Tìm x:
\(\frac{3\times x+25}{x}-30=170\)
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(3 x X + 25) : X - 30 = 170
(3 x X + 25) : X = 170+30
(3 x X + 25) : X = 200
3xX:X+25:X=200
3x1+25:X=200
3+25:X=200
25:X=200-3
25:X=197
X=25:197
(3x+25):x-30=170
(3x+25):x=170+30
(3x+25):x=200
3x:x+25:x=200
3+25:x=200
25:x=200-3
25:X=197
x=25:197
x=\(\frac{25}{197}\)
\(\frac{1.2.3....31}{2^{30}.\left(2.3....31\right).32}=\frac{1}{2^{31}.32}=\frac{1}{2^{36}}=2^{-36}=2^x\)
Vậy x=-36
Hok tốt
Bài 2:
\(a,45+170+25+30\)
\(=\left(45+25\right)+\left(170+30\right)\)
\(=60+200=260\)
Bài 3:
\(a,\left(x-6\right).5=150\)
\(x-6=150:5\)
\(x-6=30\)
\(x=30+6\)
\(x=36\)
\(b,2^5.\left(3x-2\right)=2^3.2^6\)
\(2^5.\left(3x-2\right)=2^{3+6}\)
\(2^5.\left(3x-2\right)=2^9\)
\(3x-2=2^9:2^5\)
\(3x-2=2^4=16\)
\(3x=16+2\)
\(3x=22\)
\(x=22:3\)
\(x\approx7,3\)
\(c,100-7.\left(x-5\right)=51\)
\(7.\left(x-5\right)=100-51\)
\(7.\left(x-5\right)=49\)
\(x-5=49:7\)
\(x-5=7\)
\(x=7+5\)
\(x=12\)
Phần d) bạn thiếu dữ liệu ạ.
Bài 3:
a: \(x\in\left\{-5;-4;-3;-2;-1\right\}\)
b: \(x\in\left\{-3;-2;-1;0;1;2;3;4;5;6\right\}\)
\(25\%+\frac{3}{4}.x=4\frac{2}{5}:2,2\Leftrightarrow\frac{1}{4}+\frac{3}{4}.x=\frac{22}{5}:\frac{11}{5}\)
\(\Leftrightarrow\frac{1}{4}+\frac{3}{4}.x=2\Leftrightarrow\frac{3}{4}.x=2-\frac{1}{4}\)
\(\Leftrightarrow\frac{3}{4}.x=\frac{7}{4}\Leftrightarrow x=\frac{7}{4}:\frac{3}{4}\Leftrightarrow\frac{7}{3}\)
1/2 * x - 3/5 = -4 /5
1/2 * x = - 4 /5 + 3/5
1/2* x = -1/5
x = -1/5 : 1/2
x = -1/5 *2
x = -2 /5
Vay x = -2/5
b ) ( x - 2/3 ) : -3 /7 = - 9/14
x - 2/3 = - 9/14 * -3/7
x - 2/3 = 27/98
x = 27/98+ 2/3
x = 81/294 + 196/ 294
x = 277/294
Vay x= 277/294
Ban oi , k cho mk nha .
\(x^2-25\%x=0\)
\(x.x-\frac{1}{4}x=0\)
\(x.\left(x-\frac{1}{4}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x-\frac{1}{4}=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=0+\frac{1}{4}\end{cases}\Rightarrow}\orbr{\begin{cases}x=0\\x=\frac{1}{4}\end{cases}}}\)
~ Hok tốt ~