5x-1=52
3x=910
2x=83
22x-3=29
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a) Đặt: \(A=1+2^2+2^3+...+2^{10}\)
\(\Rightarrow2A=2\left(1+2^2+2^3+...+2^9+2^{10}\right)\)
\(\Rightarrow2A=2+2^3+2^4+...+2^{10}+2^{11}\)
\(\Rightarrow2A-A=\left(2+2^3+2^4+...+2^{10}+2^{11}\right)-\left(1+2^2+2^3+...+2^{10}\right)\)
\(\Rightarrow A=\left(2^3-2^3\right)+\left(2^4-2^4\right)+...+\left(2-1\right)+\left(2^{11}-2^2\right)\)
\(\Rightarrow A=0+0+...+1+\left(2^{11}-2^2\right)\)
\(\Rightarrow A=1+2^{11}-2^2=1+2048-4=2045\)
Vậy: \(1+2^2+2^3+...+2^{10}=2045\)
b)
a] \(60-3\left(x-1\right)=2^3\cdot3\)
\(\Rightarrow60-3\left(x-1\right)=24\)
\(\Rightarrow3\left(x-1\right)=36\)
\(\Rightarrow x-1=12\)
\(\Rightarrow x=13\)
b] \(\left(3x-2\right)^3=2\cdot2^5\)
\(\Rightarrow\left(3x-2\right)^3=2^6\)
\(\Rightarrow\left(3x-2\right)^3=\left(2^2\right)^3\)
\(\Rightarrow3x-2=2^2\)
\(\Rightarrow3x=6\)
\(x=2\)
c] \(5^{x+1}-5^x=500\)
\(\Rightarrow5^x\left(5-1\right)=500\)
\(\Rightarrow5^x\cdot4=500\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
d] \(x^2=x^4\)
\(\Rightarrow x=x^2\)
\(\Rightarrow x-x^2=0\)
\(\Rightarrow x\left(1-x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\1-x=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
\(\left(5x-29\right)-\left(2x-29\right)=-21\)
\(5x-29-2x+29=-21\)
\(5x-2x=-21+29-29\)
\(3x=-21\)
\(x=-7\)
Bài 1:
29.(85-47)+85.(47-29)
=29.38+85.18
=1102+1530
=2632
BÀI 2
a, 15x = -75
x =( -75) : 15
x = -5
Vậy x= -5
b,-5x+8=-27
-5x = -27 - 8
-5x= -35
x =-35 : -5
x = 7
Vậy x = 7
c,3.(17 + x ) = - 42
17 + x = - 42 : 3
17 + x = -14
x = - 14 - 17
x = -31
Vậy x = - 31
d,-10 -( 2x -16) = 0
2x - 16 = 10-0
2x - 16 = 10
2x = 10 +16
2x = 26
x = 26 : 2
x = 13
Vậy x = 13
e,( mik ko bít làm)
f,( tự làm nghen bạn)
a, = x2 - 6x + 9 - 1 = (x - 3)2 - 12 = (x - 4)(x - 2)
b, = 4x2 - 4x - 3x + 3 = 4x(x - 1) - 3(x - 1) = (x - 1)(4x - 3)
c, = (x + 2)(5x - 4)
d, = 5x2 - 5x + 2x - 2 = 5x(x - 1) + 2(x - 1) = (x - 1)(5x + 2)
a) \(x^2-6x+8\)
\(=x^2-4x-2x+8\)
\(=x\left(x-4\right)-2\left(x-4\right)\)
\(=\left(x-4\right)\left(x-2\right)\)
b) \(4x^2-7x+3\)
\(=4x^2-4x-3x+3\)
\(=4x\left(x-1\right)-3\left(x-1\right)\)
\(=\left(x-1\right)\left(4x-3\right)\)
c) \(\left(3x-1\right)^2-\left(2x-3\right)^2\)
\(=9x^2-6x+1-\left(4x^2-12x+9\right)\)
\(=9x^2-6x+1-4x^2+12x-9\)
\(=5x^2+6x-8\)
\(=5x^2+10x-4x-8\)
\(=5x\left(x+2\right)-4\left(x+2\right)\)
\(=\left(x+2\right)\left(5x-4\right)\)
d) \(5x^2-3x-2\)
\(=5x^2-5x+2x-2\)
\(=5x\left(x-1\right)+2\left(x-1\right)\)
\(=\left(x-1\right)\left(5x+2\right)\)
5x-1 = 5^2
5^x : 5 = 5^2
5^x = 5^2 * 5
5^x = 5^3
x=3
----------------------------
3^x = 9^10
3^x = (3^2)^10
3^x = 3^20
x=20
--------------------------------
2^x = 8^3
2^x = (2^3)^3
2^x = 2^9
x=9
-------------------------------
22x-3 = 2^9
22x : 2^3 = 2^9
22x = 2^9 * 2^3
22x = 2^12
2x = 12
x=6
a/ 5x-1 = 52 => x - 1 = 2 => x = 3
b/ 3x = 910 => 3x = (32)10 => 3x = 320 => x = 20
c/ 2x = 83 => 2x = (23)3 => 2x = 29 => x = 9
d/ 22x-3 = 29 => 2x - 3 = 9 => 2x = 12 => x = 6