Câu 2 Câu 3 Câu 4 Câu 5 Câu 6 Câu 7
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\(\frac{12}{1}:\frac{6}{5}+\frac{4}{7}=\frac{60}{6}+\frac{7}{4}=\frac{10}{1}+\frac{7}{4}=\frac{40}{4}+\frac{7}{4}=\frac{47}{4}\)
\(\left(\frac{5}{6}+\frac{3}{4}\right)\cdot\frac{8}{19}=\frac{38}{24}\cdot\frac{18}{9}=\frac{38}{24}\cdot2=\frac{76}{24}=\frac{19}{6}\)
\(\left(\frac{7}{4}-\frac{5}{3}\right)\cdot\frac{2}{3}=\frac{1}{12}\cdot\frac{2}{3}=\frac{1}{13}\)
Câu 1 :
\(\frac{1}{5}:\frac{3}{6}=\frac{1}{5}\times\frac{6}{3}\)
\(=\frac{6}{15}=\frac{2}{5}\)
Câu 2 :
\(\frac{4}{8}+\frac{2}{4}=\frac{1}{2}+\frac{1}{2}\)
\(=1\)
Câu 3 :
\(\frac{2}{5}\times\frac{6}{4}=\frac{12}{20}=\frac{6}{10}\)
Câu 4 :
\(\frac{7}{6}-\frac{2}{3}=\frac{7}{6}-\frac{4}{6}\)
\(=\frac{3}{6}=\frac{1}{2}\)
\(3,=\left(\dfrac{13}{25}-\dfrac{38}{25}\right)+\left(\dfrac{14}{9}-\dfrac{5}{9}\right)=-1+1=0\\ 4,=\left(\dfrac{4}{9}\right)^5\cdot\left(\dfrac{9}{49}\right)^5=\left(\dfrac{4}{9}\cdot\dfrac{9}{49}\right)^5=\left(\dfrac{4}{49}\right)^5\\ 5,\Rightarrow\dfrac{x}{5}=\dfrac{y}{3}=\dfrac{x-y}{5-3}=\dfrac{x+y}{5+3}=\dfrac{2}{2}=\dfrac{x+y}{8}\Rightarrow x+y=8\\ 6,\Rightarrow\left[{}\begin{matrix}x=\sqrt{2}\\x=-\sqrt{2}\end{matrix}\right.\Rightarrow2\text{ giá trị}\\ 7,=\dfrac{3^{10}\cdot2^{30}}{2^9\cdot3^9\cdot2^{20}}=2\cdot3=6\)
\(\frac{1}{3}:x-\frac{2}{3}=\frac{5}{6}+\frac{7}{8}\)
\(\frac{1}{3}:x-\frac{2}{3}=\frac{41}{24}\)
\(\frac{1}{3}:x=\frac{19}{8}\)
\(x=\frac{8}{57}\)
\(\frac{2}{5}-x:\frac{3}{5}=\frac{6}{7}\)
\(x:\frac{3}{5}=\frac{-16}{35}\)
\(x=\frac{-48}{175}\)
\(\frac{4}{5}-\frac{26}{m}=\frac{-8}{15}\)
\(\frac{26}{m}=\frac{4}{3}\)
=> 26 x 3 = m x 4
78 = m x 4
m = 19,5
Câu 1 :\(\frac{1}{3}\div x-\frac{2}{3}=\frac{5}{6}+\frac{7}{8}\)
\(\Leftrightarrow\frac{1}{3x}=\frac{5}{6}+\frac{7}{8}+\frac{2}{3}\)
\(\Leftrightarrow\frac{1}{3x}=\frac{4\cdot5}{24}+\frac{7\cdot3}{24}+\frac{2\cdot8}{24}\)
\(\Leftrightarrow\frac{1}{3x}=\frac{20}{24}+\frac{21}{24}+\frac{16}{24}\)
\(\Leftrightarrow\frac{1}{3x}=\frac{57}{24}\)
\(\Leftrightarrow24=57\cdot3x\)
\(\Leftrightarrow24=171x\)
\(\Leftrightarrow x=\frac{24}{171}=\frac{8}{57}\)
Câu 2: \(\frac{2}{5}-x\div\frac{3}{5}=\frac{6}{7}\)
\(\Leftrightarrow\frac{-5x}{3}=\frac{6}{7}-\frac{2}{5}\)
\(\Leftrightarrow\frac{-5x}{3}=\frac{5\cdot6}{35}-\frac{2\cdot7}{35}\)
\(\Leftrightarrow\frac{-5x}{3}=\frac{30}{35}-\frac{14}{35}\)
\(\Leftrightarrow-\frac{5x}{3}=\frac{16}{35}\)
\(\Leftrightarrow-175x=48\)
\(\Leftrightarrow x=-\frac{48}{175}\)
Câu 3: \(\frac{4}{5}-\frac{26}{m}=-\frac{8}{15}\)
\(\Leftrightarrow\frac{26}{m}=\frac{4}{5}-\left(-\frac{8}{15}\right)\)
\(\Leftrightarrow\frac{26}{m}=\frac{4}{5}+\frac{8}{15}\)
\(\Leftrightarrow\frac{26}{m}=\frac{12}{15}+\frac{8}{15}\)
\(\Leftrightarrow\frac{26}{m}=\frac{20}{15}\)
\(\Leftrightarrow20m=26\cdot15=390\)
\(\Leftrightarrow m=\frac{390}{20}=\frac{39}{2}\)
Câu 1:120a chia hết cho 12
36b chia hết cho 12
=>(120a+36b)chia het cho 12
\(Cau2:\)\(5^7+5^6+5^5\)=\(5^5\left(5^2+5+1\right)=5^5\cdot21\)
=>\(5^7+5^6+5^5chiahetcho21\)
Câu 2.
\(R_{13}=\dfrac{R_1\cdot R_3}{R_1+R_3}=\dfrac{30\cdot60}{30+60}=20\Omega\)
\(R_{tđ}=R_2+R_{13}=45+20=65\Omega\)
\(I_m=\dfrac{U}{R}=\dfrac{130}{65}=2A\)
\(I_{13}=I_m=2A\)
\(U_{13}=U-U_2=U-I_2\cdot R_2=130-2\cdot45=40V\)
\(R_1//R_3\Rightarrow U_1=U_3=U_{13}=40V\)
\(I_3=\dfrac{U_3}{R_3}=\dfrac{40}{60}=\dfrac{2}{3}A\)
Câu 3.
\(R_1//R_2\)
\(\Rightarrow R_{tđ}=\dfrac{R_1\cdot R_2}{R_1+R_2}=\dfrac{10\cdot30}{10+30}=7,5\Omega\)
\(U_1=U_2=U_m=15V\)
\(I_1=\dfrac{U_1}{R_1}=\dfrac{15}{10}=1,5A\)
\(I_2=\dfrac{U_2}{R_2}=\dfrac{15}{30}=0,5A\)
\(I_m=I_1+I_2=1,5+0,5=2A\)