8/15 : 2/11 - 7/15 : 2/11
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\(\dfrac{2}{1}+\dfrac{12}{56}=\dfrac{112+12}{56}=\dfrac{122}{56}=\dfrac{61}{28}\)
\(\left(\dfrac{8+7}{15}\right):\dfrac{2}{11}\)
\(1:\)\(\dfrac{2}{11}\)
\(\dfrac{11}{2}\)

8: \(=\dfrac{-5}{9}-\dfrac{4}{9}+\dfrac{8}{15}+\dfrac{7}{15}-\dfrac{2}{11}=\dfrac{-2}{11}\)
9: =2/7-2/5+5/7=1-2/5=3/5
10: \(=\dfrac{7}{19}\left(\dfrac{8}{11}+\dfrac{3}{11}\right)-\dfrac{12}{19}=\dfrac{-5}{19}\)
11: \(=\dfrac{-5}{7}\left(\dfrac{2}{11}+\dfrac{9}{11}\right)=\dfrac{-5}{7}\)

a ,b
cách 1 : cộng 2 số trong ngặc rồi tính bình thường
cách 2 : nhân phân phối ra rồi tính nhân chia trước cộng trừ sau
c,d
cách 1 : tính bình thường, nhân chia trc cộng trừ sau
cách 2 : đặt nhân tử ( thừa số ) chung
Cách 1 : \((\frac{6}{11}+\frac{5}{11})\cdot\frac{3}{7}=1\cdot\frac{3}{7}=\frac{3}{7}\)
Cách 2 : \(\frac{6}{11}\cdot\frac{3}{7}+\frac{5}{11}\cdot\frac{3}{7}=\frac{18}{77}+\frac{15}{77}=\frac{33}{77}=\frac{3}{7}\)
Cách 1 dễ rồi nha
Cách 2 : \(\frac{6}{7}:\frac{2}{5}-\frac{4}{7}:\frac{2}{5}=\frac{15}{7}-\frac{10}{7}=\frac{5}{7}\)
Cách 1 tự làm
Cách 2 : \(\frac{3}{5}\cdot(\frac{7}{9}-\frac{2}{9})=\frac{3}{5}\cdot\frac{5}{9}=\frac{1}{3}\)
Cách 1 : ...
Cách 2 : \((\frac{8}{15}+\frac{7}{15}):\frac{2}{11}=1:\frac{2}{11}=\frac{2}{11\cdot1}=\frac{2}{11}\)

a) Cách 1:
(6/7 - 4/7):2/5
=2/7 : 2/5
=5/7
Cách 2:
(6/7 - 4/7):2/5
=6/7:2/5 - 4/7:2/5
=15/7-10/7
=5/7
b) Cách 1:
8/15:2/11+7/15:2/11
=44/15+77/30
=165/30=11/2
Cách 2:
8/15:2/11+7/15:2/11
= (8/15+7/15):2/11
=1:2/11
=11/2


a: \(=\left(15-6-\dfrac{13}{18}\right):\dfrac{298}{27}-\dfrac{17}{8}:\dfrac{51}{40}\)
\(=\dfrac{149}{18}\cdot\dfrac{27}{298}-\dfrac{5}{3}=\dfrac{3}{2}-\dfrac{5}{3}=\dfrac{9-10}{6}=\dfrac{-1}{6}\)
b: \(=\dfrac{-16}{5}\cdot\dfrac{-15}{64}+\dfrac{-22}{15}:\dfrac{11}{2}\)
\(=\dfrac{3}{4}-\dfrac{4}{15}=\dfrac{29}{60}\)
c: \(=\dfrac{-7}{9}\left(\dfrac{4}{11}+\dfrac{7}{11}\right)+5+\dfrac{7}{9}=\dfrac{-7}{9}+\dfrac{7}{9}+5=5\)
d: \(=\dfrac{1}{2}\cdot\dfrac{4}{3}\cdot10\cdot\dfrac{1}{5}\cdot\dfrac{3}{4}=1\)
e: \(=\dfrac{4}{25}+\dfrac{11}{2}\cdot\dfrac{5}{2}+\dfrac{-23}{4}=\dfrac{204}{25}\)

\(\frac{8}{15}:\frac{2}{11}+\frac{7}{15}:\frac{2}{11}\)
\(=\frac{8}{15}\times\frac{11}{2}+\frac{7}{15}\times\frac{11}{2}\)
\(=\frac{11}{2}\times\left(\frac{8}{15}+\frac{7}{15}\right)\)
\(=\frac{11}{2}\times1\)
\(=\frac{11}{2}\)
P/s tham khảo nha

cách 1 :
\(\frac{3}{5}\chi\frac{7}{9}+\frac{3}{5}\chi\frac{2}{9}\)
= \(\frac{3}{5}\chi\left(\frac{7}{9}+\frac{2}{9}\right)\)
= \(\frac{3}{5}\chi1\)
= \(\frac{3}{5}\)
cách 2 :
\(\frac{3}{5}\chi\frac{7}{9}+\frac{3}{5}\chi\frac{2}{9}\)
= \(\frac{7}{15}\) + \(\frac{2}{15}\)
= \(\frac{9}{15}=\frac{3}{5}\)
\(C1:\frac{3}{5}.\frac{7}{9}+\frac{3}{5}.\frac{2}{9}\) \(C2:\frac{3}{5}.\frac{7}{9}+\frac{3}{5}.\frac{2}{9}\)
\(=\frac{3}{5}\left(\frac{7}{9}+\frac{2}{9}\right)=\frac{3}{5}.1=\frac{3}{5}\) \(=\frac{7}{15}+\frac{2}{15}=\frac{3}{5}\)
\(C1:\frac{8}{15}:\frac{2}{11}+\frac{7}{15}:\frac{2}{11}\) \(C2:\frac{8}{15}:\frac{2}{11}+\frac{7}{15}:\frac{2}{11}\)
\(=\left(\frac{8}{15}+\frac{7}{15}\right):\frac{2}{11}=1:\frac{2}{11}=\frac{11}{2}\) \(=\frac{44}{15}+\frac{77}{30}=\frac{88}{30}+\frac{77}{30}=\frac{11}{2}\)
\(\left(\dfrac{8}{15}-\dfrac{7}{15}\right):\dfrac{11}{2}\)
\(\dfrac{1}{15}x\dfrac{11}{2}=\dfrac{11}{30}\)
\(\dfrac{8}{15}:\dfrac{2}{11}-\dfrac{7}{15}:\dfrac{2}{11}\)
\(=\left(\dfrac{8}{15}-\dfrac{7}{15}\right).\dfrac{11}{2}\)
\(=\dfrac{1}{15}.\dfrac{11}{2}=\dfrac{11}{30}\)