3/5+5/2:5/6-1/2:5/6=
(nêu cách làm)
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= 2/3 + 1/3 . 7/18 : 5/12
= 2/3 + 7/54 : 5/12
= 2/3 + 14/45
= 44/45
1) 1/3 x 1/2 x 3/7 = 3/42 = 1/14
2) 5/4 x 1/3 +1/7 = 5/12 + 1/7 = 35/84 + 12/84 = 47/84
3) 8 x ( 8/9 - 2/3 ) = 8 x 2/9 = 16/9
4) 5/6 x 48/20 x 1/2 = 240/240 = 1
5) ( 2/5 + 3/4 ) + 8 = 23/20 + 8 = 23//20 + 160/20 = 183/20
6) 10 x ( 1/2 - 1/5 ) = 10 x 3/10 = 10/1 x 3/10 = 30/10 = 3
Ta có: \(\frac{5}{6}< 1;\frac{6}{5}>1\)
\(\Rightarrow\frac{6}{5}>\frac{5}{6}\)
Ta có: \(\frac{5}{6}< 1;\frac{6}{5}>1\)
Vậy \(\frac{5}{6}< \frac{6}{5}\)
\(A=\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)
\(=6-\frac{2}{3}+\frac{1}{2}-5-\frac{5}{3}+\frac{3}{2}-3+\frac{7}{3}-\frac{5}{2}\)
\(=6-5-3+\left(\frac{-2}{3}+\frac{-5}{3}+\frac{7}{3}\right)+\left(\frac{1}{2}+\frac{3}{2}-\frac{5}{2}\right)\)
\(=-2+0+\frac{-1}{2}=\frac{-5}{2}\)
`=(3)/(5)+((5)/(2)-(1)/(2)):(5)/(6)`
`=(3)/(5)+2:(5)/(6)`
`=(3)/(5)+(12)/(5)=(15)/(5)=3`
\(=\dfrac{3}{5}+\dfrac{5}{2}.\dfrac{6}{5}-\dfrac{1}{2}.\dfrac{6}{5}=\dfrac{3}{5}+\dfrac{6}{5}.\left(\dfrac{5}{2}-\dfrac{1}{2}\right)=\dfrac{3}{5}-\dfrac{6}{5}.2=0\)