Tính hợp lý:(1+2+3+4+5+.......+2046)x(13x15-15x12-15)
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3/ 4x7 + 1 / 7 x 8 + 5 / 8 x13 + 2 / 13 x 15 + 9 / 15 x 24
= 1/ 4-1/7+ 1 / 7 - 1/8 + 1/ 8 - 1/ 13 + 1/ 13 - 1/ 15 + 1/ 15 - 1/24
= 1/ 4 - 1/24
=5/ 24
\(\frac{3}{4\times7}+\frac{1}{7\times8}+\frac{5}{8\times13}+\frac{2}{13\times15}+\frac{9}{15\times24}\)
= \(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{24}\)
= \(\frac{1}{4}-\frac{1}{24}\)
= \(\frac{6}{24}-\frac{1}{24}\)
= \(\frac{5}{24}\)
\(\frac{3}{4.7}+\frac{1}{1.8}+\frac{5}{8.13}+\frac{2}{13.15}+\frac{9}{15.24}\)
Đặt A = ( 3 + 1 + 5 + 2 + 9 ) . \(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{24}\)
A = 20 . \(\frac{1}{4}-\frac{1}{24}\)
A = 20 . \(\frac{6}{24}-\frac{1}{24}\)
A = 20 . \(\frac{5}{24}\)
A = \(\frac{100}{24}\)
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# DanLinh
( 1+2+3+.... +99) x (13x15 -12 x 15- 15)
= ( 1+2+3+.... +99) x 0
=0
\(240:\left(5^3-5^3:5^2\right)-3^6:3^4+15\cdot11\cdot\left(13-9\right)\)
\(=240:\left(5^3-5\right)-3^{6-4}+15\cdot11\cdot4\)
\(=240\cdot\left(125-5\right)-3^2+60\cdot11\)
\(=240:120-9+60\cdot\left(10+1\right)\)
\(=2-9+600+60\)
\(=653\)
1.a) 4.(12+88) = 4.100=400
b)72- 6 .[2.8:8 ]=72-6.[16:8]=72-6 .2= 49-12=37 ( tui ko chắc lắm )
2.a) x=26-11=15
b) (4x-15)3=53
4x-15=5
4x= 5+15
4x=20
vậy x = 20
Bài 2:
a: Ta có: x+11=26
nên x=15
b: Ta có: \(\left(4x-15\right)^3=125\)
\(\Leftrightarrow4x-15=5\)
hay x=5
Bài 1:
\(\Leftrightarrow2^n\cdot\dfrac{9}{2}=9\cdot5^n\)
\(\Leftrightarrow2^n=2\cdot5^n\)
\(\Leftrightarrow2^{n-1}=5^n\)
Bài 2:
a: \(A=\dfrac{2^8+3^8}{2^8}=1+\dfrac{3^8}{2^8}\)
b: \(B=\left(2^{17}+17^2\right)\cdot\left(9^{15}-15^9\right)\cdot\left(16-16\right)=0\)
\(\dfrac{-2}{9}-\dfrac{3}{4}+\dfrac{3}{5}+\dfrac{1}{15}+\dfrac{1}{57}+\dfrac{1}{3}-\dfrac{1}{36}\)
\(=\left(-\dfrac{2}{9}-\dfrac{3}{4}-\dfrac{1}{36}\right)+\left(\dfrac{3}{5}+\dfrac{1}{15}+\dfrac{1}{3}\right)+\dfrac{1}{57}\)
\(=\dfrac{-8-27-1}{36}+\dfrac{9+1+5}{15}+\dfrac{1}{57}\)
\(=-\dfrac{36}{36}+\dfrac{15}{15}+\dfrac{1}{57}\)
\(=\dfrac{1}{57}\)
15 × (4 - 7) - 15 × (5 - 3)
= 15 × (-3) - 15 × 2
= 15 × (-3 - 2)
= -15 × 5
= -75
--------
73 × (8 - 59) - 59 × (8 - 73)
= 73 × 8 - 73 × 59 - 59 × 8 + 59 × 73
= 8 × (73 - 59) + 73 × (59 - 59)
= 8 × 14 + 73 × 0
= 8 × 14
= 112
15 x (4-7) - 15 x (5-3)
= 15 x (-3) - 15 x (-2)
= 15 x (-3 - (-2))
= 15 x (-1)
= -15
73 x (8-59) - 59 x (8-73)
= 73 x 8 - 59 x 73 - 59 x (-65)
= 73 x 8 - 59 x (73 - (-65))
= 73 x 8 - 59 x 8
= 8 x (73-59)
= 8 x 14
= 112
(1+2+3+..+2046)x(15x13-15x12-15)=(1+2+...+2046)x15x(13-12-1)=0