1.2+2.4+3.6+4.8+5.10+6.12
3.4+6.8+9.12+12.16+15.20+18.24
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\(\dfrac{1.2+2.4+3.6+4.8+5.10}{3.4+6.8+9.12+12.16+15.20}\)
\(=\dfrac{1.2+2.4+3.6+4.8+5.10}{3.4+3.4.2.2+3.4.3.3+3.4.2.8+3.4.5.5}\)
\(=\dfrac{1.2.\left(4+3^2+2.8+5^2\right)}{3.4.\left(4+3^2+2.8+5^2\right)}\)
\(=\dfrac{1}{6}\)
\(\dfrac{1.2+2.4+3.6+4.8+5.10}{3.4+6.8+9.12+12.16+15.20}\)
\(=\dfrac{1.2+1.2.2^2+1.2.3^2+1.2.4^2+1.2.5^2}{3.4+3.4.2^2+3.4.3^2+3.4.4^2+3.4.5^2}\)
\(=\dfrac{1.2\left(1+2^2+3^2+4^2+5^2\right)}{3.4\left(1+2^2+3^2+4^2+5^2\right)}\\ =\dfrac{2}{12}=\dfrac{1}{6}\)
Ta có:
\(D=\dfrac{1.2+2.4+3.6+4.8+5.10}{3.4+6.8+9.12+12.16+15.20}\\ =\dfrac{1.2+1.2.4+1.2.3.3+1.2.2.8+1.2.5.5}{3.4+3.4.2.2+3.4.3.3+3.4.2.8+3.4.5.5}\\ =\dfrac{1.2\left(4+3^2+2.8+5^2\right)}{3.4\left(2^2+3^2+2.8+5^2\right)}\\ =\dfrac{1.2}{3.4}=\dfrac{1}{6}\)
Vậy \(D=\dfrac{1}{6}\)
= \(\frac{1.2+2.4+3.6+4.8+5.10}{3.2\left(1.2+2.4+3.6+4.8+5.10\right)}=\frac{1}{6}\)
nha :*
Ta có:
\(\frac{1.2+2.4+3.6+4.8+5.10+6.12}{3.4+6.8+9.12+12.16+15.20}\)
\(=\frac{1.2+2\left(1.2\right)+3.\left(1.2\right)+4\left(1.2\right)+5.\left(1.10\right)+6\left(1.2\right)}{3.4+2\left(3.4\right)+3\left(3.4\right)+4\left(3.4\right)+5\left(3.4\right)+6\left(3.4\right)}\)
\(=\frac{\left(1.2\right)\left(1+2+3+4+5+6\right)}{\left(3.4\right)\left(1+2+3+4+5+6\right)}\)
\(=\frac{1.2}{3.4}\)
\(=\frac{1}{6}\)
Ai k mình mình k lại.