x+1+2+3+4=123 .tìm x
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1. tìm x
kết quả x là : 2010
2. tìm x
a) x = 13
b) x = 6
đúng ko
câu 3 số lớn quá
1.
1(1+2+3+4+....+x)=2021055
1+2+3+4+....+x=2021055:1=2021055
x+(x+1)/1=2021055
=>x(x+1)=1*2021055=2021055=2011*2010 =>x=2010
1) 5^2 . x + 2^4 . x = 123
=> 25 .x + 16 .x = 123
=> x ( 25 + 16 ) = 123
=> x . 41 = 123
=> x = 123 : 41
=> x = 3
b, 3^6 : 3 ^ 3 + 5.x = 57
=> 3^3 + 5.x = 57
=> 27 + 5x = 57
=> 5x = 57 - 27
=> 5x = 30
=> x = 30 : 5
=> x = 6
\(\frac{x+1}{125}+\frac{x+2}{124}+\frac{x+3}{123}+\frac{x+4}{122}+\frac{x+146}{5}=0\)
\(\left(\frac{x+1}{125}+1\right)+\left(\frac{x+2}{124}+1\right)+\left(\frac{x+3}{123}+1\right)+\left(\frac{x+4}{122}+1\right)+\left(\frac{x+146}{5}-4\right)=0\)
\(\frac{x+126}{125}+\frac{x+126}{124}+\frac{x+126}{123}+\frac{x+126}{122}+\frac{x+126}{5}=0\)
\(\left(x+126\right).\left(\frac{1}{125}+\frac{1}{124}+\frac{1}{123}+\frac{1}{122}+\frac{1}{5}\right)=0\)
vì \(\left(\frac{1}{125}+\frac{1}{124}+\frac{1}{123}+\frac{1}{122}+\frac{1}{5}\right)\ne0\)nên x + 126 = 0 \(\Rightarrow\)x = -126
b) 123 - 5.(x+4) = 38
=> 5.(x+4) = 123 - 38
=> 5.(x+4) = 85
=> (x+4) = 85 : 5
=> x+4 = 17
=> x = 17 - 4
=> x = 13
c) 2.x - 138 = 23.32
=>2.x - 138 = 736
=>2.x = 736 + 138
=>2.x = 874
=> x = 874 : 2
=> x = 437
d) 70 - 5.(x-3) = 45
=> 5.(x-3) = 70 - 45
=> 5.(x-3) = 25
=> (x-3) = 25 : 5
=> x-3 = 5
=> x = 5 + 3
=> x = 8
Bài 1:
a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)
b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)
c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)
d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)
hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)
e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)
hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)
tự hỏi tự trả lời ak
x=123-4-3-2-1=113