8.3 - ( 110 + 15 ) : 16
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15: \(\Leftrightarrow\left\{x^2-\left[8^2-\left(25-24\right)^3-63\right]^3-48\right\}=1\)
\(\Leftrightarrow x^2-48=1\)
=>x=7 hoặc x=-7
3^4.(4x+16)=8.3^7
đề :
34.(4x+16)=8.37
34.(4x+16)=17496
(4x+16) = 17496 : 34
(4x+16) = 216
4x+16=216
4x = 216 - 16
4x = 200
x = 200 : 4
x = 50
3^4.(4x+16)=8.3^7
đề :
34.(4x+16)=8.37
34.(4x+16)=17496
(4x+16) = 17496 : 34
(4x+16) = 216
4x+16=216
4x = 216 - 16
4x = 200
x = 200 : 4
x = 50
Ta có :
\(\frac{A}{B}=\frac{\left(-2\right)^0+1^{2017}+\left(\frac{-1}{3}\right)^8.3^8}{2^{15}}:\frac{6^2}{2^{16}}\)
=> \(\frac{A}{B}=\frac{1+1+\left(\frac{-1}{3}.3\right)^8}{2^{15}}.\frac{2^{16}}{6^2}\)
=> \(\frac{A}{B}=\frac{1+1+1^8}{1}.\frac{2}{6^2}\)
=> \(\frac{A}{B}=\frac{3}{1}.\frac{2}{2^2.3^2}\)
=> \(\frac{A}{B}=\frac{1}{2.3}=\frac{1}{6}\)
Ta có:
\(\frac{A}{B}\)=\(\frac{\left(-2\right)^0+1^{2017}+\left(\frac{-1}{3}\right)^8\cdot3^8}{2^{15}}\):\(\frac{6^2}{2^{16}}\)
=>\(\frac{A}{B}\)=\(\frac{1+1+\left(\frac{-1}{3}\cdot3\right)^8}{2^{15}}\).\(\frac{2^{16}}{6^2}\)
=>\(\frac{A}{B}\)=\(\frac{1+1+1^8}{2^{15}}\).\(\frac{2^{16}}{6^2}\)
=>\(\frac{A}{B}\)=\(\frac{3}{2^{15}}\).\(\frac{2^{16}}{6^2}\)
=>\(\frac{A}{B}\)=\(\frac{2}{3.2^2}\)
=>\(\frac{A}{B}\)=\(\frac{1}{6}\)
a) 3 2 + − 4 3 = 1 6
1 10 + − 4 5 = − 7 10
Mà 1 6 > − 7 10 nên 3 2 + − 4 3 > 1 10 + − 4 5
b) 1 2 + 1 3 + 1 4 + 1 5 + 1 6 = 29 20 < 2
Nên 1 2 + 1 3 + 1 4 + 1 5 + 1 6 < 2