5+ 5=???
giup với
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-12.(x-5)+7.(3-x)=5
-12x-60+21-7x=5
(-12x-7x)-(60+21)=5
-19x-81=5
-19x=5-81
-19x=-76
x=-76:(-19)
x=4
x=
x=44:(-19)
\(-12\left(x-5\right)+7\left(3-x\right)=5\)
\(60-12x+21-7x=5\)
\(81-19x=5\)
\(19x=81-5\)
\(19x=76\)
\(x=4\)
6)
a) \(x-150:5=-40\\ \Rightarrow x=-40+30\\ \Rightarrow x=-10\)
b) \(\dfrac{11}{12}+\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\\ \Rightarrow\dfrac{2}{5}+x=\dfrac{2}{3}-\dfrac{11}{12}\\ \Rightarrow x=-\dfrac{1}{4}-\dfrac{2}{5}\\ \Rightarrow x=-\dfrac{13}{20}\)
c) \(\dfrac{162}{3^x}=2\\ \Rightarrow2.3^x=162\\ \Rightarrow3^x=81\\ \Rightarrow3^x=3^4\\ \Rightarrow x=4\)
\(\Leftrightarrow5^x\left(1+5^2\right)=650\)
\(\Leftrightarrow5^x26=650\)
\(\Leftrightarrow5^x=25\)
\(\Leftrightarrow5^x=5^2\)
<=> x = 2
5x + 5x+2 = 650
5x + 5x . 52 = 650
5x . (1 + 52) = 650
5x = 650 : 26
5x = 52
x = 2
\(5^{20}:\left(5^{16}+5^{15}\cdot20\right)\)
\(=5^{20}:\left[5^{15}\left(5+20\right)\right]\)
\(=\frac{5^5}{25}\)
\(=\frac{5^5}{5^2}\)
\(=5^3\)
X + \(\frac{5}{2}\)x \(\frac{2}{3}\)= \(\frac{5}{2}\)
X + \(\frac{5}{3}\) = \(\frac{5}{2}\)
X = \(\frac{5}{2}\)- \(\frac{5}{3}\)
X = \(\frac{5}{6}\)
~ Hok T ~
x + 5/2 x 2/3 = 5/2
x + 10/6 = 5/2
x = 5/2 - 10/6
x = 5/6
Ai trên 10 SP k tui ikkkkkkkk
\(A=5^5+5^4-8.5^3\)
\(A=5^3.\left(5^2+5-8\right)\)
\(A=5^3.22\)
\(A=5^3.2.11⋮11\)
Vậy \(A=5^5+5^4-8.5^3\)chia hết cho 11
\(3x+5\)\(⋮\)\(2x+1\)
\(\Leftrightarrow2\left(3x+5\right)\)\(⋮\)\(2x+1\)
\(\Rightarrow6x+10\)\(⋮\)\(2x+1\)
\(\Rightarrow3\left(2x+1\right)+7\)\(⋮\)\(2x+1\)
\(\Leftrightarrow7\)\(⋮\)\(2x+1\)
\(\Rightarrow2x+1\inƯ_7\)Mà \(Ư_7=\left\{\pm1;\pm7\right\}\)
\(\Rightarrow...\)
\(C=5\left(\frac{5}{1.6}+\frac{5}{6.11}+...+\frac{5}{26.31}+\frac{5}{31.35}\right).\)
\(=5\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+...+\frac{1}{26}-\frac{1}{31}+\frac{1}{31.35}\right)\)
\(=5\left(1-\frac{1}{31}+\frac{1}{31.35}\right)\)
\(=\frac{10501}{2107}\)
Ta có : \(C=\frac{5^2}{1.6}+\frac{5^2}{6.11}+\frac{5^2}{11.16}+...+\frac{5^2}{31.36}\)
\(\Leftrightarrow\frac{C}{5}=\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+...+\frac{5}{31.36}\)
\(=\frac{1}{1}-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+\frac{1}{11}-\frac{1}{16}+...+\frac{1}{31}-\frac{1}{36}\)
\(=1-\frac{1}{36}=\frac{35}{36}\)
\(\Rightarrow C=\frac{35}{36}\cdot5=\frac{175}{36}\)
Vậy : \(C=\frac{175}{36}\)
P/s : Không chắc lắm :))
= 10....k dùm
bằng 10 nha