giai pt: (-2/x^2-4x+3)+(-2/x^2-4x+15)+........+(-2/x^2-4020x+2009*2011)=(2010/2009)
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=> 3x-(1/2013+2/2012+3/2011)=3x-(4/2010+5/2009+6/2008)=>6x=-4/2010-5/2009-6/2008+1/2013+2/2012+3/2011 =>x=... làm tiếp đi bạn
Bài 2:
Vì a,b là nghiệm PT nên \(\left\{{}\begin{matrix}30a^2-4a=2010\\30b^2-4b=2010\end{matrix}\right.\)
\(\Rightarrow N=\dfrac{a^{2008}\left(30a^2-4a\right)+b^{2008}\left(30b^2-4b\right)}{a^{2008}+b^{2008}}\\ \Rightarrow N=\dfrac{a^{2008}\cdot2010+b^{2008}\cdot2010}{a^{2008}+b^{2008}}=2010\)
Bài 1:
Viét: \(\left\{{}\begin{matrix}x_1+x_2=a\\x_1x_2=a-1\end{matrix}\right.\)
\(M=\dfrac{2x_1^2+x_1x_2+2x_2^2}{x_1^2x_2+x_1x_2^2}=\dfrac{2\left(x_1+x_2\right)^2-3x_1x_2}{x_1x_2\left(x_1+x_2\right)}=\dfrac{2a^2-3a+3}{a^2-a}\)
a) x+2x+3x+4x+...+2011x = 2012.2013
\(\Rightarrow\) x(1+2+3+4+...+2011) = 4050156
\(\Rightarrow\) x.2023066 = 4050156
\(\Rightarrow\) x = 4026/2011
a.|x-1|=3
=>x-1=3 hoặc x-1=-3
=>x=4 hoăc x=-2
vậy...
b.2x+17=15
=>2x=15-17
=>2x=-2
=>x=-1
vậy...
c.tự giải
d.4x-15=-75-x
=>4x+x=-75+15
=>5x=-60
=>x=-12
vậy...
2.2+(-3)+4+...+(-2011)+2012
=(-3+2)+...+(-2011+2010)+2012 (có 2010 cặp)
=-1.2010+2012
=-2010+2012=2
a: =>3,6-x+0,5=3,5-0,75+x
=>4,1-x=x+2,75
=>-2x=-1,35
=>x=0,675
b: =>5x^2-5x+x-1=0
=>(x-1)(5x+1)=0
=>x=1 hoặc x=-1/5
c: \(\Leftrightarrow\left(\dfrac{2-x}{2008}+1\right)=\left(\dfrac{1-x}{2009}+1\right)+\left(1-\dfrac{x}{2010}\right)\)
=>\(2010-x=0\)
=>x=2010
\(x+2x+3x+...+2011x=2012.1013\)
\(\dfrac{2011\left(2011+1\right)}{2}x=2012.2013\)
\(x=2012.2013.\dfrac{2}{2011.2012}\)
\(x=\dfrac{4026}{2011}\)
(2008 x 2009 x 2010 x 2011) x (1 + 1/2 : 3/2 - 4/3)
=(2008 x 2009 x 2010 x 2011) x (1 + 1/3 - 4/3)
=(2008 x 2009 x 2010 x 2011) x (4/3 - 4/3)
=(2008 x 2009 x 2010 x 2011) x 0
=0