Tìm x E N biết
b, x:18; x:30; x:12 và 100<x<400
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Áp dụng tc dtsbn:
\(3x=7y\Rightarrow\dfrac{x}{7}=\dfrac{y}{3}=\dfrac{x-y}{7-3}=\dfrac{-16}{4}=-4\\ \Rightarrow\left\{{}\begin{matrix}x=-28\\y=-12\end{matrix}\right.\)
b) \(\Leftrightarrow3x^3+12x-2x^2-8=0\\ \Leftrightarrow\left(3x^3-2x^2\right)+\left(12x-8\right)=0\\ \Leftrightarrow x^2\left(3x-2\right)+4\left(3x-2\right)=0\\ \Leftrightarrow\left(x^2+4\right)\left(3x-2\right)=0\)
Vì \(x^2+4>0\Rightarrow3x-2=0\Rightarrow x=\dfrac{2}{3}\)
c) \(x^2+5x=0\\ \Leftrightarrow x\left(x+5\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=-5\end{matrix}\right.\)
d) \(\Leftrightarrow x^3-27+x\left(4-x^2\right)=36\\ \Leftrightarrow x^3+4x-x^3=63\\ \Leftrightarrow4x=63\\ \Leftrightarrow x=\dfrac{63}{4}\)
b) 3x(x\(^3\) +12x-2x\(^2\)-8=0
3x(x\(^2\)+4)-2(x\(^2\)+4)=0
(x\(^2\)+4)(3x-2)=0
\(\Leftrightarrow\left[{}\begin{matrix}X^2+4=0\\3X-2=0\end{matrix}\right.\) <=> \(\left[{}\begin{matrix}x\in Z\\X=\dfrac{2}{3}\end{matrix}\right.\)
a) x\(^2\)+5x=0
x(x+5)=0
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+5=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-5\end{matrix}\right.\)
c)(x-3)(x\(^2\)+3x+9)+x(x+2)(2-x)=36
x\(^3\)-27+x(x+2)(2-x)=36
4x-27=36
4x=36+27
4x=63
x=\(\dfrac{63}{4}\)
B-(\(3x^6-4xy^5+\dfrac{1}{3}xy^2\))=
B= \(\left(7x^6-\dfrac{1}{2}xy^5-xy^2-\dfrac{1}{3}\right)+\left(3x^6-4xy^5+\dfrac{1}{3}xy^2-\dfrac{3}{2}\right)\)
B= \(7x^6-\dfrac{1}{2}xy^5-xy^2-\dfrac{1}{3}+3x^6-4xy^5+\dfrac{1}{3}xy^2-\dfrac{3}{2}\)
B= \(7x^6+3x^6-\dfrac{1}{2}xy^5-4xy^5-xy^2+\dfrac{1}{3}xy^2-\dfrac{1}{3}+\dfrac{2}{3}\)
B= \(10x^6-\dfrac{9}{2}xy^5-\dfrac{2}{3}xy^2+\dfrac{1}{3}\)
A. 3x(x-1) = 21
x-1 = 21: 3
x-1 = 7
x = 7+1
x = 8
Vậy x=8
B. 30-3x(x-2)=18
3x(x-2)= 30-18
3x(x-2)= 12
x-2 = 12:3
x-2 = 4
x = 4+2
x = 6
Vậy x=6
\(a,3\left(x-1\right)=21\)
\(3x-3=21\)
\(3x=21+3\)
\(3x=24\)
\(x=8\)
\(b,30-3\left(x-2\right)=18\)
\(30-3x+6=18\)
\(30-3x=18-6\)
\(30-3x=12\)
\(3x=30-12\)
\(3x=18\)
\(x=6\)
\(1\)/
\(a\)) \(=\left(\dfrac{7}{5}-\dfrac{8}{7}\right)+\dfrac{17}{5}:0,6\)
\(=\dfrac{9}{35}+\dfrac{17}{3}\)
\(=\dfrac{622}{105}\)
\(b\)) \(=\dfrac{11}{6}+\dfrac{-14}{15}\)
\(=\dfrac{9}{10}\)
\(c\)/ \(=\dfrac{7}{4}-\dfrac{2}{3}\)
\(=\dfrac{13}{12}\)
A = { 19 ; 20 }
B = { 1 ; 2 ; 3 }
C = { 35 ; 36 ; 37 ; 38 }
A = { 19;20 }
B = { 1;2;3 }
C = { 35;36;37;38 } k cho mik với nhé bn
ta phân tích
\(\hept{\begin{cases}18=2.3^2\\30=2.3.5\\12=2^2.3\end{cases}}\Rightarrow BCNN\left(12,18,30\right)=2^2.3^2.5=180\)
vậy x là bội của 180 mà x nằm trong khoảng 100 đến 400
nên hoẵ x =180 hoặc x =360