Tính nhanh : 4/13*5/11+4/13*6/11-4/13
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Những câu hỏi liên quan
HA
1
15 tháng 5 2015
ta có \(\frac{\frac{4}{5}-\frac{4}{11}+\frac{4}{13}}{\frac{9}{5}-\frac{9}{11}+\frac{9}{13}}+\frac{\frac{5}{7}+\frac{5}{11}-\frac{5}{13}}{\frac{9}{7}+\frac{9}{11}-\frac{9}{13}}\)
\(=\frac{4\left(\frac{1}{5}-\frac{1}{11}+\frac{1}{13}\right)}{9\left(\frac{1}{5}-\frac{1}{11}+\frac{1}{13}\right)}+\frac{5\left(\frac{1}{7}+\frac{1}{11}-\frac{1}{13}\right)}{9\left(\frac{1}{7}+\frac{1}{11}-\frac{1}{13}\right)}\)
\(=\frac{4}{9}+\frac{5}{9}=\frac{9}{9}=1\)
24 tháng 3 2021
\(A,\dfrac{7}{11}+\dfrac{5}{6}-\dfrac{-4}{11}-\dfrac{1}{6}\)
\(= (\dfrac{7}{11}+\dfrac{-4}{11})-(\dfrac{5}{6}-\dfrac{1}{6})\)
\(=\dfrac{3}{11}-\dfrac{2}{3}\)
\(= \dfrac{9}{33}-\dfrac{22}{33}\)
\(= \dfrac{-13}{33}\)
\(B,\dfrac{5}{9}.\dfrac{7}{3}+\dfrac{5}{9}.\dfrac{9}{13}-\dfrac{5}{9}:\dfrac{13}{5}\)
\(=(\dfrac{5}{9}.\dfrac{5}{9}:\dfrac{5}{9}).\dfrac{7}{3}+\dfrac{9}{13}-\dfrac{13}{5}\)
\(=(\dfrac{5}{9}.\dfrac{7}{3})+(\dfrac{9}{13}-\dfrac{13}{5})\)
\(=(\dfrac{5}{9}.\dfrac{21}{9})+(\dfrac{45}{65}-\dfrac{169}{65})\)
\(=\dfrac{35}{27}+\dfrac{-124}{65}\)
\(=\dfrac{2275}{1755}+\dfrac{-3348}{1755}\)
\(=\dfrac{-1073}{1755}\)
S
4
N
25 tháng 5 2018
a. 3, 63 + 5, 13 + 6 , 63 + 8, 13 + 9, 63 + 11 , 13
= 8,76 + 6 , 63 + 8, 13 + 9, 63 + 11 , 13
= 15,39 + 8, 13 + 9, 63 + 11 , 13
= 23,52 + 9, 63 + 11 , 13
= 33,15 + 11 , 13
= 44,28
b. 135 , 7 + 20 , 4 + 4 , 6
= 156,1 + 4,6
= 160,7
TT
2
14 tháng 3 2018
8/27+4/5+19/27+11/15=(8/27+19/27) + (4/5+11/15)
= 1+ (12/15+11/15)
= 1+ 1/8/15=2/8/15
12/13+2/7+8/13+6/13+5/7=(12/13+8/13+6/13) + (2/7+5/7)
= 2+ 1
=3
Ý a có thể bạn chép nhầm 4/5 rồi
20 tháng 9 2021
\(=\dfrac{3\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}{13\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{17}+\dfrac{1}{11}\right)}=\dfrac{3}{13}\)
MH
20 tháng 9 2021
\(\dfrac{\dfrac{3}{4}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{11}}{\dfrac{13}{4}-\dfrac{13}{5}+\dfrac{13}{7}+\dfrac{13}{11}}\)
\(=\dfrac{3\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}{13\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}\)
\(=\dfrac{3}{13}\)
= \(\frac{4}{13}.\left(\frac{5}{11}+\frac{6}{11}-1\right)=\frac{4}{13}.\left(\frac{11}{11}-1\right)=\frac{4}{13}.0=0\)