x/16=y/12=75/100
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\(=\frac{7}{5}-\frac{27}{12}+\frac{3}{5}+\frac{2}{3}+\frac{1}{3}-\frac{3}{4}\)
\(=\frac{7}{5}+\frac{3}{5}+\frac{2}{3}+\frac{1}{3}-\frac{27}{12}-\frac{9}{12}\)
\(=2+1-3=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(12:\dfrac{3}{4}+75\%\cdot\dfrac{1}{2}-16\cdot50\%\)
\(=12\cdot\dfrac{4}{3}+\dfrac{3}{4}\cdot\dfrac{1}{2}-16\cdot0,5\)
\(=16-8+\dfrac{3}{8}\)
\(=8,375\)
b: \(75\%\cdot4+22,5:3-1\dfrac{3}{5}\)
\(=0,75\cdot4+7,5-1,6\)
\(=3+7,5-1,6\)
=10,5-1,6
=8,9
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1 bạn tự là nhé dễ lắm :))
Bài 2 :
Ta có :
\(4x-15=-75-x\)
\(\Leftrightarrow\)\(4x+x=-75+15\)
\(\Leftrightarrow\)\(5x=-60\)
\(\Leftrightarrow\)\(x=\frac{-60}{5}\)
\(\Leftrightarrow\)\(x=-12\)
Bài 3 :
Ta có :
\(12⋮\left(x-3\right)\)\(\Rightarrow\)\(\left(x-3\right)\inƯ\left(12\right)\)
Mà \(Ư\left(12\right)=\left\{1;-1;2;-2;3;-3;4;-4;6;-6;12;-12\right\}\)
Suy ra : ( lập bảng )
\(x-3\) | \(1\) | \(-1\) | \(2\) | \(-2\) | \(3\) | \(-3\) | \(4\) | \(-4\) | \(6\) | \(-6\) | \(12\) | \(-12\) |
\(x\) | \(4\) | \(2\) | \(5\) | \(1\) | \(6\) | \(0\) | \(7\) | \(-1\) | \(9\) | \(-3\) | \(15\) | \(-9\) |
Vậy \(x\in\left\{4;2;5;1;6;0;7;-1;9;-3;15;-9\right\}\)
Chúc bạn học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left\{{}\begin{matrix}x+y=1500\\x+\dfrac{75}{100}x+y+\dfrac{68}{100}y=2583\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x+y=1500\\\left(x+y\right)+\dfrac{3}{4}x+\dfrac{17}{25}y=2583\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x+y=1500\\1500+\dfrac{3}{4}x+\dfrac{17}{25}y=2583\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x+y=1500\\\dfrac{3}{4}x+\dfrac{17}{25}y=1083\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=900\\y=600\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
ĐKXĐ: \(x\ge-15\)
Ta có: \(\sqrt{16\left(x-1\right)^2}=2x+\sqrt{12}\cdot\sqrt{75}\)
\(\Leftrightarrow\sqrt{\left[4\left(x-1\right)\right]^2}=2x+30\)
\(\Leftrightarrow\left|4x-4\right|=2x+30\)
\(\Leftrightarrow\left[{}\begin{matrix}4x-4=2x+30\\4x-4=-2x-30\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x-4-2x-30=0\\4x-4+2x+30=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x-34=0\\6x+26=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}2x=34\\6x=-26\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=17\left(nhận\right)\\x=-\frac{26}{6}\left(nhận\right)\end{matrix}\right.\)
Vậy: \(x\in\left\{17;\frac{-26}{6}\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{8\times3\times4}{16\times3}=\dfrac{8\times3\times2\times2}{2\times8\times3}=2.\\ \dfrac{30\times25\times7\times8}{75\times8\times12\times14}=\dfrac{5\times2\times3\times5\times5\times7\times8}{3\times5\times5\times8\times2\times2\times3\times2\times7}=\dfrac{5}{12}.\)
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