Tìm x biết:
a) (3/4.x-0,54) : (-2/9) =0,48 - 3/4
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(3/4.x-27/50) : (-2/9) = 12/25 - 3/4
(3/4.x-27/50) : (-2/9) = -27/100
3/4.x-27/50 = -27/100 × (-2/9)
3/4.x-27/50 = 3/50
3/4.x = 3/50 + 27/50
3/4.x = 3/5
x = 3/5 :3/4
x = 4/5
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\(\left(\frac{3}{4}\times x-0,54\right):\frac{2}{9}=\frac{3}{4}-0,48\)
\(\left(\frac{3}{4}\times x-0,54\right):\frac{2}{9}=0,27\)
\(\left(\frac{3}{4}\times x-0,54\right)=0,27\times\frac{2}{9}\)
\(\left(\frac{3}{4}\times x-0,54\right)=0,06\)
\(\frac{3}{4}\times x=0,06+0,54\)
\(\frac{3}{4}\times x=0,6\)
\(x=0,6:\frac{3}{4}\)
\(x=0,8\)
(3/4 *x -0.54):2/9 = 3/4- 12/25
(3/4 *x- 27/50) :2/9 =27/100
3/4*x- 27/50 = 27/100* 2/9
3/4*x-27/50 = 3/50
3/4*x = 3/50+ 27/50
3/4*x =3/5
x= 3/5:3/4= 4/5
2(x4+3)-(9)=17
⇒2x4+6+9=17
⇒2x4+15=17
⇒ 2x4=2
⇒ x4=1
⇒ x=\(\pm1\)
b) 5x2.x+1-3.42=-47
⇒5x3+1-48=-47
⇒5x3-47=-47
⇒5x3=0
⇒x3=0
⇒x=0
a) \(2\left(x^4+3\right)-\left(-9\right)=17\)
\(2x^4+6+9=17\)
\(2x^4=2\)
\(x^4=1\)
⇒ \(x=1\)
( 3/4 . x - 0,54 ) . 4/9 + 8/75 = 4/15
( 3/4 . x - 0,54 ) . 4/9 = 4/15 - 8/75
( 3/4 . x - 0,54 ) . 4/9 = 4/25
3/4 . x - 0,54 = 4/25 : 4/9
3/4 . x - 0,54 = 9/25
3/4 . x = 9/25 + 0,54
3/4 . x = 9/10
x = 3/4 : 9/10
x = 5/6
\(\left(\frac{3}{4}x-0,54\right)\frac{4}{9}+\frac{8}{75}=\frac{4}{15}\)
\(\left(\frac{3}{4}x-\frac{27}{50}\right)\frac{4}{9}=\frac{4}{15}-\frac{8}{15}=\frac{-4}{15}\)
\(\frac{3}{4}x-\frac{27}{50}=\frac{-4}{15}:\frac{4}{9}=\frac{-3}{5}\)
\(\frac{3}{4}x=\frac{-3}{5}+\frac{27}{50}=\frac{-3}{50}\)
\(x=\frac{-3}{50}:\frac{3}{4}\)
\(x=\frac{-2}{25}\)
\(\left(\frac{3}{4}\cdot X-0.54\right):\left(-\frac{2}{9}\right)=0.48-\frac{3}{4}\)
\(\left(\frac{3}{4}.X-0.54\right):\left(-\frac{2}{9}\right)=\frac{-27}{100}\)
\(\left(\frac{3}{4}.X-0.54\right)=\frac{-27}{100}.\frac{-2}{9}\)
\(\left(\frac{3}{4}.X-0.54\right)=\frac{3}{50}\)
\(\frac{3}{4}.X=\frac{3}{50}+0.54\)
\(\frac{3}{4}.X=\frac{3}{50}+\frac{27}{50}\)
\(\frac{3}{4}.X=\frac{3}{5}\)
X= \(\frac{3}{5}:\frac{3}{4}\)
X= \(\frac{3}{5}.\frac{4}{3}\)
X=\(\frac{4}{5}\)