Tìm x:
3/5 x x +9
___________ +9 =16:8/9
21
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\(16:\left(\frac{3}{5}x+\frac{8}{21}+9\right)=\frac{7}{10}\)
\(\frac{3}{5}x+\frac{8}{21}+9=\frac{160}{7}\)
\(\frac{3}{5}x=\frac{283}{21}\)
\(x=\frac{1415}{63}\)
Vậy ...
a) \(\dfrac{7}{9}\times\dfrac{13}{25}\times\dfrac{9}{7}=\left(\dfrac{7}{9}\times\dfrac{9}{7}\right)\times\dfrac{13}{25}=1\times\dfrac{13}{25}=\dfrac{13}{25}\)
b) \(\dfrac{5}{9}\times\dfrac{21}{25}+\dfrac{21}{25}\times\dfrac{4}{9}\)
\(=\dfrac{21}{25}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)\)
\(=\dfrac{21}{25}\times1=\dfrac{21}{25}\)
c) \(\dfrac{19}{5}\times\dfrac{11}{16}-\dfrac{9}{5}\times\dfrac{11}{16}\)
\(=\dfrac{11}{16}\times\left(\dfrac{19}{5}-\dfrac{9}{5}\right)\)
\(=\dfrac{11}{16}\times2=\dfrac{22}{16}=\dfrac{11}{8}\)
1.\(\dfrac{8}{11}+\dfrac{8}{33}\times\dfrac{3}{4}=\dfrac{8}{11}+\dfrac{8\times3}{33\times4}=\dfrac{8\times12}{11\times12}+\dfrac{8\times3}{33\times4}=\dfrac{8\times15}{132}=\dfrac{120}{132}=\dfrac{10}{11}\)
2.\(\dfrac{7}{9}\times\dfrac{3}{14}:\dfrac{5}{8}=\dfrac{7}{9}\times\dfrac{3}{14}\times\dfrac{8}{5}=\dfrac{4}{15}\)
3.\(\dfrac{5}{12}-\dfrac{7}{32}:\dfrac{21}{16}=\dfrac{5}{12}-\dfrac{7}{32}\times\dfrac{16}{21}=\dfrac{5}{12}-\dfrac{1}{6}=\dfrac{5-2}{12}=\dfrac{3}{12}=\dfrac{1}{4}\)
`@V.Tr.V`
3/5*x+8/21+9=16:7/10
3/5*x+8/21=160/7-9
3/5*x=97/7-8/21
x=283/21:3/5
x=1415/63
\(16\div\left(\frac{3}{5}\times x+8+\frac{9}{21}\right)=\frac{7}{10}\)
\(\Rightarrow\frac{3}{5}x+\frac{59}{7}=\frac{160}{7}\)
\(\Rightarrow\frac{3}{5}x=\frac{101}{7}\)
\(\Rightarrow x=\frac{35}{303}\)
~Study well~
#KSJ
\(16:\left(\frac{3}{5}.x+8+\frac{9}{21}\right)=\frac{7}{10}\)
\(\frac{3}{5}x+\frac{59}{7}=\frac{160}{7}\)
\(\frac{3}{5}x=\frac{101}{7}\)
\(x=\frac{35}{303}\)