Tính các tổng sau bằng phương pháp hợp lí nhất:
2/3.5 + 2/5.7+...+2/37.39
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A=1/1-1/2+1/2-1/3+1/3-1/4+....+1/49-1/50
A=1/1-1/50
A=49/50
Vay A=49/50
B=1/3-1/5+1/5-1/7....+1/37-1/39
B=1/3-1/39
b=36/117
B=4/13
Tham khảo :Câu hỏi của hoàng quỳnh dương - Toán lớp 7 - Học toán với OnlineMath
\(B=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{37.39}\)
\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{37}-\frac{1}{39}\)
\(=\frac{1}{3}-\frac{1}{39}\)
\(=\frac{4}{13}\)
Study well ! >_<
\(B=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{37.39}\)
\(B=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+....+\frac{1}{37}-\frac{1}{39}\)
\(B=\frac{1}{3}-\frac{1}{39}=\frac{13}{39}-\frac{1}{39}=\frac{12}{39}\)
\(\frac{2}{3.5}+\frac{2}{5.7}+........+\frac{2}{37.39}\)
\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+......+\frac{1}{37}-\frac{1}{39}\)
\(=\frac{1}{3}-\frac{1}{39}\)
\(=\frac{13}{39}-\frac{1}{39}\)
\(=\frac{12}{39}=\frac{4}{13}\)
ta có A=1/3-1/5+1/5-1/7+1/7-1/9+....+1/37-1/39
=1/3-1/39
=12/39
\(A=\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{49.50}\)
\(A=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{49}-\dfrac{1}{50}\)
\(A=\dfrac{1}{1}-\dfrac{1}{50}=\dfrac{49}{50}\)
\(A=\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{49.50}=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{49}-\dfrac{1}{50}\)
\(A=\dfrac{1}{1}-\dfrac{1}{50}=\dfrac{50}{50}-\dfrac{1}{50}=\dfrac{49}{50}\)
\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{37.39}\)
\(=\frac{5-3}{3.5}+\frac{7-5}{5.7}+...+\frac{39-37}{37.39}\)
\(=\frac{5}{3.5}-\frac{3}{3.5}+\frac{7}{5.7}-\frac{5}{5.7}+...+\frac{39}{37.39}-\frac{37}{37.39}\)
\(=\)\(\frac{2}{3}-\frac{2}{5}+\frac{2}{5}-\frac{2}{7}+...+\frac{2}{37}-\frac{2}{39}\)
\(=\frac{2}{3}-\frac{2}{39}\)
\(=\frac{8}{13}\)
Ta có: 2/3.5=1/3 - 1/5
2/5.7=1/5 - 1/7
........
2/37.39=1/37 - 1/39
2/3.5 + 2/5.7 + ... + 2/37.39=1/3 - 1/5 + 1/5 - 1/7 +..... + 1/37 - 1/39
= 1/3 - 1/39
= 36/117