23 : x + 1
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1. Tính:
a) 23 + 24 - ( 65 x 2 - 4 ) x 4 + 66 + 44 - ( 54 : 9 x 9 : 9 + 45 ) : 1 + 1 - 1 x ( 23 + 23 - 23 x 2 +1 ) = 51
b) 4444444444444444444444444444444444444444444444444444444444444444444 : 1
= 4444444444444444444444444444444444444444444444444444444444444444444
c) 30 = 0
d) 1/1 = 1
e)
a) - 530
b) 44444444444444444444444444444444444444444444444444444444444444444444
c) 0
d) 1
e) Em là em
\(a.415\times7-415\times5+415\times8\)
\(=415\times\left(7-5+8\right)=415\times10=4150\)
\(b.23\times87+12\times23+23\)
\(=23\times\left(87+12+1\right)=23\times100=2300\)
a. 415 x 7 - 415 x 5 + 4 15 x 8
= 415 x ( 7 - 5 + 8 )
= 415 x 10
= 41 50
b. 23 x 87 + 1 2 x 23 + 2 3
= 23x 87 + 12 x 23 + 23 x 1
= 23 x ( 87 + 12 + 1 )
= 23 x 100
= 2300
=
a) 415 x 7 - 415 x 5 + 415 x 8
= 415 x (7 - 5 + 8)
= 415 x 10
= 4150
b) 23 x 87 + 12 x 23 + 23
= 23 x 87 + 12 x 23 + 23 x 1
= 23 x (87 + 12 + 1)
= 23 x 100
= 2300
`(1/(1.3)+1/(3.5)+.......+1/(23.25))xx((x+1)+(x+3)+(x+5)+.....+(x+23))=144`
`(2/(1.3)+2/(3.5)+.......+2/(23.25))xx[(x+x+....+x)+(1+3+5+...+23)]=288`
`(1-1/3+1/3-1/5+.....+1/23-1/25)xx(12x+(24.12)/2)=288`
`(1-1/25)xx(12x+12.12)=288`
`24/25xx[12(x+12)]=288`
`24/25xx(x+12)=28`
`x+12=28:24/25=50`
`x=50-12=38`
Vậy `x=38`