17- 9 =
19- 8 =
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Phương pháp giải:
- Tính giá trị của mỗi vế
- So sánh rồi điền dấu thích hợp vào chỗ trống.
Lời giải chi tiết:
19 + 7 < 19 + 9 17 + 7 < 17 + 9
17 + 9 = 19 + 7 37 + 15 < 55 − 1
38 − 8 = 23 + 7 28 − 3 > 17 + 6
Phương pháp giải:
- Tính giá trị của mỗi vế.
- So sánh rồi điền dấu thích hợp vào chỗ trống.
Lời giải chi tiết:
8 + 5 > 8 + 4
8 + 5 < 8 + 6
18 + 10 > 17 + 10
8 + 9 = 9 + 8
18 + 9 = 19 + 8
18 + 8 < 19 + 9
\(C=\dfrac{4}{9}\times\dfrac{13}{17}+\dfrac{4}{17}\times\dfrac{4}{9}+\dfrac{2}{9}\\ =\dfrac{4}{9}\times\left(\dfrac{13}{17}+\dfrac{4}{17}\right)+\dfrac{2}{9}\\ =\dfrac{4}{9}\times1+\dfrac{2}{9}\\ =\dfrac{4}{9}+\dfrac{2}{9}\\ =\dfrac{6}{9}=\dfrac{2}{3}\)
\(D=\dfrac{8}{19}\times\dfrac{5}{11}+\dfrac{7}{11}\times\dfrac{8}{19}+\dfrac{12}{11}\times\dfrac{11}{19}\\ =\dfrac{8}{19}\times\left(\dfrac{5}{11}+\dfrac{7}{11}\right)+\dfrac{12}{11}\times\dfrac{11}{19}\\ =\dfrac{8}{19}\times\dfrac{12}{11}+\dfrac{12}{11}\times\dfrac{11}{19}\\ =\dfrac{12}{11}\times\left(\dfrac{8}{19}+\dfrac{11}{19}\right)\\ =\dfrac{12}{11}\times19\\ =\dfrac{12}{11}\)
\(C=\dfrac{4}{9}\cdot\dfrac{13}{17}+\dfrac{4}{17}\cdot\dfrac{4}{9}+\dfrac{2}{9}\)
\(C=\dfrac{4}{9}\cdot\left(\dfrac{13}{17}+\dfrac{4}{17}\right)+\dfrac{2}{9}\)
\(C=\dfrac{4}{9}\cdot\dfrac{13+4}{17}+\dfrac{2}{9}\)
\(C=\dfrac{4}{9}\cdot\dfrac{17}{17}+\dfrac{9}{2}\)
\(C=\dfrac{4}{9}\cdot1+\dfrac{2}{9}\)
\(C=\dfrac{4}{9}+\dfrac{2}{9}\)
\(C=\dfrac{4+2}{9}\)
\(C=\dfrac{6}{9}\)
\(C=\dfrac{2}{3}\)
\(D=\dfrac{8}{19}\cdot\dfrac{5}{11}+\dfrac{7}{11}\cdot\dfrac{8}{19}+\dfrac{12}{11}\cdot\dfrac{11}{19}\)
\(D=\dfrac{8}{19}\cdot\left(\dfrac{5}{11}+\dfrac{7}{11}\right)+\dfrac{12}{11}\cdot\dfrac{11}{19}\)
\(D=\dfrac{8}{19}\cdot\dfrac{12}{11}+\dfrac{12}{11}\cdot\dfrac{11}{19}\)
\(D=\dfrac{12}{11}\cdot\left(\dfrac{8}{19}+\dfrac{11}{19}\right)\)
\(D=\dfrac{12}{11}\cdot\dfrac{19}{19}\)
\(D=\dfrac{12}{11}\cdot1\)
\(D=\dfrac{12}{11}\)
a: \(=\dfrac{8}{9}\cdot\dfrac{9}{4}\cdot\dfrac{12}{19}\cdot\dfrac{19}{24}=\dfrac{1}{2}\cdot2=1\)
b: \(=\dfrac{5}{16}\cdot\dfrac{17}{15}\cdot\dfrac{8}{17}=\dfrac{5}{16}\cdot\dfrac{8}{15}=\dfrac{40}{240}=\dfrac{1}{6}\)
c: \(=\dfrac{4}{13}\left(\dfrac{2}{7}+\dfrac{5}{7}\right)-\dfrac{3}{26}=\dfrac{4}{13}-\dfrac{3}{26}=\dfrac{5}{26}\)
c: \(=\dfrac{3}{4}\left(\dfrac{6}{11}+\dfrac{5}{11}\right)-\dfrac{1}{5}=\dfrac{3}{4}-\dfrac{1}{5}=\dfrac{11}{20}\)
a) 19 +7 = 17 + 9
b) 23 + 7 = 38 - 8
c) 17 + 9 > 17 +7
d) 16 + 8 < 28 – 3
a: =35/17-18/17-9/5+4/5
=1-1=0
b: =-7/19(3/17+8/11-1)
=7/19*18/187=126/3553
c: =26/15-11/15-17/3-6/13
=1-6/13-17/3
=7/13-17/3=-200/39
\(\left(\frac{9}{15}+\frac{8}{11}\right)+\frac{6}{15}=\left(\frac{9}{15}+\frac{6}{15}\right)+\frac{8}{11}\)
\(=1+\frac{8}{11}=\frac{19}{11}\)
\(\left(\frac{26}{17}+\frac{15}{34}\right)+\left(\frac{8}{17}+\frac{19}{34}\right)=\left(\frac{26}{17}+\frac{8}{17}\right)+\left(\frac{15}{34}+\frac{19}{34}\right)\)
\(=2+1=3\)
\(\left(\frac{9}{15}+\frac{8}{11}\right)+\frac{6}{15}\)
\(=\left(\frac{9}{15}+\frac{6}{15}\right)+\frac{8}{11}\)
\(=1+\frac{8}{11}\)
\(=\frac{19}{11}\)
\(\left(\frac{26}{17}+\frac{15}{34}\right)+\left(\frac{8}{17}+\frac{19}{34}\right)\)
\(=\frac{26}{17}+\frac{15}{34}+\frac{8}{17}+\frac{19}{34}\)
\(=\left(\frac{26}{17}+\frac{8}{17}\right)+\left(\frac{15}{34}+\frac{19}{34}\right)\)
\(=2+1\)
\(=3\)
(9 x 7 + 8 x 9 - 15 x 9) : (1 + 3 + 5 + 7 + ... + 17 + 19)
= 9 x (7 + 8 - 15) : (1 + 3 + 5 + 7 + ... + 17 + 19)
= 9 x 0 : (1 + 3 + 5 + 7 + ... + 17 + 19)
= 0
(9 x 7 + 8 x 9 - 15 x 9) : (1 + 3 + 5 + 7 + ... + 17 + 19)
= 9 x (7 + 8 - 15) : (1 + 3 + 5 + 7 + ... + 17 + 19)
= 9 x 0 : (1 + 3 + 5 + 7 + ... + 17 + 19)
= 0
`#lv`
`A=(-1)+(-5)+(-9)+...+(-101)`
`=-(1+5+9+...+101)`
Số số hạng là :
`[101-(-1)]:4+1=26(` số hạng `)`
Tổng là :
`[(-101)+(-1)]xx26:2=-1326`
Vậy `A=-1326`
__
`B=-5/17 . 8/19 + (-12)/17 . 8/19 - 11/19`
`=((-5)/17+(-12)/17).8/19-11/19`
`=-1.8/19-11/19`
`=-8/19-11/19`
`=-8/19+(-11)/19`
`=-19/19`
`=-1`
__
`C=10/1.6 + 10/6.11 + 10/11.16 + ... + 10/2016.2021`
`=2.(1-1/6+1/6-1/11+...+1/2016-1/2021)`
`=2(1-1/2021)`
`=2. (2021/2021-1/2021)`
`=2. 2020/2021`
`=4040/2021`
DE THE EM 17-9=8 19-8=11
17 - 9 = 8
19 - 8 = 11