giúp tớ với còn 20p nữa tớ nộp bà ruii
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a) \(\left(x-3\right)^{2022}=\left(x-3\right)^{2023}\)
\(\left(x-3\right)^{2022}\left(x-3-1\right)=0\)
\(\left(x-3\right)^{2022}\left(x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=4\end{matrix}\right.\)
b) \(\left(x+1\right)^{2024}+\left(x+1\right)^{2023}=2\)
\(\left[\left(x+1\right)^{2022}-1\right]\left[\left(x+1\right)^{2022}+2\right]=0\)
\(\Leftrightarrow x+1=1\)
\(\Leftrightarrow x=0\)
c) \(\left(x+3\right)^2+\left(x+3\right)=12\)
\(\left[\left(x+3\right)-3\right]\left[\left(x+3\right)+4\right]=0\)
\(x\left(x+7\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-7\end{matrix}\right.\)
1 had it fixed
2 have it replaced
3 had a new monitor deliver
4 had it tested
5 have the software installed
6 had all those problems solved
Bài 5
1 be - the past participle
2 the past participle
3 of
4 recycled
5 fall
6 environment
a: \(18\cdot7+65:13\)
=126+5
=131
b: \(785-\dfrac{323+148}{3}+2781\)
\(=785+2781-\dfrac{471}{3}\)
=3566-157
=3409
c: \(703-\dfrac{140}{42+28}-17^6\cdot17^9:17^{13}\)
\(=703-\dfrac{140}{70}-17^2\)
\(=703-289-2\)
=703-291
=412
e: \(\left(2^3\cdot9^4+9^3\cdot45\right):\left(9^2\cdot10-9^2\right)\)
\(=\dfrac{9^3\left(2^3\cdot9+45\right)}{9^2\cdot\left(10-1\right)}=\dfrac{9^3}{9^3}\cdot\left(8\cdot9+45\right)\)
=72+45
=117
kiểm tra hả?
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