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Giúp em với em đang cần gấppp:<VI. Give the correct form of verbs in the bracket : The past simple tense.1. I ( meet ) ______ them at the movie theater last night.2. He ( go ) _________ to English club two days ago.3. She ( teach ) ______  at a village school last year?4. They ( not / return ) __________ Ha Noi last week.5. What ( the children / do ) __________ this morning ?6. Where they ( live ) __________ in 2005 ?7. The students (  not / be ) __________ here twenty five minutes...
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Giúp em với em đang cần gấppp:<
VI. Give the correct form of verbs in the bracket : The past simple tense.

1. I ( meet ) ______ them at the movie theater last night.

2. He ( go ) _________ to English club two days ago.

3. She ( teach ) ______  at a village school last year?

4. They ( not / return ) __________ Ha Noi last week.

5. What ( the children / do ) __________ this morning ?

6. Where they ( live ) __________ in 2005 ?

7. The students (  not / be ) __________ here twenty five minutes ago.

They ( be ) __________ in their classroom.

8. This morning, I ( get ) __________ up, ( brush ) __________ my teeth,

( wash ) __________ my face then ( have ) __________  breakfast.

9. My parents __________ very tired after the trip. (be)

10. I __________a lot of gifts for my little sister. (buy)

11. Lan and Mai _______ sharks, dolphins and turtles at Tri Nguyen aquarium. (see)

12. Trung _____ chicken and rice for dinner. (eat)

13. They ____ about their holiday in Hoi An. (talk)

14. Phuong _____ to Hanoi yesterday. (return?

15. We _____ the food was delicious.(think)

16. They (buy) __________that house last year?

17. She (not go) __________to school yesterday.

18. That boy (have) __________some eggs last night ?

4

VI. Give the correct form of verbs in the bracket : The past simple tense.

1. What did ( the children / do ) _____do_____ this morning ?

2. Where did they ( live ) _____live_____ in 2005 ?

3. The students (  not / be ) ____weren't______ here twenty five minutes ago.

They ( be ) ____were______ in their classroom.

4. This morning, I ( get ) ____got______ up, ( brush ) ____brushed______ my teeth,

( wash ) _____washed_____ my face then ( have ) _____had_____  breakfast.

5. My parents _____were_____ very tired after the trip. (be)

6. I bought lot of gifts for my little sister. (buy)

7. Lan and Mai ___saw____ sharks, dolphins and turtles at Tri Nguyen aquarium. (see)

8. Trung __ate___ chicken and rice for dinner. (eat)

9. They __talked__ about their holiday in Hoi An. (talk)

10.Did Phuong __return___ to Hanoi yesterday. (return?

11. We ___thought__ the food was delicious.(think)

12. Did They (buy) _____buy_____that house last year?

13. She (not go) ____didn't go______to school yesterday.

14. Did That boy (have) _____have_____some eggs last night ?

15 tháng 2 2022

1.did the children do

2.did they live

3.weren't/were

4.got/brushed/washed/had

5.were

6.bought

7.saw

8.ate

9.talked

10.returned

11.thought

12.didn't go

13.Did that boy have

20 tháng 10 2021

Bài 2: 

Tọa độ giao điểm  là:

\(\left\{{}\begin{matrix}2x+y=3\\3x-2y=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}4x+2y=6\\3x-2y=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=1\\x=1\end{matrix}\right.\)

Thay x=1 và y=1 vào (d), ta được:

\(2m-1+1=5m\)

\(\Leftrightarrow m=0\)

11 tháng 1 2022

Vì (13x + 4y) ⋮ 17 => 5(13x + 4y) ⋮ 17 hay (65x + 20y) ⋮ 17 (1). Nếu (7x + 10y) ⋮ 17 => 2(7x + 10y) ⋮ 17 hay (14x + 20y) ⋮ 17 (2). Từ (1)(2) => (65x + 20y) - (14x + 20y) = 51x = 17.3x ⋮ 17 => (7x + 10y) ⋮ 17. Vậy (7x + 10y) ⋮ 17 (đpcm)

  
11 tháng 10 2021

\(a,\Leftrightarrow\left\{{}\begin{matrix}8x+12y=16\\8x+12y=-3\end{matrix}\right.\Leftrightarrow HPT.vô.nghiệm\\ b,\Leftrightarrow\left\{{}\begin{matrix}2x-2y+6x+3y=5\\5x+5y-4x+2y=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}8x+y=5\\x+7y=2\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}56x+7y=35\\x+7y=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{3}{5}\\y=\dfrac{1}{5}\end{matrix}\right.\\ c,\Leftrightarrow\left\{{}\begin{matrix}\dfrac{x}{6}+\dfrac{y}{8}=\dfrac{5}{2}\\\dfrac{x}{6}+\dfrac{y}{9}=\dfrac{2}{3}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{x}{2}+\left(-\dfrac{11}{18}\right)=2\\y=\dfrac{2}{3}-\dfrac{5}{2}=-\dfrac{11}{6}\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{47}{9}\\y=-\dfrac{11}{6}\end{matrix}\right.\)

\(d,ĐK:x\ne-2;y\ne1\\ HPT\Leftrightarrow\left\{{}\begin{matrix}\dfrac{2}{x+2}-\dfrac{6}{y-1}=4\\\dfrac{2}{x+2}+\dfrac{2}{y-1}=5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{1}{x+2}-\dfrac{3}{y-1}=2\\\dfrac{8}{y-1}=1\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}\dfrac{1}{x+2}=2+\dfrac{3}{8}=\dfrac{19}{8}\\y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-\dfrac{30}{19}\\y=9\end{matrix}\right.\)

\(e,\Leftrightarrow\left\{{}\begin{matrix}x^2=4-y^2\\3\left(4-y^2\right)-2y^2=3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x^2=4-y^2\\12-5y^2=3\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x^2=4-y^2\\y^2=\dfrac{9}{5}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x^2=\dfrac{11}{5}\\y^2=\dfrac{9}{5}\end{matrix}\right.\)

Vậy hpt có nghiệm \(\left(x;y\right)=\left\{\left(\pm\dfrac{\sqrt{55}}{5};\pm\dfrac{3\sqrt{5}}{5}\right)\right\}\)

Phương trình hoành độ giao điểm là:

\(x^2-2mx+m^2-m=0\)

a: Để (P) cắt (d) tại hai điểm phân biệt thì \(\left(-2m\right)^2-4\left(m^2-m\right)>0\)

=>4m>0

hay m>0

b: Để (P) cắt (d) tại hai điểm nằm về hai phía của trục tung thì \(m^2-m< 0\)

=>0<m<1

1 tháng 4 2022

Câu này tương đối lằng nhằng khi lấy biểu thức A nhân với biểu thức B

Vì rút gọn A thì biểu thức của A siêu lằng nhằng

1 tháng 4 2022

Để làm được câu c thì phải qua câu b trước đã

Bài 1: 2)\(A=\dfrac{\sqrt{x}+1}{2\sqrt{x}-1}+\dfrac{\sqrt{x}}{\sqrt{x}+3}-\dfrac{x+6\sqrt{x}+2}{2x+5\sqrt{x}-3}\)

                \(=\dfrac{\left(\sqrt{x}+1\right)\left(\sqrt{x}+3\right)+\left(2\sqrt{x}-1\right)\sqrt{x}}{\left(2\sqrt{x}-1\right)\left(\sqrt{x}+3\right)}-\dfrac{\sqrt{x}^2+6\sqrt{x}+2}{2x-\sqrt{x}+6\sqrt{x}-3}\\ =\dfrac{\sqrt{x}^2+3\sqrt{x}+\sqrt{x}+3+2\sqrt{x}^2-\sqrt{x}-\sqrt{x}^2-6\sqrt{x}-2}{\left(2\sqrt{x}-1\right)\left(\sqrt{x}+3\right)}\\ =\dfrac{2\sqrt{x}^2-3\sqrt{x}+1}{\left(2\sqrt{x}-1\right)\left(\sqrt{x}+3\right)}\\ =\dfrac{2\sqrt{x}^2-2\sqrt{x}-\sqrt{x}+1}{\left(2\sqrt{x}-1\right)\left(\sqrt{x}+3\right)}\\ =\dfrac{2\sqrt{x}\left(\sqrt{x}-1\right)-\left(\sqrt{x}-1\right)}{\left(2\sqrt{x}-1\right)\left(\sqrt{x}+3\right)}\\ =\dfrac{\left(2\sqrt{x}-1\right)\left(\sqrt{x}-1\right)}{\left(2\sqrt{x}-1\right)\left(\sqrt{x}+3\right)}\\ =\dfrac{\sqrt{x}-1}{\sqrt{x}+3}\)

\(P=A\cdot B=\dfrac{\sqrt{x}-1}{\sqrt{x}+3}\cdot\dfrac{\sqrt{x}+3}{x+8}=\dfrac{\sqrt{x}-1}{x+8}\)

 

15 tháng 10 2021

Bài 2: 

a: Xét (O) có

CM là tiếp tuyến có M là tiếp điểm

CA là tiếp tuyến có A là tiếp điểm

Do đó: CM=CA

Xét (O) có 

DM là tiếp tuyến có M là tiếp điểm

DB là tiếp tuyến có B là tiếp điểm

Do đó: DM=DB

Ta có: CM+MD=CD

mà CM=CA

và DM=DB

nên CD=CA+DB