12}\)

\(=-\frac{25}{84}\)

a) \(\frac{2}{3}-\frac{5}{7}\cdot\frac{14}{25}\)

\(=\frac{2}{3}-\frac{2}{5}=\frac{4}{15}\)

b) \(\frac{-2}{5}\cdot\frac{5}{8}+\frac{5}{8}\cdot\frac{3}{5}\)

\(=\frac{5}{8}\left(-\frac{2}{5}+\frac{3}{5}\right)\)

\(=\frac{5}{8}\cdot\frac{1}{5}=\frac{1}{8}\)

c) \(25\%-1\frac{1}{2}+0,5\cdot\frac{12}{5}\)

\(=0,25-1,5+0,5\cdot2,4\)

\(=0,25-1,5+1,2=-0,05\)

22 tháng 7 2021

a) \(\frac{2}{3}-\frac{5}{7}\cdot\frac{14}{25}=\frac{2}{3}-\frac{2}{5}=\frac{10-6}{15}=\frac{4}{15}\)

b) \(-\frac{2}{5}\cdot\frac{5}{8}+\frac{5}{8}\cdot\frac{3}{5}=\frac{5}{8}\cdot\left(-\frac{2}{5}+\frac{3}{5}\right)=\frac{5}{8}\cdot\frac{1}{5}=\frac{1}{8}\)

c) \(25\%-1\frac{1}{2}+0,5\cdot\frac{12}{5}=\frac{1}{4}-\frac{3}{2}+\frac{1}{2}\cdot\frac{12}{5}=\frac{1}{4}-\frac{3}{2}+\frac{6}{5}=\frac{5-30+24}{20}=-\frac{1}{20}\)

~~ Chúc bạn học tốt ~~

11 tháng 12 2019

a) \(\frac{15}{12}+\frac{5}{13}-\frac{3}{12}-\frac{18}{13}=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)

                                                     \(=1+\left(-1\right)\)

                                                     \(=0\)

b) \(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}=\left(\frac{11}{24}+\frac{13}{24}\right)+\left(-\frac{5}{41}-\frac{36}{41}\right)+0,5\)

                                                                    \(=1+\left(-1\right)+0,5\)

                                                                    \(=0,5\)

_Học tốt nha_

11 tháng 12 2019

a, \(\frac{15}{12}\)\(\frac{5}{13}\)\(\frac{3}{12}\)-\(\frac{18}{13}\)

\(\frac{5}{4}\)\(\frac{5}{13}\) - \(\frac{1}{4}\) - \(\frac{18}{13}\)

\(\left(\frac{5}{4}-\frac{1}{4}\right)\)\(\left(\frac{5}{13}-\frac{18}{13}\right)\)

= 1 - 1 = 0

b, \(\frac{11}{24}\)\(\frac{5}{41}\)\(\frac{13}{24}\)+ 0,5 - \(\frac{36}{41}\)

\(\left(\frac{11}{24}+\frac{13}{24}\right)\)\(\left(\frac{5}{41}+\frac{36}{41}\right)\)+ 0,5

= 1 - 1 + 0,5 = 0,5

c,  \(\left(-\frac{3}{4}+\frac{2}{3}\right):\frac{5}{11}+\left(-\frac{1}{4}+\frac{1}{3}\right):\frac{5}{11}\)

=\(\left(-\frac{3}{4}+\frac{2}{3}\right).\frac{11}{5}+\left(-\frac{1}{4}+\frac{1}{3}\right).\frac{5}{11}\)

\(\frac{11}{5}.\left(-\frac{3}{4}+\frac{2}{3}-\frac{1}{4}+\frac{1}{3}\right)\)

\(\frac{11}{5}.\left[\left(-\frac{3}{4}-\frac{1}{4}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)\right]\)

=  \(\frac{11}{5}.\left[\left(-1\right)+1\right]\)

= 0

d, \(\left(-3\right)^2.\left(\frac{3}{4}-0,25\right)-\left(3\frac{1}{2}-1\frac{1}{2}\right)\)

\(9.\left(0,75-0,25\right)-2\)

= 9. 0,5 - 2 = 2,5

e, \(\frac{13}{25}+\frac{6}{41}-\frac{38}{25}+\frac{35}{41}-\frac{1}{2}\)

\(\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)

= -1 + 1 - \(\frac{1}{2}\)

\(-\frac{1}{2}\)

29 tháng 7 2018

sao bạn tự đăng tự giải thế? hay là bạn giải cho ai à?

29 tháng 7 2018

ukm bn

17 tháng 4 2019

i don't know i mới học lớp 5

bn eie mik lớp 6 nha bn