\(-\frac{77}{21}.\frac{8}{9}-\frac{111}{93}\)
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a, \(\frac{-5}{21}+\frac{2}{9}=\frac{-15}{63}+\frac{14}{63}=\frac{-1}{63}\)
b, \(\frac{-4}{21}-\frac{5}{12}=\frac{-16}{84}-\frac{35}{84}=\frac{-51}{84}=\frac{-17}{28}\)
c, \(\frac{6}{-4}+\frac{1}{8}=\frac{-3}{2}+\frac{1}{8}=\frac{-12}{8}+\frac{1}{8}=\frac{-11}{8}\)
d, \(\frac{-56}{77}-\frac{30}{66}=\frac{-8}{11}-\frac{5}{11}=\frac{-13}{11}\)
e, \(\frac{-3}{9}+\frac{5}{-3}=\frac{-1}{3}+\frac{-5}{3}=\frac{-6}{3}=-2\)
\(\frac{-1}{2}+\frac{1}{3}+\frac{2}{4}=\frac{-6}{12}+\frac{4}{12}+\frac{6}{12}\)
= \(\frac{4}{12}\)
\(\frac{69}{77}\times\frac{21}{11}=\frac{69\times21}{77\times11}=\frac{1449}{847}=\frac{207}{121}\)
\(\frac{69}{77}:\frac{21}{11}=\frac{69}{77}\times\frac{11}{21}=\frac{69\times11}{77\times21}=\frac{759}{1617}=\frac{23}{49}\)
\(\frac{66}{77}-\frac{21}{11}=\frac{66}{77}-\frac{147}{77}=\frac{66-147}{77}=\frac{-81}{77}\)
\(\frac{69}{77}+\frac{21}{11}=\frac{69}{77}+\frac{147}{77}=\frac{69+147}{77}=\frac{216}{77}\)
~ Hok tốt ~
\(\frac{x+5}{95}+\frac{x+6}{94}+\frac{x+7}{93}+\frac{x+8}{92}+\frac{x+9}{91}=-5\)
\(\left(\frac{x+5}{95}+1\right)+\left(\frac{x+6}{94}+1\right)+\left(\frac{x+7}{93}+1\right)+\left(\frac{x+8}{92}+1\right)+\left(\frac{x+9}{91}+1\right)=-5+5=0\)
Gọi tổng dãy số hạng trên là A
A = 1 + \(\frac{1}{2}\)+ 1 + \(\frac{1}{6}\)+ 1 + \(\frac{1}{12}\)+ ... + 1 + \(\frac{1}{90}\)+ 1 + \(\frac{1}{110}\)
Mà từ \(\frac{1}{2}\)đén \(\frac{1}{110}\) có 10 số
A = 1 x 10 + \(\frac{1}{2}\)+( \(\frac{1}{2}\)- \(\frac{1}{3}\)) + ( \(\frac{1}{3}\)-\(\frac{1}{4}\)) + (\(\frac{1}{4}\)-\(\frac{1}{5}\)) + ... + \(\frac{1}{11}\)
A = 10 + \(\frac{1}{2}\)+ \(\frac{1}{2}\)+ \(\frac{1}{11}\)= \(\frac{112}{11}\)