tinh tong:
S=1/1.2+1/2.3+1/3.4+...+1/2011.2012
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=> 3S = 1.2.3 + 2.3.3 + 3.4.3 + .... + 2011.2012.3
=> 3S = 1.2.3 + 2.3.( 4 - 1 ) + 3.4.( 5 - 2 ) + .... + 2011.2012.( 2013 - 2010 )
=> 3S = 1.2.3 + 2.3.4 - 1.2.3 + .... + 2011.2012.2013 - 2010.2011.2012
=> 3S = ( 1.2.3 - 1.2.3 ) + ( 2.3.4 - 2.3.4 ) + .... + ( 2010.2011.2012 - 2010.2011.2012 ) + 2011.2012.2013
=> 3S = 2011.2012.2013
=> S = ( 2011.2012.2013 ) : 3
3S=1.2.3+2.3.(4-1)+...............+2011.2012.(2013-2010)
3S=1.2.3+2.3.4-1.2.3+...............+2011.2012.2013-2010.2011.2012
3S=2011.2012.2013
S=2011.2012.2013:3
S=2714954572
1.50+2.49+3.48+...+49.2+50.1=
= (1.50+2.50+3.50+...+50.1)-(1.2+2.3+3.4+...+49.50)
= (2500+50).50:2-41650
= 63750-41650=22100
2,
A = 1.2 + 2.3 + 3.4 + ... + 2011.2012
3A = 1.2.3 + 2.3.3 + 3.4.3 + ... + 2011.2012.3
3A = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 2011.2012.(2013 - 2010)
3A = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 2011.2012.2013 - 2010.2011.2012
3A = 2011.2012.2013
A = 2011.2012.2013 : 3
A = 2714954572
1/1.2+1/2.3+1/3.4+......+1/99.100
=1-1/2+1/2-1/3+1/3-1/4+..........+1/99-1/100
=1-1/100
=99/100
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}=1-\frac{1}{100}=\frac{99}{100}\)\(\frac{99}{100}\)
Ta có công thức : \(\frac{1}{n}-\frac{1}{n+1}=\frac{1}{n\left(n+1\right)}\)
\(\Rightarrow\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}=\frac{99}{100}\)
\(S=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2011.2012}\)
\(S=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2011}-\frac{1}{2012}\)
\(S=1-\frac{1}{2012}\)
\(S=\frac{2011}{2012}\)
Chúc bạn học tốt nha !!!
=1-1/2+1/2-1/3+1/3-1/4+...+1/2011-1/2012
= 1-1/2012
= 2011/2012