2 hm + 238dam......... 526dam 326
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\(\dfrac{327}{326}=1\dfrac{1}{326},\dfrac{326}{325}=1\dfrac{1}{325}\)
Do \(\dfrac{1}{326}< \dfrac{1}{325}\Rightarrow1\dfrac{1}{326}< 1\dfrac{1}{325}\)
\(\Rightarrow\dfrac{327}{326}< \dfrac{326}{325}\)
Có: \(\dfrac{327}{326}=1+\dfrac{1}{326}\)
\(\dfrac{326}{325}=1+\dfrac{1}{325}\)
Mà \(\dfrac{1}{326}< \dfrac{1}{325}\Rightarrow1+\dfrac{1}{326}< 1+\dfrac{1}{325}\Rightarrow\dfrac{327}{326}< \dfrac{326}{325}\)
\(\frac{327}{326}=1+\frac{1}{326};\frac{326}{325}=1+\frac{1}{325}\)
Vì \(\frac{1}{326}<\frac{1}{325}\) nên \(1+\frac{1}{326}<1+\frac{1}{325}\)
Vậy \(\frac{327}{326}<\frac{326}{325}\)
Tick đúng cho mình nha
− 326 − ( 115 − 326 ) = − 326 − 115 + 326 = ( − 326 + 326 ) − 115 = 0 − 115 = − 115.
\(\dfrac{1}{10}hm^2=1000m^2\)
\(\dfrac{3}{5}hm^2=6000m^2\)
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
\(\Leftrightarrow\frac{x+2}{327+1}+\frac{x+3}{326+1}+\frac{x+4}{325+1}+\frac{x+5}{324+1}+\frac{x+349}{5-4}=0\)
\(\Leftrightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\Leftrightarrow\left(x+329\right)\cdot\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
Do \(\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)\ne0\)
Nên \(x+329=0\Rightarrow x=-329\)