- Tính : 3\2.4\3.5\4.....101\100
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Ta có:
\(\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot...\cdot\frac{99}{98}\cdot\frac{100}{99}=\frac{3\cdot4\cdot5\cdot...99\cdot100}{2\cdot3\cdot4\cdot...\cdot98.99}\)\(=\frac{100}{2}=50\)
Ta có : A = 3/2.4/3.5/4.....99/98.100/99
A= 3.4.5....99.100 / 2.3.4....98.99
A=100/2=50
chúc bạn học tốt nhớ k cho mìn nhé
\(\frac{2^2}{1.3}+\frac{3^2}{2.4}+...+\frac{100^2}{99.101}\\ =\frac{2.2}{1.3}+\frac{3.3}{2.4}+...+\frac{100.100}{99.101}\\ =\frac{2.}{1.}\frac{3.}{2.}\frac{...}{...}\frac{100}{99}+\frac{2.}{3.}\frac{3.}{4.}\frac{...}{...}\frac{100}{101}\\ =\frac{100}{1}+\frac{2}{101}\\ =\frac{10100}{101}+\frac{2}{101}\\ =\frac{10102}{101}\)
\(\frac{2^2}{1.3}+\frac{3^2}{2.4}+\frac{4^2}{3.5}+...+\frac{100^2}{99.101}\)
\(=\frac{2.2}{1.3}+\frac{3.3}{2.4}+\frac{4.4}{3.5}+...+\frac{100.100}{99.101}\)
\(=\frac{2.3.4...100}{1.2.3...99}.\frac{2.3.4...100}{3.4.5...101}\)
\(=100.\frac{2}{101}\)
\(=\frac{200}{101}\)
\(\dfrac{4}{1.3}.\dfrac{9}{2.4}.\dfrac{16}{3.5}.....\dfrac{100}{9.10}\)
\(=\dfrac{2.2}{1.3}.\dfrac{3.3}{2.4}.\dfrac{4.4}{3.5}.....\dfrac{10.10}{9.10}\)
\(=\dfrac{2.3.4.....10}{1.2.3......9}.\dfrac{2.3.4.....10}{3.4.5.....10}\)
\(=10.2\)
\(=20\)
B=1.3+2.4+3.5+...+97.99+98.100B=1.3+2.4+3.5+...+97.99+98.100
B=1(2+1)+2(3+1)+....+97(98+1)+98(99+1)B=1(2+1)+2(3+1)+....+97(98+1)+98(99+1)
B=1.2+1+2.3+2+....+97.98+97+98.99+98B=1.2+1+2.3+2+....+97.98+97+98.99+98
B=(1.2+2.3+3.4+....+97.98+98.99)+(1+2+3+...+98)B=(1.2+2.3+3.4+....+97.98+98.99)+(1+2+3+...+98)
B=98.99.1003+98.992B=98.99.1003+98.992
B=323400+4851=328251B=323400+4851=328251
Số đó=1.3 + 2.4 + 3.5 +....+ 98.100
= 1(2+1) + 2.(3+1) + 3.(4+1) +...+ 98(99+1)
= 1.2 + 1 + 2.3 + 2 + 3.4 + 3+....+ 98.99 +98
= (1.2 + 2.3 + 3.4+....98.99) + (1+2+3+....+98)
=323400 + 4851=328251