22.5+(49-172)
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- [ - 171 + ( 171 + 23 )] - [ 172 -( 38 + 172) ] - 49
= - [ - 171 + 171 + 23] - [ 172 -38 - 172] - 49
= -23 - ( -38) - 49
= -23 +38 -49
= 15 - 49
= - 34
a) 29 – [16 + 3.(51 – 49)]
b) 5.22 + 98:72
c) 311 : 39 – 147 : 72
d) 295 – (31 – 22.5)2
718 : 716 +22.33
a-[171+(171+23)]-[172-(38+172)]-49
=[171+194]-[172-210]-49
=365-(-38)-49
=403-49=354
\(a)\) \(5^{13}:5^{10}-25.2^2=5^3-25.4=125-100=25\)
\(b)\) \(20:2^2+5^9:5^8=20:4+5^1=5+5=10\)
\(c)\) \(100:5^2+7.3^2=100:25+7.9=4+36=40\)
\(d)\) \(84:4+3^9:3^7+5^0=84:4+3^2+1=21+9+1=31\)
\(e)\)
\(29-\left[16+3.\left(51-49\right)\right]=29-\left[16+3.2\right]=29-\left[16+6\right]=29-22=7\)
\(f)\) \(5.2^2+98:7^2=5.4+98:49=20+2=22\)
\(g)\) \(3^{11}:3^9-147:7^2=3^2-147:49=9-3=6\)
\(295-\left(31-2^2.5\right)^2=295-\left(31-4.5\right)^2=295-\left(31-20\right)^2=295-11^2=295-121=174\)
\(7^{18}:7^{16}+2^2.3^2=7^2+4.9=49+36=85\)
a: \(5^{13}:5^{10}-25\cdot2^2\)
\(=5^3-25\cdot4\)
=125-100
=25
b: \(20:2^2+5^9:5^8\)
\(=20:4+5\)
=5+5
=10
2.|-5|.|-3|-4-4.(25:5)+|-4|
[15:(-3)+40:(-8)].3(16:8)
-[-171+(171+23)]-[172-(38+172)]-49
giúp mik vs :3
\(2\cdot\left|-5\right|\cdot\left|-3\right|-4-4\cdot(25:5)+\left|-4\right|\)
\(=2\cdot5\cdot3-4-4\cdot5+4\)
\(=30-4-4\cdot5+4=30-4-20+4=10\)
\(a)196:4-12.\left(-5\right)=49+60=109.\\ b)2^2.5+\left(49-17^2\right)=4.5+49-289=20-240=-220.\\ c)29.\left(15-34\right)-15.\left(29-34\right)=29.15-29.34-15.29+15.34=-29.34+15.34=-476.\)
Bài 2:
Gọi số sách là x
Theo đề, ta có: \(x\in BC\left(10;12;15\right)\)
mà 100<=x<=150
nên x=120
\(=20+49-289=-220\)
=20+49−289=−220