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\(E=\frac{1}{25\cdot27}+\frac{1}{27\cdot29}+...+\frac{1}{73\cdot75}\)
\(E=\frac{1}{2}\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+...+\frac{1}{73}-\frac{1}{75}\right)\)
\(\Rightarrow E=\frac{1}{2}\left(\frac{1}{25}-\frac{1}{75}\right)=\frac{1}{2}\cdot\frac{2}{75}=\frac{1}{75}\)
\(F=\frac{15}{90\cdot94}+\frac{15}{94\cdot98}+...+\frac{15}{146\cdot150}\)
\(F=\frac{15}{4}\cdot\left(\frac{1}{90}-\frac{1}{94}+\frac{1}{94}-\frac{1}{98}+...+\frac{1}{146}-\frac{1}{150}\right)\)
\(\Rightarrow F=\frac{15}{4}\cdot\left(\frac{1}{90}-\frac{1}{150}\right)=\frac{15}{4}\cdot\frac{1}{225}=\frac{1}{60}\)
\(G=\frac{10}{56}+\frac{10}{140}+\frac{10}{260}+...+\frac{10}{1400}\)
\(G=\frac{5}{28}+\frac{5}{70}+\frac{5}{130}+...+\frac{5}{700}\)
\(G=\frac{5}{4\cdot7}+\frac{5}{7\cdot10}+\frac{5}{10\cdot13}+...+\frac{5}{25\cdot28}\)
\(G=\frac{5}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{25}-\frac{1}{28}\right)\)
\(\Rightarrow G=\frac{5}{3}\left(\frac{1}{4}-\frac{1}{28}\right)=\frac{5}{3}\cdot\frac{3}{14}=\frac{5}{14}\)
a ) 15 / 90 x 94 + 15 / 94 x 98 + 15 / 98 x102+...+ 15 / 146 x 150
= 15/4 x ( 4/90 x 94 + 4/94 x 98 + ... + 4/ 146 x 150 )
= 15/4 x ( 1/90 - 1/94 + 1/94 - 1/98 + ... + 1/146 - 1/150 )
= 15/4 x ( 1/90 - 1/150 )
= 15/4 x 2/450
= 1/60
b ) 10 / 56 + 10/ 140 + 10 / 260+...+ 10 /1400
= 5/28 + 5/70 + 5/130 + ... + 5/700
= 5/4 x 7 + 5/7 x 10 + 5/10 x 13 + ... + 5 /25 x 28
= 5/3 x ( 3/4 x 7 + 3/7 x 10 + ... + 3/25 x 28 )
= 5/3 x ( 1/4 - 1/7 + 1/7 - 1/10 + ... + 1/25 - 1/28 )
= 5/3 x ( 1/4 - 1/28 )
= 5/3 x 6/28
= 5/14
ngài kiệt lí đây gian lận tuyệt vời.
vĩ đại như nước trong nguồn chảy ra.
a ) 15 / 90 x 94 + 15 / 94 x 98 + 15 / 98 x102+...+ 15 / 146 x 150
= 15/4 x ( 4/90 x 94 + 4/94 x 98 + ... + 4/ 146 x 150 )
= 15/4 x ( 1/90 - 1/94 + 1/94 - 1/98 + ... + 1/146 - 1/150 )
= 15/4 x ( 1/90 - 1/150 )
= 15/4 x 2/450
= 1/60
b ) 10 / 56 + 10/ 140 + 10 / 260+...+ 10 /1400
= 5/28 + 5/70 + 5/130 + ... + 5/700
= 5/4 x 7 + 5/7 x 10 + 5/10 x 13 + ... + 5 /25 x 28
= 5/3 x ( 3/4 x 7 + 3/7 x 10 + ... + 3/25 x 28 )
= 5/3 x ( 1/4 - 1/7 + 1/7 - 1/10 + ... + 1/25 - 1/28 )
= 5/3 x ( 1/4 - 1/28 )
= 5/3 x 6/28
= 5/14
Trịnh Thành Công có copy ở đâu ko mà sao làm(gõ) nhanh quá vậy?
a ) 15 / 90 x 94 + 15 / 94 x 98 + 15 / 98 x102+...+ 15 / 146 x 150
= 15/4 x ( 4/90 x 94 + 4/94 x 98 + ... + 4/ 146 x 150 )
= 15/4 x ( 1/90 - 1/94 + 1/94 - 1/98 + ... + 1/146 - 1/150 )
= 15/4 x ( 1/90 - 1/150 )
= 15/4 x 2/450
= 1/60
b ) 10 / 56 + 10/ 140 + 10 / 260+...+ 10 /1400
= 5/28 + 5/70 + 5/130 + ... + 5/700
= 5/4 x 7 + 5/7 x 10 + 5/10 x 13 + ... + 5 /25 x 28
= 5/3 x ( 3/4 x 7 + 3/7 x 10 + ... + 3/25 x 28 )
= 5/3 x ( 1/4 - 1/7 + 1/7 - 1/10 + ... + 1/25 - 1/28 )
= 5/3 x ( 1/4 - 1/28 )
= 5/3 x 6/28
= 5/14
Tốn công quá !
a ) 15 / 90 x 94 + 15 / 94 x 98 + 15 / 98 x102+...+ 15 / 146 x 150
= 15/4 x ( 4/90 x 94 + 4/94 x 98 + ... + 4/ 146 x 150 )
= 15/4 x ( 1/90 - 1/94 + 1/94 - 1/98 + ... + 1/146 - 1/150 )
= 15/4 x ( 1/90 - 1/150 )
= 15/4 x 2/450
= 1/60
b ) 10 / 56 + 10/ 140 + 10 / 260+...+ 10 /1400
= 5/28 + 5/70 + 5/130 + ... + 5/700
= 5/4 x 7 + 5/7 x 10 + 5/10 x 13 + ... + 5 /25 x 28
= 5/3 x ( 3/4 x 7 + 3/7 x 10 + ... + 3/25 x 28 )
= 5/3 x ( 1/4 - 1/7 + 1/7 - 1/10 + ... + 1/25 - 1/28 )
= 5/3 x ( 1/4 - 1/28 )
= 5/3 x 6/28
= 5/14
\(F=\frac{15}{90.94}+\frac{15}{94.98}+\frac{15}{98.102}+....+\frac{15}{146.150}\)
\(\Rightarrow F=\frac{15}{4}\left(\frac{15}{90}-\frac{15}{94}+\frac{15}{94}-\frac{15}{98}+....+\frac{15}{146}-\frac{15}{150}\right)\)
\(\Rightarrow F=\frac{15}{4}\left(\frac{1}{6}-\frac{1}{10}\right)=\frac{15}{4}\left(\frac{5}{30}-\frac{3}{30}\right)=\frac{15}{4}.\frac{1}{15}=\frac{15}{60}=\frac{1}{4}\)
\(A=\frac{15}{90.94}+\frac{15}{94.98}+...+\frac{15}{146.150}\)
\(A=15\left(\frac{1}{90.94}+\frac{1}{94.98}+...+\frac{1}{146.150}\right)\)
\(A=\frac{15}{4}\left(\frac{1}{90}-\frac{1}{94}+\frac{1}{94}-\frac{1}{98}+...+\frac{1}{146}-\frac{1}{150}\right)\)
\(A=\frac{15}{4}\left(\frac{1}{90}-\frac{1}{150}\right)\)
\(A=\frac{15}{4}.\frac{1}{225}\)
\(A=\frac{1}{60}\)
a) F = \(\frac{1}{25.27}+\frac{1}{27.29}+\frac{1}{29.31}+...+\frac{1}{73.75}\)
F = \(\frac{1}{2}.\left(\frac{1}{25}-\frac{1}{27}\right)+\frac{1}{2}.\left(\frac{1}{27}-\frac{1}{29}\right)+\frac{1}{2}.\left(\frac{1}{29}-\frac{1}{31}\right)+...+\frac{1}{2}.\left(\frac{1}{73}-\frac{1}{75}\right)\)
F = \(\frac{1}{2}.\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)
F = \(\frac{1}{2}.\left(\frac{1}{25}-\frac{1}{75}\right)\)
F = \(\frac{1}{2}.\frac{2}{75}\)
F = \(\frac{1}{75}\)
b) G = \(\frac{15}{90.94}+\frac{15}{94.98}+\frac{15}{98.102}+...+\frac{15}{146.150}\)
G = \(\frac{15}{4}.\frac{4}{90.94}+\frac{15}{4}.\frac{4}{94.98}+\frac{15}{4}.\frac{4}{98.102}+...+\frac{15}{4}.\frac{4}{146.150}\)
G = \(\frac{15}{4}.\left(\frac{1}{90}-\frac{1}{94}\right)+\frac{15}{4}.\left(\frac{1}{94}-\frac{1}{98}\right)+\frac{15}{4}.\left(\frac{1}{98}-\frac{1}{102}\right)+...+\frac{15}{4}.\left(\frac{1}{146}-\frac{1}{150}\right)\)
G = \(\frac{15}{4}.\left(\frac{1}{90}-\frac{1}{94}+\frac{1}{94}-\frac{1}{98}+\frac{1}{98}-\frac{1}{102}+...+\frac{1}{146}-\frac{1}{150}\right)\)
G = \(\frac{15}{4}.\left(\frac{1}{90}-\frac{1}{150}\right)\)
G = \(\frac{15}{4}.\frac{1}{225}\)
G = \(\frac{1}{60}\)
<br class="Apple-interchange-newline"><div id="inner-editor"></div>12.4 +14.6 +...+198.100
=12 (22.4 +24.6 +...+298.100 )
<br class="Apple-interchange-newline"><div id="inner-editor"></div>=12 (12 −14 +14 −16 +...+198 −1100 )
<br class="Apple-interchange-newline"><div id="inner-editor"></div>=12 (12 −14 +14 −16 +...+198 −1100 )
<br class="Apple-interchange-newline"><div id="inner-editor"></div>=12 (12 −1100 )=12 .49100 =49200
1056 +10140 +10260 +...+101400 =53 (
\(\frac{15}{90.94}+\frac{15}{94.98}+\frac{15}{98.102}+...+\frac{15}{146.150}\)
\(=\frac{15}{4}\left(\frac{1}{90}-\frac{1}{94}+\frac{1}{94}-\frac{1}{98}+\frac{1}{98}-\frac{1}{102}+...+\frac{1}{146}-\frac{1}{150}\right)\)
\(=\frac{15}{4}\left(\frac{1}{90}-\frac{1}{150}\right)\)
\(=\frac{15}{4}.\frac{1}{225}\)
\(=\frac{1}{60}\)
\(\frac{15}{90\cdot94}+\frac{15}{94\cdot98}+\frac{15}{98\cdot102}+...+\frac{15}{146\cdot150}\)
\(=\frac{15}{4}\cdot\left(\frac{1}{90}-\frac{1}{94}+\frac{1}{94}-\frac{1}{98}+\frac{1}{98}-\frac{1}{102}+...+\frac{1}{146}-\frac{1}{150}\right)\)
\(=\frac{15}{4}\cdot\left(\frac{1}{90}-\frac{1}{150}\right)\)
\(=\frac{15}{4}\cdot\frac{1}{225}=\frac{1}{60}\)
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