Tính: 1.2.3+2.3.4+...+48.49.50
Ai nhanh mk tick. Ths
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a) A=1.2.3+2.3.4+...+98.99.100
4A=1.2.3.4+2.3.4.4+3.4.5.4+...+98.99.100.4
=1.2.3.4+2.3.4.(5-1) + 3.4.5.(6-2) +...+ 98.99.100.(101-97)
=1.2.3.4+2.3.4.5 -1.2.3.4+3.4.5.6 -2.3.4.5+...+98.99.100.101-97.98.99.100
= 98.99.100.101
Suy ra A=98.99.100.101
=24497550
đặt S=1.2.3+2.3.4+....+47.48.49
4S=1.2.3.(4-0)+2.3.4.(5-1)+...+47.48.49.(50-46)
4S=1.2.3.4-1.2.3+2.3.4.5-1.2.3.4+....+47.48.49.50-46.47.48.49
4S=47.48.49.50-1.2.3
S=(47.48.49.50-1.2.3):4
A=3+3^2+3^3+...+3^2004
Ta có:A=(3+3^2+3^3+3^4)+...+(3^2001+3^2002+3^2003+3^2004)
=>A=120+...+(3^2000.3+3^2000.3^2+3^2000.3^3+3^2000.3^4)
=>A=120+...+3^2000(3+3^2+3^3+3^4)
=>A=120+...+3^2000.120
=>A=(1+...+3^2000).120
Vì 120 chia hết cho 120 nên A chia hết cho 120=>A chia hết cho 10
A=3+3^2+3^3+...+3^2004
=>A=(3+3^2+3^3)+...+(3^2002+3^2003+3^2004)
=>A=39+...+(3^2000.3+3^2000.3^2+3^2000.3^3)
=>A=39+...+3^2000(3+3^2+3^3)
=>A=39+...+3^2000.39
=>A=(1+...+3^2000).39
Vì 39 chia hết cho 13 nên A chia hết cho 13
Ta có:A chia hết cho 10;A chia hết cho 13 và (10;13)=1 nên A chia hết cho 10.13
=>A chia hết cho 130
Vậy...
Đặt A=1.2+2.3+3.4+............+1999.2000
3A=1.2.3+2.3.(4-1)+.................+1999.2000.(2001-1998)
3A=1.2.3+2.3.4-1.2.3+............+1999.2000.2001-1998.1999.2000
3A=1999.2000.2001
A=1999.2000.2001:3
A=2666666000
b,Đặt B=1.2+2.2+3.3+............+1999.1999
B=1.(2-1)+2.(3-1)+3.(4-1)+..........+1999.(2000-1)
B=1.2-1+2.3-2+3.4-3+...........+1999.2000-1999
B=(1.2+2.3+3.4+.............+1999.2000)-(1+2+3+...........+1999)
B=2666666000-1999000
B=2664667000
c,Đặt C=1.2.3+2.3.4+..........+48.49.50
4C=1.2.3.4+2.3.4.(5-1)+.........+48.49.50.(51-47)
4C=1.2.3.4+2.3.4.5-1.2.3.4+..............+48.49.50.51-47.48.49.50
4C=48.49.50.51
C=48.49.50.51:4
C=1499400
\(A=\frac{9}{1.2}+\frac{9}{2.3}+\frac{9}{3.4}+...+\frac{9}{98.99}+\frac{9}{99.100}\)
\(A=\frac{1}{9}.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{98.99}+\frac{1}{99.100}\right)\)
\(A=\frac{1}{9}.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\right)\)
\(A=\frac{1}{9}.\left(1-\frac{1}{100}\right)\)
\(A=\frac{1}{9}.\frac{99}{100}\)
\(A=\frac{11}{100}\)
A = 9/1.2 + 9/2.3 + 9/3.4 +...+ 9/98.99 + 9/99.100
= 9. (1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/98 - 1/99 + 1/99 - 1/100)
= 9. (1 - 1/100)
= 9 . 99/100
= 891/100