\(\frac{x}{75}\)=\(\frac{-5}{4}.\frac{x}{25}\)
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NT
0
25 tháng 2 2019
\(\frac{x+5}{95}+\frac{x+3}{97}+\frac{x+1}{99}=\frac{x+15}{85}+\frac{x+20}{80}+\frac{x+25}{75}.\)
\(\frac{x+5}{95}+1+\frac{x+3}{97}+1+\frac{x+1}{99}+1-\frac{x+15}{85}-1-\frac{x+20}{80}-1-\frac{x+25}{75}-1=0\)
\(\frac{x+100}{95}+\frac{x+100}{97}+\frac{x+100}{99}-\frac{x+100}{85}-\frac{x+100}{80}-\frac{x+100}{75}=0\)
\(\left(x+100\right).\left(\frac{1}{95}+\frac{1}{97}+\frac{1}{99}-\frac{1}{85}-\frac{1}{80}-\frac{1}{75}\right)=0\)
\(\Rightarrow x+100=0\Rightarrow x=-100\)
\(\frac{1}{95}+\frac{1}{97}+\frac{1}{99}-\frac{1}{85}-\frac{1}{80}-\frac{1}{75}\ne0\)
MT
23 tháng 6 2015
\(\frac{74-x}{26}+\frac{75-x}{25}+\frac{76-x}{24}+\frac{77-x}{23}+\frac{78-x}{22}=-5\)
\(\frac{74-x}{26}+1+\frac{75-x}{25}+1+\frac{76-x}{24}+1+\frac{77-x}{23}+1+\frac{78-x}{22}=-5+5\)
\(\frac{74-x}{26}+\frac{26}{26}+\frac{75-x}{25}+\frac{25}{25}+\frac{76-x}{24}+\frac{24}{24}+\frac{77-x}{23}+\frac{23}{23}+\frac{78-x}{22}+\frac{22}{22}=0\)
\(\frac{100-x}{26}+\frac{100-x}{25}+\frac{100-x}{24}+\frac{100-x}{23}+\frac{100-x}{22}=0\)
\(\left(100-x\right)\left(\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{23}+\frac{1}{22}\right)=0\)
=>100-x=0 ( \(\left(\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{23}+\frac{1}{22}\right)\ne0\))
x=100
hahaha
X
15 tháng 7 2015
A)\(75\%.x-\frac{3}{2}:\frac{5}{4}=3\frac{1}{2}+25\%\)
<=>\(\frac{3}{4}x-\frac{6}{5}=\frac{7}{2}+\frac{1}{4}\)
<=>\(\frac{3}{4}x=\frac{7}{2}+\frac{1}{4}+\frac{6}{5}\)
<=>\(\frac{3}{4}x=\frac{99}{20}\)
<=>\(x=\frac{33}{5}\)
B)\(\left(x-\frac{3}{4}\right).50\%-\frac{2}{7}=1+\frac{3}{4}\)
<=>\(\left(x-\frac{3}{4}\right)\cdot\frac{1}{2}=\frac{7}{4}\)
<=>\(\frac{1}{2}x-\frac{3}{8}=\frac{7}{4}\)
<=>\(\frac{1}{2}x=\frac{17}{8}\)
<=>\(x=\frac{17}{4}\)
C)\(\left(\frac{5}{6}-2\frac{1}{2}\right):x=\frac{2}{5}-\frac{1}{3}\)
<=>\(-\frac{5}{3}:x=\frac{1}{15}\)
<=>\(x=-\frac{25}{3}\)
D)\(\left(\frac{1}{4}-x\right)-\frac{1}{2}=2\frac{1}{2}+1\)
<=>\(\frac{1}{4}-x-\frac{1}{2}=\frac{7}{2}\)
<=>\(-\frac{1}{4}-x=\frac{7}{2}\)
<=>\(x=-\frac{15}{4}\)
30 tháng 10 2016
Bài 1:
a) Ta có:
\(3,2\cdot x+\left(-1,2\right)\cdot x+2,7=-4,9\)
\(\Rightarrow\left[3,2+\left(-1,2\right)\right]\cdot x=\left(-4,9\right)-2,7\)
\(\Rightarrow2x=-7,6\)
\(\Rightarrow x=\left(-7,6\right):2\)
\(\Rightarrow x=-3,8\)
Vậy \(x=-3,8\)
b) Ta có:
-5,6.x+2,9.x-3,86=-9,8
=>[(-5,6)+2,9].x=(-9,8)+3,86
=>(-2,7).x=-5,94
=>x=(-5,94):(-2,7)
=>x=2,3
Vậy x=2,2
-5 . 25 = x . 4 => x : 75
-125 = x . 4 => x : 75
-125 : 4= x => x : 75