(2010x162-324x1005)-(5+10+15+.................+50
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(√10−√15+3√3)√5−√72(10−15+33)5−72
=√15−√15+15−6√2=15−15+15−62
\(=\)15−6√2
(15√50+5√200−3√450)8√10(1550+5200−3450)810
=(15.5√2+5.10√2−3.15√2)8√10=(15.52+5.102−3.152)810
=
a: \(\dfrac{-7}{15}=\dfrac{-7\cdot4}{15\cdot4}=\dfrac{-28}{60}\)
\(\dfrac{5}{12}=\dfrac{5\cdot5}{12\cdot5}=\dfrac{25}{60}\)
b: \(\dfrac{1}{5}=\dfrac{1\cdot6}{5\cdot6}=\dfrac{6}{30}\)
\(\dfrac{-2}{3}=\dfrac{-2\cdot10}{3\cdot10}=\dfrac{-20}{30}\)
\(\dfrac{7}{10}=\dfrac{7\cdot3}{10\cdot3}=\dfrac{21}{30}\)
c: \(\dfrac{-15}{50}=\dfrac{-15\cdot3}{50\cdot3}=\dfrac{-45}{150}\)
\(\dfrac{9}{10}=\dfrac{9\cdot15}{10\cdot15}=\dfrac{135}{150}\)
\(\dfrac{26}{-30}=\dfrac{-26}{30}=\dfrac{-26\cdot5}{30\cdot5}=\dfrac{-130}{150}\)
d: \(\dfrac{7}{10}=\dfrac{7\cdot51}{10\cdot51}=\dfrac{357}{510}\)
\(\dfrac{-5}{-15}=\dfrac{1}{3}=\dfrac{1\cdot170}{3\cdot170}=\dfrac{170}{510}\)
\(\dfrac{3}{17}=\dfrac{3\cdot30}{17\cdot30}=\dfrac{90}{510}\)
e: \(\dfrac{-4}{-75}=\dfrac{4}{75}=\dfrac{4}{75}\)
\(\dfrac{-3}{5}=\dfrac{-3\cdot15}{5\cdot15}=\dfrac{-45}{75}\)
\(\dfrac{8}{25}=\dfrac{8\cdot3}{25\cdot3}=\dfrac{24}{75}\)
f: \(-\dfrac{4}{5}=\dfrac{-4\cdot7}{5\cdot7}=\dfrac{-28}{35}\)
\(\dfrac{6}{7}=\dfrac{6\cdot5}{7\cdot5}=\dfrac{30}{35}\)
3 x 15 + 21 x 15 + 85 x 5
= 45 + 315 + 425
= 785
15 - 30 + 40
= 25
21 + 19 - 50 + 10
= 0
\(\dfrac{1}{5}-\dfrac{1}{4}+2\)
\(=-\dfrac{1}{20}+2\)
\(=\dfrac{39}{20}\)
\(\left(\dfrac{1}{4}+\dfrac{1}{6}\right)\times\left(\dfrac{1}{2}-\dfrac{1}{4}\right)\)
\(=\dfrac{5}{12}\times\dfrac{1}{4}\)
\(=\dfrac{5}{12}\times\dfrac{3}{12}\)
\(=\dfrac{5}{48}\)
\(\dfrac{1}{10}+\dfrac{1}{5}-\dfrac{3}{4}\)
\(=-\dfrac{9}{20}\)
\(3\times15+21\times15+85\times5\\ =15\times\left(3+21\right)+425\\ =15\times24+425\\ =360+425\\ =785\)
\(15-30+40\\ =\left(15+40\right)-30\\ =55-30\\ =25\)
\(21+19-50+10\\ =\left(21+19\right)-\left(50-10\right)\\ =40-40\\ =0\)
\(\dfrac{1}{5}-\dfrac{1}{4}+2\)
\(=\dfrac{4}{20}-\dfrac{5}{20}+\dfrac{40}{20}\)
\(=\dfrac{\left(4+40\right)}{20}-\dfrac{5}{20}\)
\(=\dfrac{44}{20}-\dfrac{5}{20}\)
\(=\dfrac{39}{20}\)
\(\left(\dfrac{1}{4}+\dfrac{1}{6}\right)\times\left(\dfrac{1}{2}-\dfrac{1}{4}\right)\)
\(=\dfrac{5}{12}\times\dfrac{1}{4}\)
\(=\dfrac{5}{48}\)
\(\dfrac{1}{10}+\dfrac{1}{5}-\dfrac{3}{4}\)
\(=\dfrac{2}{20}+\dfrac{4}{20}-\dfrac{15}{20}\)
\(=\dfrac{6}{20}-\dfrac{15}{20}\)
\(=-\dfrac{9}{20}\)
mình nghĩ là đáp án :A.13/20 ,14/20 , 15/20
nha bn hoặc bn có thể chọn đáp án B
10(81+19)+100+50(91+9)
=10.100+100+50.100
=1000+100+5000
=6100
=14.5.35+10.5.5.7+4.5.7
=70.35+50.35+4.35
=35.(70+50+4)
=35.124
=4340
15 : 5 = 3 15 : 3 = 5 35 : 5 = 7 |
10 : 5 = 2 25 : 5 = 5 5 : 5 = 1 |
40 : 5 = 8 45 : 5 = 9 50 : 5 = 10 |
30 : 5 = 6 20 : 5 = 4 20 : 4 = 5 |
15 : 5 = 3 15 : 3 = 5 35 : 5 = 7 | 10 : 5 = 2 25 : 5 = 5 5 : 5 = 1 |
40 : 5 = 8 45 : 5 = 9 50 : 5 = 10 | 30 : 5 = 6 20 : 5 = 4 20 : 4 = 5 |
Phương pháp giải:
Nhẩm bảng chia 55 rồi điền kết quả vào chỗ trống.
Lời giải chi tiết:
5 : 5=1 | 20 : 5=4 | 40 : 5=8 |
45 : 5=9 | 10 : 5=2 | 25 : 5=5 |
50 : 5=10 | 30 : 5=6 | 15 : 5=3 |
\(B=\frac{10}{5}+\frac{20}{10}+\frac{30}{15}+...+\frac{100}{50}\)
\(B=2+2+2+...+2\)
Số số hạng có là : ( 100 - 10) : 10 + 1 = 10
\(B=10\cdot2=20\)
kết quả là âm -275 nha bạn
duyệt đi