MN GIÚP MIK VS Ạ MIK CẦN GẤP
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NT
6 tháng 9 2021
c. \(\left|\dfrac{8}{4}-\left|x-\dfrac{1}{4}\right|\right|-\dfrac{1}{2}=\dfrac{3}{4}\)
\(\Rightarrow\left[{}\begin{matrix}\left|\dfrac{8}{4}-x+\dfrac{1}{4}\right|-\dfrac{1}{2}=\dfrac{3}{4}\\\left|\dfrac{8}{4}+x-\dfrac{1}{4}\right|-\dfrac{1}{2}=\dfrac{3}{4}\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}\left|\dfrac{9}{4}-x\right|-\dfrac{1}{2}=\dfrac{3}{4}\\\left|\dfrac{7}{4}+x\right|-\dfrac{1}{2}=\dfrac{3}{4}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}\dfrac{9}{4}-x-\dfrac{1}{2}=\dfrac{3}{4}\\x=\dfrac{9}{4}-\dfrac{1}{2}=\dfrac{3}{4}\end{matrix}\right.\\\left[{}\begin{matrix}\dfrac{7}{4}+x-\dfrac{1}{2}=\dfrac{3}{4}\\-\dfrac{7}{4}-x-\dfrac{1}{2}=\dfrac{3}{4}\end{matrix}\right.\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}x=1\\x=\dfrac{7}{2}\end{matrix}\right.\\\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=-3\end{matrix}\right.\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{7}{2}\\x=-3\end{matrix}\right.\)
Ở nơi x=9/4-1/2 là x-9/4-1/2 nha
KK
6 tháng 9 2021
a. -1,5 + 2x = 2,5
<=> 2x = 2,5 + 1,5
<=> 2x = 4
<=> x = 2
b. \(\dfrac{3}{2}\left(x+5\right)-\dfrac{1}{2}=\dfrac{4}{3}\)
<=> \(\dfrac{3}{2}x+\dfrac{15}{2}-\dfrac{1}{2}=\dfrac{4}{3}\)
<=> \(\dfrac{9x}{6}+\dfrac{45}{6}-\dfrac{3}{6}=\dfrac{8}{6}\)
<=> 9x + 45 - 3 = 8
<=> 9x = 8 + 3 - 45
<=> 9x = -34
<=> x = \(\dfrac{-34}{9}\)
DT
Đỗ Thanh Hải
CTVVIP
6 tháng 9 2021
C
1 cooking
2 listening
3 reading
4 playing
5 cycling
1 People collect a lot of things such as stamps, milk bottle labels, comic books as well as car toys
2 She is 20 years old
3 She is a hairdresser
4 It is collecting candy shells
5 Her friends and relatives
B
1 F
2 F
3 F
4 F
5 T
24 tháng 1
Câu 1:
a: 5x-2=3x+6
=>5x-3x=2+6
=>2x=8
=>\(x=\dfrac{8}{2}=4\)
b: a<=b
=>-2022a>=-2022b
=>-2022a+2021>=-2022b+2021
Câu 2:
1:
a: ĐKXĐ: x<>1
\(\dfrac{3}{x-1}+1=\dfrac{2x+5}{x-1}\)
=>\(\dfrac{3+x-1}{x-1}=\dfrac{2x+5}{x-1}\)
=>\(2x+5=x+2\)
=>x=-3(nhận)
b: |x-9|=2x-3
=>\(\left\{{}\begin{matrix}2x-3>=0\\\left(2x-3\right)^2=\left(x-9\right)^2\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x>=\dfrac{3}{2}\\\left(2x-3-x+9\right)\left(2x+3+x-9\right)=0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x>=\dfrac{3}{2}\\\left(x+6\right)\left(3x-6\right)=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x>=\dfrac{3}{2}\\\left[{}\begin{matrix}x=-6\left(loại\right)\\x=2\left(nhận\right)\end{matrix}\right.\end{matrix}\right.\)
=>x=2
2:
\(\dfrac{x-3}{2}-\dfrac{3x+2}{4}< \dfrac{1}{3}\)
=>\(\dfrac{6\left(x-3\right)-3\left(3x+2\right)}{12}< \dfrac{4}{12}\)
=>6x-18-9x-6<4
=>-3x-24<4
=>-3x<28
=>\(x>-\dfrac{28}{3}\)
Câu 3:
Gọi độ dài quãng đường AB là x(km)
(Điều kiện: x>0)
Thời gian đi từ A đến B là \(\dfrac{x}{40}\left(giờ\right)\)
Thời gian ô tô đi từ B về A là \(\dfrac{x}{30}\left(giờ\right)\)
Theo đề, ta có phương trình:
\(\dfrac{x}{40}+\dfrac{x}{30}+\dfrac{1}{2}=9+\dfrac{1}{4}\)
=>\(\dfrac{7x}{120}=8,75\)
=>\(x=8,75:\dfrac{7}{120}=120\cdot1,25=150\left(nhận\right)\)
vậy: Độ dài quãng đường AB là 150km
SV
Sinh Viên NEU
CTVVIP
7 tháng 1
ride : a horse, a motorbike, a tricycle, an elephent, a bicycle, a donkey,
drive: a car, a train, a taxi, a truck, a coach, a van, on the highway, home
go: home, abroad, swimming, shopping, sailing, overseas, fishing, jogging
sail: a boat, a yatch, a dighy
travel: abroad, overseas, the ocean, the sea
R
1
RY
24 tháng 4 2022
a. f(\(\dfrac{-1}{2}\)) = \(4.\left(\dfrac{-1}{2}\right)^2+3.\left(\dfrac{-1}{2}\right)-2\)
= \(4.\dfrac{1}{4}-\left(\dfrac{-3}{2}\right)-\dfrac{4}{2}\)
= \(\dfrac{2}{2}+\dfrac{3}{2}-\dfrac{4}{2}\)
= \(\dfrac{1}{2}\)
were going, saw
to tell
eat
don't study
going