Tìm X : X -( 31/5 + 31/15 + 31/35 + 31/63 + 31/99 +31/143) =9/13
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NV
2
VA
28 tháng 7 2016
Ta có :
Đặt \(A=\frac{31}{3}+\frac{31}{15}+...+\frac{31}{143}\)
\(A=\frac{31}{1.3}+\frac{31}{3.5}+...+\frac{31}{11.13}\)
\(\frac{2}{31}A=\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{11.13}\)
\(\frac{2}{31}A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{11}-\frac{1}{13}\)
\(\frac{2}{31}A=1-\frac{1}{13}\)
\(A=\frac{12}{13}:\frac{2}{31}\)
\(A=\frac{186}{13}\)
\(\Rightarrow x-\frac{186}{13}=\frac{9}{13}\)
\(x=\frac{9}{13}+\frac{186}{13}\)
\(x=\frac{195}{13}=15\)
Ủng hộ mk nha !!! ^_^
18 tháng 8 2021
\(\text{Đặt }A=\frac{31}{3}+\frac{31}{15}+...+\frac{31}{143}\)
\(\Rightarrow A=\frac{31}{1.3}+\frac{31}{3.5}+...+\frac{31}{11.13}\)
\(\Rightarrow\frac{2}{31}A=\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{11.13}\)
\(\Rightarrow\frac{2}{31}A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{11}-\frac{1}{13}\)
\(\Rightarrow\frac{2}{31}A=1-\frac{1}{13}\Rightarrow A=\frac{12}{13}:\frac{2}{31}=\frac{186}{13}\)
\(\Rightarrow x-\frac{186}{13}=\frac{9}{13}\)
\(\Rightarrow x=\frac{9}{13}+\frac{186}{13}\)
\(\Rightarrow x=\frac{195}{13}=15\)
DP
30 tháng 6 2017
\(X-\left(\frac{31}{5}+\frac{31}{15}+\frac{31}{35}+\frac{31}{63}+\frac{31}{99}+\frac{31}{143}\right)=\frac{9}{13}\)
\(X-\left(\frac{31}{5}+\frac{31}{3\cdot5}+\frac{31}{5\cdot7}+\frac{31}{7\cdot9}+\frac{31}{9\cdot11}+\frac{31}{11\cdot13}\right)=\frac{9}{13}\)
\(X-\left[\frac{31}{2}\cdot\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\right)+\frac{31}{5}\right]=\frac{9}{13}\)
\(X-\left[\frac{31}{2}\cdot\left(\frac{1}{3}-\frac{1}{13}\right)+\frac{31}{5}\right]=\frac{9}{13}\)
\(X-\left[\frac{31}{2}\cdot\frac{10}{39}+\frac{31}{5}\right]=\frac{9}{13}\)
\(X-\frac{1984}{195}=\frac{9}{13}\)
\(\Rightarrow X=\frac{9}{13}+\frac{1984}{195}=\frac{163}{15}\)
25 tháng 6 2018
\(\frac{31}{3}+\frac{31}{15}+\frac{31}{35}+\frac{31}{63}+\frac{31}{99}+\frac{31}{143}=\frac{31}{1.3}+\frac{31}{3.5}+\frac{31}{5.7}+\frac{31}{7.9}+\frac{31}{9.11}+\frac{31}{11.13}\\ \)
\(=\frac{31}{2}.\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\right)\)
\(=\frac{31}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\right)\)
\(=\frac{31}{2}.\left(1-\frac{1}{13}\right)=\frac{31}{2}.\frac{12}{13}=\frac{31.6}{13}=\frac{186}{13}\)
\(\Rightarrow x-\frac{186}{13}=\frac{9}{13}\Leftrightarrow x=\frac{195}{13}=15\)
NV
25 tháng 6 2018
\(x-\left(\frac{31}{3}+\frac{31}{15}+\frac{31}{35}+\frac{31}{63}+\frac{31}{99}+\frac{31}{143}\right)=\)\(\frac{9}{13}\)(1)
Đặt \(A=\frac{31}{3}+\frac{31}{15}+\frac{31}{35}+\frac{31}{63}+\frac{31}{99}+\frac{31}{143}\)
\(A=31\left(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}\right)\)
\(\Rightarrow2A=31\left(\frac{2}{3}+\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}+\frac{2}{143}\right)\)
\(2A=31\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\right)\)
\(2A=31\left(2-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\right)\)
\(2A=31\left(2-\frac{1}{13}\right)\)
\(2A=31.\frac{25}{13}\)
\(2A=\frac{775}{13}\)
\(\Rightarrow A=\frac{775}{13}:2\)
\(A=\frac{775}{26}\)
Thay vào (1) ta có:
\(x-\frac{775}{26}=\frac{9}{13}\)
\(\Leftrightarrow x=\frac{9}{13}+\frac{775}{26}\)
\(\Leftrightarrow x=\frac{61}{2}\)
T
2 tháng 7 2019
#)Giải :
\(200-18:\left(372:3x-1\right)-28=166\)
\(\Leftrightarrow200-18:\left(372:3x-1\right)=194\)
\(\Leftrightarrow18:\left(372:3x-1\right)=6\)
\(\Leftrightarrow372:3x-1=3\)
\(\Leftrightarrow3x-1=124\)
\(\Leftrightarrow3x=125\)
\(\Leftrightarrow x=\frac{125}{3}\)
XO
2 tháng 7 2019
200 - 18 : (372 : 3 . x - 1) - 28 = 166
=> 200 - 18 : (372 : 3.x - 1) = 166 + 28
=> 200 - 18 : (372 : 3.x) - 1) = 194
=> 18 : (372 : 3.x - 1) = 200 - 194
=> 18 : (372 : 3.x - 1) = 6
=> 372 : 3.x - 1 = 18 : 6
=> 372 : 3.x - 1 = 3
=> 372 : 3.x = 3 + 1
=> 372 : 3.x = 4
=> 3.x = 372 : 4
=> 3.x = 93
=> x = 93 : 3
=> x = 31
14 tháng 4 2022
b: =15/31(34/63-11/21)=15/31x1/63=5/651
a: \(=\dfrac{67}{63}\cdot5+\dfrac{11}{31}\cdot\dfrac{5}{7}=5\left(\dfrac{67}{63}+\dfrac{11}{31\cdot7}\right)=\dfrac{10880}{1953}\)
14 tháng 4 2022
a)67/63 x 15/3 + 15/31 x 11/21
Thiếu đề
b)15/31 x 34/63 - 11/21 x 15/31
=15/31 x ( 34/63 -11/21)
= 15/31 x 1/63= 5/651
14 tháng 4 2022
b: =15/31(34/63-11/21)=15/31x1/63=5/651
a: \(=\dfrac{67}{63}\cdot5+\dfrac{11}{31}\cdot\dfrac{5}{7}=5\left(\dfrac{67}{63}+\dfrac{11}{31\cdot7}\right)=\dfrac{10880}{1953}\)
14 tháng 4 2022
b: =15/31(34/63-11/21)=15/31x1/63=5/651
a: =67/63⋅5+11/31⋅5/7=5(67/63+11/31⋅7)=10880/1953
22 tháng 7 2021
31 - [ 26 - ( 209 + 35 ) ]
= 31 - ( 26 - 344 )
=31 - ( -318)
= 31 + 318 ( trừ trừ thành cộng nha )
= 349
22 tháng 7 2021
31-(26-(209+35)=31-
hok tốt
k cho mik
kb nữa nhé
SM
9 tháng 9 2018
S = 5 + 52 + 53 + 54 + .......... + 599
a) S = ( 5 + 52 + 53 ) + ( 54 + 55 + 56 ) + .... + ( 597 + 598 + 599 )
= 5. ( 1 + 5 + 52 ) + 54 . ( 1 + 5 + 52 ) + .... + 597 . ( 1 + 5 + 52 )
= ( 1 + 5 + 52 ). ( 5 + 54 + .. + 597 )
= 31 . ( 5 + 54 + .... + 597 ) chia hết cho 31 ( đpcm )
c ) 5S = 52 + 53 + .. + 5100
=> 5S - S = 4S = 5100 + 599 + ........ + 53 + 52 - 5 - 52 - 53 - ..... - 599
= 5100 - 5
25x - 5 = 4S
=> 25x - 5 = 5100 - 5
=> 25x = 5100
=> 25x = ( 52 )50
=> 25x = 2550
=> x = 50
Vậy x = 50
Câu b quên cách làm rồi
9 tháng 9 2018
a) S=5+52+53+54+...+599
=(5+52+53)+(54+55+56)+...+(597+598+599)
=5(1+5+52)+54(1+5+52)+...+597(1+5+52)
=5.31+54.31+...+597.31
=31(5+54+...+597)⋮31(đpcm)
b) S=5+52+53+54+...+599
=5+(52+53)+(54+55)+...+(598+599)
=5+5(5+52)+53(5+52)+...+597(5+52)
=5+5.30+53.30+...+597.30
=5+30.(5+53+...+597)
Mà 5⋮̸30 nên S⋮̸30(đpcm)
c) Ta có: 5S=52+53+54+55+...+5100
5S−S=(52+53+54+55+...+5100)−(5+52+53+54+...+599)
4S=5100−5
⇒25x−5=5100−5
⇒25x=5100
⇒25x=2550
⇒x=50
\(X=\frac{908}{75}\)kq đó
Ta có: x-(\(\frac{31}{5}+\frac{31}{3.5}+\frac{31}{5.7}+\frac{31}{7.9}+\frac{31}{9.11}\)\(+\frac{31}{11.13}\))=\(\frac{9}{13}\)
x-\(\frac{31}{5}\)-\(\frac{31}{2}\)x(\(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\))=\(\frac{9}{13}\)
x-\(\frac{31}{5}-\frac{31}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+.....+\frac{1}{11}-\frac{1}{13}\right)\)=\(\frac{9}{13}\)
x-\(\frac{31}{5}\)\(-\frac{31}{2}\left(\frac{1}{3}-\frac{1}{13}\right)=\frac{9}{13}\)
x-\(\frac{31}{5}-\frac{31}{2}.\frac{10}{39}\)\(=\frac{9}{13}\)
x-\(\frac{31}{5}-\frac{155}{39}=\frac{9}{13}\)
x-\(\frac{434}{195}\)=\(\frac{9}{13}\)
x =\(\frac{9}{13}+\frac{434}{195}=\frac{569}{195}\)
nhé