| x + 4 | + 12 = 26 ( tìm x )
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5 ngày 14 giờ : 4 = 134 giờ : 4 = 33,5 giờ
Tìm x:
X x 3 - 12 = 26
X x 3 = 26 + 12
X x 3 = 38
X = 38 : 3
X = 12,66
1) 5 ngày 14 giờ : 4
= 134 giờ : 4 = 33,5 giờ
2) \(x\times3-12=26\)
\(x\times3=26+12\)
\(x\times3=38\)
\(x=38\div3\)
\(x=\approx12,67\)
\(x+27=12.4\)
\(\Leftrightarrow x+27=48\)
\(\Leftrightarrow x=48-27\)
\(\Leftrightarrow x=21\)
\(3x-4=26\)
\(\Leftrightarrow3x=26+4\)
\(\Leftrightarrow3x=30\)
\(\Leftrightarrow x=30:3\)
\(\Leftrightarrow x=10\)
\(\frac{12}{26}=\frac{-x}{4}=\frac{21}{y}=\frac{z}{180}\)
\(\Rightarrow\frac{12}{26}=\frac{-x}{4}\Leftrightarrow-x.26=48\Leftrightarrow x=\frac{-24}{13}\)
\(\Rightarrow\frac{12}{26}=\frac{21}{y}\Leftrightarrow12.y=546\Leftrightarrow y=\frac{91}{2}\)
\(\Rightarrow\frac{12}{26}=\frac{z}{180}\Leftrightarrow z.26=2160\Leftrightarrow z=\frac{1080}{13}\)
Vậy : ...
chúc bạn học tốt
\(1,\Leftrightarrow7x=42\Leftrightarrow x=6\\ 2,\Leftrightarrow36-4x=4\Leftrightarrow4x=32\Leftrightarrow x=8\\ 3,\Leftrightarrow3x=35\Leftrightarrow x=\dfrac{35}{3}\\ 4,\Leftrightarrow x-12=144\Leftrightarrow x=156\\ 5,\Leftrightarrow x-14=16\Leftrightarrow x=30\\ 6,\Leftrightarrow3x-24=\dfrac{148}{73}\Leftrightarrow3x=\dfrac{1900}{73}\Leftrightarrow x=\dfrac{1900}{219}\\ 7,\Leftrightarrow33+x=45\Leftrightarrow x=12\\ 8,Sai.đề\\ 9,\Leftrightarrow\left(x+9\right):2=39\Leftrightarrow x+9=78\Leftrightarrow x=69\\ 11,\Leftrightarrow2\left(x+7\right)=38\Leftrightarrow x+7=19\Leftrightarrow x=12\\ 13,\Leftrightarrow2\left(x-51\right)=66\Leftrightarrow x-51=33\Leftrightarrow x=84\)
\(15,\Leftrightarrow x-19=9\Leftrightarrow x=28\\ 17,\Leftrightarrow\left(x-3\right):2=48\Leftrightarrow x-3=96\Leftrightarrow x=99\\ 19,\Leftrightarrow0x=46\Leftrightarrow x\in\varnothing\\ 8,Sai.đề\\ 14,\Leftrightarrow2x=209\Leftrightarrow x=\dfrac{209}{2}\\ 16,\Leftrightarrow2x+6=157\Leftrightarrow2x=151\Leftrightarrow x=\dfrac{151}{2}\\ 18,\Leftrightarrow5\left(x+4\right)=100\Leftrightarrow x+4=20\Leftrightarrow x=16\\ 20,\Leftrightarrow\left(3x-5\right)^3=27=3^3\Leftrightarrow3x-5=3\Leftrightarrow x=\dfrac{8}{3}\)
=> \(|x+4|\) = 14
=> \(\left[{}\begin{matrix}x=10\\x=-18\end{matrix}\right.\)
Vậy \(\left[{}\begin{matrix}x=10\\x=-18\end{matrix}\right.\)
TH1: Nếu x+4\(\ge0\) thì ta được:
\(\left|x+4\right|+12=26\) \(\Leftrightarrow x+4+12=26\Leftrightarrow x+16=26\Leftrightarrow x=26-16=10\)
TH2: Nếu x+4\(< 0\) thì ta được:
\(\left|x+4\right|+12=26\) \(\Leftrightarrow x-4+12=26\Leftrightarrow x+8=26\Leftrightarrow x=26-8=18\)
Vậy ....