A bằng 45. 94- 2. 69/ 210. 38+ 68. 20
giải cụ thể mk nha ai làm đc 1 like
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b: \(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)
\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+3^8\cdot2^{10}\cdot5}\)
\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{11}\cdot3^9}\)
\(=\dfrac{1}{2}\cdot\dfrac{-2}{3}=\dfrac{-1}{3}\)
a: \(A=2^{100}-2^{99}+2^{98}-2^{97}+...+2^2-2\)
=>\(2A=2^{101}-2^{100}+2^{99}-2^{98}+...+2^3-2^2\)
=>\(2A+A=2^{101}-2^{100}+2^{99}-2^{98}+...+2^3-2^2+2^{100}-2^{99}+...+2^2-2\)
=>\(3A=2^{101}-2\)
=>\(A=\dfrac{2^{101}-2}{3}\)
b: Sửa đề: \(A=\dfrac{2\cdot8^4\cdot27^2+4\cdot6^9}{2^7\cdot6^7+2^7\cdot40\cdot9^4}\)
\(A=\dfrac{2\cdot2^{12}\cdot3^6+2^2\cdot2^9\cdot3^9}{2^7\cdot2^7\cdot3^7+2^7\cdot2^3\cdot5\cdot3^8}\)
\(=\dfrac{2^{11}\cdot3^6\left(2^3+3^3\right)}{2^{10}\cdot3^7\left(2^4+5\cdot3\right)}\)
\(=\dfrac{2}{3}\cdot\dfrac{4+27}{16+15}=\dfrac{2}{3}\)
c: \(B=\dfrac{4^5\cdot9^4-2\cdot6^4}{2^{10}\cdot3^8+6^8\cdot20}\)
\(=\dfrac{2^{10}\cdot3^8-2\cdot2^4\cdot3^4}{2^{10}\cdot3^8+2^8\cdot2^2\cdot5\cdot3^8}\)
\(=\dfrac{2^5\cdot3^4\left(2^5\cdot3^4-1\right)}{2^{10}\cdot3^8\left(1+5\right)}=\dfrac{1}{2^5\cdot3^4}\cdot\dfrac{32\cdot81-1}{6}\)
\(=\dfrac{2591}{2^6\cdot3^5}\)
Biểu thức =\(\frac{15}{34}+\frac{4}{27}+\frac{19}{34}+\frac{23}{27}\) ( rút gọn đó )
=\(\left(\frac{15}{34}+\frac{19}{34}\right)+\left(\frac{4}{27}+\frac{23}{27}\right)\)
=\(\frac{15+19}{34}+\frac{4+23}{27}\)= \(\frac{34}{34}+\frac{27}{27}\)
= \(1+1=2\)
Oke nhá !!
d+ 0 =1. vậy d = 0+1 =1
c + 1 =0. vậy c= 0-1=-1
b + (-1) =1. vậy b=1-(-1) = 2
a + 2 =-1. vậy a= -1-2=-3
suy ra x(x-4)=x hoặc -x
th1:x(x-4)=x
x-4=x:x=1
suy ra x=1+4 =5
th2:x(x-4)=-x
x-4=-x:x=-1
suy ra x=-1+4=3
vậy x=5 hoặc 3
nhớ k mình nha
ta có x lớn hơn hoặc bằng 0
|x(x-4)|=x => |x| . |x-4| = x
vì x > hoặc = 0 => |x | = x => x|x-4|=x => x|x-4|-x=0 => x (|x-4| - 1 ) = 0 => x = 0 hoặc |x-4| - 1 =0
tự làm tiếp phần còn lại nhé nhok
|x(x - 4)| = x
\(\Rightarrow\orbr{\begin{cases}x\left(x-4\right)=x\\x\left(x-4\right)=-x\end{cases}}\Rightarrow\orbr{\begin{cases}x-4=1\\x-4=-1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=5\\x=3\end{cases}}\)
Lời giải:
\(P=\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\\ =\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\\ =\frac{2^{19}.3^9+2^{18}.3^9.5}{2^{19}.3^9+2^{20}.3^{10}}\\ =\frac{2^{18}.3^9(2+5)}{2^{19}3^9(1+2.3)}\\ =\frac{1}{2}\)
A=\(\frac{\left(2^2\right)^5\cdot\left(3^3\right)^4-2\cdot2^9\cdot3^9}{2^{10}\cdot3^8+2^8\cdot3^8\cdot2^2\cdot5}=\frac{2^{10}\cdot3^{12}-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}=\frac{2^{10}\cdot3^8\left(3^4-3\right)}{2^{10}\cdot3^8\left(1+5\right)}=\frac{78}{6}=13\)
cho mk hoi chan chay thuoc loai tu gi vay cac ban