Phân tích đa thức thành nhân tử:
\(4x^2-y^2+4x+1\)
\(x^3-x+y^3-y\)
K
Khách
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6 tháng 11 2021
\(1,=x\left(x^2-2x+1-y^2\right)=x\left[\left(x-1\right)^2-y^2\right]=x\left(x-y-1\right)\left(x+y-1\right)\\ 2,=\left(x+y\right)^3\\ 3,=\left(2y-z\right)\left(4x+7y\right)\\ 4,=\left(x+2\right)^2\\ 5,Sửa:x\left(x-2\right)-x+2=0\\ \Leftrightarrow\left(x-2\right)\left(x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)
24 tháng 9 2021
\(1,\\ 1,=15\left(x+y\right)\\ 2,=4\left(2x-3y\right)\\ 3,=x\left(y-1\right)\\ 4,=2x\left(2x-3\right)\\ 2,\\ 1,=\left(x+y\right)\left(2-5a\right)\\ 2,=\left(x-5\right)\left(a^2-3\right)\\ 3,=\left(a-b\right)\left(4x+6xy\right)=2x\left(2+3y\right)\left(a-b\right)\\ 4,=\left(x-1\right)\left(3x+5\right)\\ 3,\\ A=13\left(87+12+1\right)=13\cdot100=1300\\ B=\left(x-3\right)\left(2x+y\right)=\left(13-3\right)\left(26+4\right)=10\cdot30=300\\ 4,\\ 1,\Rightarrow\left(x-5\right)\left(x-2\right)=0\Rightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\\ 2,\Rightarrow\left(x-7\right)\left(x+2\right)=0\Rightarrow\left[{}\begin{matrix}x=7\\x=-2\end{matrix}\right.\\ 3,\Rightarrow\left(3x-1\right)\left(x-4\right)=0\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=4\end{matrix}\right.\\ 4,\Rightarrow\left(2x+3\right)\left(2x-1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{3}{2}\\x=\dfrac{1}{2}\end{matrix}\right.\)
HH
1
LD
4 tháng 11 2021
a) \(x-xy+y-y^2=x\left(1-y\right)+y\left(1-y\right)=\left(x+y\right)\left(1-y\right)\)
b) \(x^2-2x-y^2+1=\left(x^2-2x+1\right)-y^2=\left(x-1\right)^2-y^2=\left(x-y-1\right)\left(x+y-1\right)\)
c) \(4x^2-4xy+y^2=\left(2x\right)^2-2.2x.y+y^2=\left(2x-y\right)^2\)
d) \(9x^3-9x^2y-4x+4y=9x^2\left(x-y\right)-4\left(x-y\right)=\left(9x^2-4\right)\left(x-y\right)=\left(3x-2\right)\left(3x+2\right)\left(x-y\right)\)
e) \(x^3+2+3\left(x^3-2\right)=x^3+2+3x^3-6=4x^3-4=4\left(x^3-1\right)=4\left(x-1\right)\left(x^2+x+1\right)\)
13 tháng 7 2021
\(1,x^2-xy-2x+2y\)
\(x\left(x-2\right)-y\left(x-2\right)\)
\(\left(x-2\right)\left(x-y\right)\)
\(2,x^2+4x+4-y^2\)
\(\left(x+2\right)^2-y^2\)
\(\left(x+2-y\right)\left(x+2+y\right)\)
\(3,x^2+x+y-y^2\)
\(\left(x-y\right)\left(x+y\right)+\left(x+y\right)\)
\(\left(x+y\right)\left(x-y+1\right)\)
\(4,x^3-x^2-4x+4\)
\(x^2\left(x-1\right)-4\left(x-1\right)\)
\(\left(x-1\right)\left(x^2-4\right)\)
\(\left(x-1\right)\left(x-2\right)\left(x+2\right)\)
SK
0
26 tháng 9 2018
\(4x\left(x-y\right)+3\left(y-x\right)^2\)
\(=4x\left(x-y\right)+3\left(x-y\right)\left(x-y\right)\)
\(=\left(x-y\right)\left[4x+3\left(x-y\right)\right]\)
\(=\left(x-y\right)\left(4x+3x-3y\right)\)
26 tháng 9 2018
\(4x\left(x-y\right)+3\left(y-x\right)^2\)
\(=\)\(4x\left(x-y\right)+3\left(x-y\right)^2\)
\(=\)\(4x\left(x-y\right)+\left(3x-3y\right)\left(x-y\right)\)
\(=\)\(\left(x-y\right)\left(4x+3x-3y\right)\)
\(=\)\(\left(x-y\right)\left(7x-3y\right)\)
Chúc bạn học tốt ~
a) \(\Leftrightarrow\left(2x\right)^2+2.2x.1+1-y^2\Leftrightarrow\left(2x+1\right)^2-y^2\Leftrightarrow\left(2x-1-y\right)\left(2x-1+y\right)\)
b)\(\Leftrightarrow\left(x+y\right)\left(x^2-xy+y^2\right)-\left(x+y\right)\Leftrightarrow\left(x+y\right)\left(x^2-xy+y^2-1\right)\)
T I C K cho mình nha cảm ơn
4x2 - y2 +4x + 1 = 4x2 +4x +1 - y2 = ( 2x )2 +2.2x1 +12 - y2= (2x+1)2 -y2