Mn ơi giúp em vs ạ
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PL
30 tháng 8 2022
Bài 1: \(n_{CuO}=\dfrac{3,2}{80}=0,04\left(mol\right)\)
\(CuO+H_2SO_4\rightarrow CuSO_4+H_2O\)
0,04 → 0,04
\(\Rightarrow m_{H_2SO_4}=0,04\cdot98=3,92\left(g\right)\)
\(\Rightarrow C\%_{H_2SO_4}=\dfrac{3,92}{80}\cdot100\%=4,9\%\)
Bài 2: \(n_{HCl}=0,2\cdot2=0,4\left(mol\right)\)
\(Fe_2O_3+6HCl\rightarrow2FeCl_3+3H_2\uparrow\)
\(\dfrac{1}{15}\) ← 0,4
\(\Rightarrow m_{Fe_2O_3}=\dfrac{1}{15}\cdot160=\dfrac{32}{3}\left(g\right)\)
DT
Đỗ Thanh Hải
CTVVIP
11 tháng 8 2021
Tham khảo
1. She bought this shirt yesterday
this shirt was bought yesterday
2. This baby drinks milk every day
milk is drunk by This baby every day
3. The students have cleaned the room
the room has been cleaned by The students
4. I can do these exercise
these exercise can be done by me
5. The students are writing the lessons now
the lessons are being written by The students now
6. we shall visit him tomorrow
He shall be visited tomorrow
7. he has his wife wash the clothes
he has the clothes washed by his wife
8. The students have done the test
the test has been done by The students
9. she is writing the letter now
the letter is being written now
10. he had decorated the house before last Tet
the house had been decorated before last Tet
11. we eat rice every day
rice is eaten every day
12. they were watching a film at the time
a film was being watched at the time
13. the children are singing a song now
a song is being sung by the children now
14. we have learnt thí unit
This unit has been learnt
15. he sent him a letter yesterday
A letter was sent to him yesterday
16. thay planted the trees in the garden
The trees were planted in the garden
17. he drank all the water in the bottle
all the water in the bottle was drunk
18. i will do that work for her
that work will be done for her
19. we have our mother wash the clothes
we have the clothes washed by our mother
20. Lan has got her bike repaired by Ba
HL
0
HL
0
a: Xét ΔABM và ΔDBM có
BA=BD
\(\widehat{ABM}=\widehat{DBM}\)
BM chung
Do đó: ΔABM=ΔDBM
b: Ta có: ΔABM=ΔDBM
nên \(\widehat{BAM}=\widehat{BDM}=90^0\)
c: Ta có: BA=BD
nên ΔBAD cân tại B
mà BM là đường phân giác
nên BM là đường cao
d: Ta có: ΔABM=ΔDBM
nên MA=MD
Ta có: BA=BD
nên B nằm trên đường trung trực của AD(1)
Ta có: MA=MD
nên M nằm trên đường trung trực của AD(2)
Từ (1) và (2) suy ra BM là đường trung trực của AD
hay BM⊥AD
C giúp em nốt ý g và h đc ko ạ 🥺