(0.5x - 3/7 ) : 1/2 =\(1\dfrac{1}{7}\)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
bạn làm kiểu này :
0.5x-\(\dfrac{2}{3}\)x=\(\dfrac{7}{6}\)
0-\(\dfrac{2}{3}\)x=\(\dfrac{7}{6}\)
\(\dfrac{2}{3}\)x=0-\(\dfrac{7}{6}\)
0.5x-\(\dfrac{2}{3}\)x=\(\dfrac{7}{6}\)
\(\left(\dfrac{1}{2}-\dfrac{2}{3}\right)\). x=\(\dfrac{7}{6}\)
\(\left(\dfrac{3}{6}-\dfrac{4}{6}\right)\). x=\(\dfrac{7}{6}\)
\(\dfrac{-1}{6}\). x=\(\dfrac{7}{6}\)
x=\(\dfrac{7}{6}\):\(\dfrac{-1}{6}\)
x=\(\dfrac{7}{6}\) . \(\dfrac{6}{-1}\)
x=\(\dfrac{42}{-6}\)
x=\(\dfrac{7}{-1}\)
a: \(\Leftrightarrow x^2+4x+3=x^2+4x+0.5x+2\)
=>0,5x+2=3
=>0,5x=1
hay x=2
b: \(\Leftrightarrow\left|7x-9\right|=5x-3\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=\dfrac{3}{5}\\\left(7x-9-5x+3\right)\left(7x-9+5x-3\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=\dfrac{3}{5}\\\left(2x-6\right)\left(12x-12\right)=0\end{matrix}\right.\Leftrightarrow x\in\left\{3;1\right\}\)
c: =>10x+7>-37 và 10x+7<37
=>10x>-44 và 10x<30
=>-4,4<x<3
a,\(\left(0,5x-\dfrac{3}{7}\right):\dfrac{1}{2}=1\dfrac{1}{7}\)
\(0,5x-\dfrac{3}{7}=\dfrac{4}{7}\)
\(0,5x=1\)
\(x=2\)
b,Đề chưa rõ,bạn viết lại nhé!
c,\(\left(\dfrac{1}{5}-\dfrac{3}{2}x\right)^2=\dfrac{9}{4}\)
\(\dfrac{1}{5}-\dfrac{3}{2}x=\dfrac{3}{2}\)
\(\dfrac{3}{2}x=-\dfrac{13}{10}\)
\(x=-\dfrac{13}{15}\)
1,3x+2/5x+7 =3x-1/5x+1
<=> 1,3x+2/5x-3x+1/5x = 1-7
<=> (1,3+2/5-3+1/5)x = -6
<=> -11/10x=-6
<=> x= -6 : (-11/10)
<=> x= 60/11
2.x+1/2x+1 = 0,5x+2/x +3
<=> 2x+1/2x-0,5x-2/1x = 3-1
<=> x(2+1/2-0,5-2 ) =2
<=>0x =2
<=> x=0
Hinh nhu minh thay ban Kunzy Nguyen giai hoi sai
1,3x o dau ra ???????????????
1) áp dụng tính chất của dãy tỉ số bằng nhau ta có:
\(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}=\frac{\left(3x+2\right)-\left(3x-1\right)}{\left(5x+7\right)-\left(5x+1\right)}=\frac{3x+2-3x+1}{5x+7-5x-1}=\frac{3}{6}=\frac{1}{2}\)
suy ra :
\(\frac{3x-1}{5x+1}=\frac{1}{2}\Rightarrow\left(5x+1\right).1=\left(3x-1\right).2\)
=> 5x+1=6x-2
5x-6x=-2-1
-x=-3
x=3
2)áp dụng tính chất của dãy tỉ số bằng nhau ta có;
\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}=\frac{\left(x+1\right)-2.\left(0,5x+2\right)}{\left(2x+1\right)-2.\left(x+3\right)}=\frac{x+1-x-4}{2x+1-2x-6}=\frac{-3}{-5}=\frac{3}{5}\)
suy ra:
\(\frac{x+1}{2x+1}=\frac{3}{5}\Rightarrow\left(2x+1\right).3=\left(x+1\right).5\)
=>6x+3=5x+5
6x-5x=5-3
x=2
a ) \(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
\(\Leftrightarrow\left(3x+2\right)\left(5x+1\right)=\left(3x-1\right)\left(5x+7\right)\)
\(\Leftrightarrow3x\left(5x+1\right)+2\left(5x+1\right)=3x\left(5x+7\right)-\left(5x+7\right)\)
\(\Leftrightarrow15x^2+3x+10x+2=15x^2+21x-5x-7\)
\(\Leftrightarrow15x^2+13x+2=15x^2+16x-7\)
\(\Leftrightarrow13x+2=16x-7\)
\(\Leftrightarrow13x-16x=-7-2\)
\(\Leftrightarrow-3x=-9\)
\(\Rightarrow x=3\)
b ) tương tự
x+2=-5
x =-7
x2+2x-3=0
(=) x2-x+3x-3=0
(=) x(x-1)+3(x-1)=0
(=) (x-1)(x+3)=0
=> x-1 = 0 hoặc x+3 = 0
x = 1 x =-3
x+4 = 10
x = 6
-3x + 2 =-7
(=) -3x =-9
(=) x = 3
0.5x + 4 = -1
(=) 0.5x =-5
(=) x =-10
Chúc bạn học tốt ^^
a)x+2=-5
\(\Leftrightarrow\)x =-7
b)x2+2x-3=0
\(\Leftrightarrow\)x2-x+3x-3=0
\(\Leftrightarrow\)x(x-1)+3(x-1)=0
\(\Leftrightarrow\)(x+3)(x-1)=0
\(\Rightarrow\)x+3=0 hoặc x-1=0
\(\Rightarrow\)x=-3 hoặc x=1
c)x+4=10
\(\Leftrightarrow\)x=6
d)-3x+2=-7
\(\Leftrightarrow\)-3x =-7-2
\(\Leftrightarrow\)3x =-9
\(\Leftrightarrow\)x =-3
e)0,5x+4=-1
\(\Leftrightarrow\)0,5x =-1-4
\(\Leftrightarrow\)0,5x = -5
\(\Leftrightarrow\)x =-5:0,5
\(\Leftrightarrow\)x =-10
a) 1/2x - 2/3x = 7/12
-1/6x = 7/12
x = \(\frac{7}{12}\div\frac{-1}{6}\)
x = -7/2
b) x: 12 = -2,5
x = -2,5*12
x = -30
c) 11/2x = 13/15
x = 13/15:11/2
x = 26/165
d) 3x/7 + 1 = (-1/28)*(-4)
3x/7 + 1 = 1/7
3x/7 = 1/7 - 1
3x/7 = -6/7
3x = -6
x= -6/3
x= -2
(0,5 . x - 3/7) : 1/2 = 1_1/7
(0,5 . x - 3/7) : 1/2 = 8/7
(0,5 . x - 3/7) = 8/7 . 1/2
(0,5 . x - 3/7) = 4/7
0,5 . x = 4/7 + 3/7
0,5 . x = 1
x = 1 : 0,5
x = 2
\(\Leftrightarrow\dfrac{1}{2}x-\dfrac{3}{7}=\dfrac{8}{7}\cdot\dfrac{1}{2}=\dfrac{4}{7}\\ \Leftrightarrow\dfrac{1}{2}x=1\Leftrightarrow x=2\)