Tính hợp lí :
a) 5 x 6 x 20 - 30 x 14 b) 9x 350 x 2 – 6 x 50 x 3 – 200 x 18
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Hướng dẫn giải:
a) 3 x (20 – 5)
Cách 1:
3 x (20 – 5) = 3 x 15 = 45
Cách 2:
3 x (20 – 5) = 3 x 20 – 3 x 5 = 60 – 15 = 45
b) 20 x (40 – 1)
Cách 1:
20 x (40 – 1) = 20 x 39 = 780
Cách 2:
20 x (40 – 1) = 20 x 40 – 20 x 1 = 800 – 20 = 780
a)
= 25 x 4 x 7 x 9
= 100 x 63
= 6300
b)
= 2 x 50 x 47 x 10
= 100 x 470
= 47000
c)
= 20 x 5 x 9 x 6
= 100 x 54
= 5400
a) 350 - 6(x - 2) = 230
6(x - 2) = 350 - 230
6(x - 2) = 120
x - 2 = 120 : 6
x - 2 = 20
x = 20 + 2
x = 22
Câu 1:
a) 25-(30+x) = x-(27-8)
25-30-x = x-19
-5-x = x-19
(-5)+19 = x+x
14 = 2x
x = 7
Vậy x = 7
b) (x-12)-15 = (20-7)-(18+x)
x-12-15 = 13-18-x
x-(12+15)= -5-x
x-27 = -5-x
x+x = -5+27
2x = 22
x = 11
Câu 2:
a) 4573+46-4573+35-16-5
= (4573-4573)+(46-16)+(35-5)
= 0+30+30
= 60
b) 32+34+36+38-10-12-14-16-18
= (32-12)+(34-14)+(36-16)+(38-18)-10
= 10+10+10+10-10
= 30
1, a) 25 - (30 + x) = x - (27 - 8)
25 - 30 - x = x - 27 + 8
-x - x = -27 + 8 - 25 + 30
-2x = -14
x = -14 : (-2)
x = 7
b) (x - 12) - 15 = (20 - 7) - (18 + x)
x - 12 - 15 = 20 - 7 - 18 - x
x + x = 20 - 7 - 18 + 12 + 15
2x = 22
x = 22 : 2
x = 11
2, a) 4573 + 46 - 4573 + 35 - 16 - 5
= (4573 - 4573) + (46 - 16) + (35 - 5)
= 0 + 30 + 30
= 60
b) 32 + 34 + 36 + 38 - 10 - 12 - 14 - 16 - 18
= (32 - 10) + (34 - 12) + (36 - 14) + (38 - 16) - 18
= 22 + 22 + 22 + 22 - 18
= 22 x 4 - 18
= 88 - 18
= 70
a) Ta có: \(2\sqrt{9x-27}-\dfrac{1}{5}\sqrt{25x-75}-\dfrac{1}{7}\sqrt{49x-147}=20\)
\(\Leftrightarrow6\sqrt{x-3}-\sqrt{x-3}-\sqrt{x-3}=20\)
\(\Leftrightarrow4\sqrt{x-3}=20\)
\(\Leftrightarrow x-3=25\)
hay x=28
b) Ta có: \(\sqrt{9x+18}-5\sqrt{x+2}+\dfrac{4}{5}\sqrt{25x+50}=6\)
\(\Leftrightarrow3\sqrt{x+2}-5\sqrt{x+2}+4\sqrt{x+2}=6\)
\(\Leftrightarrow2\sqrt{x+2}=6\)
\(\Leftrightarrow x+2=9\)
hay x=7
a) \(\dfrac{27}{2}\cdot7,5+\dfrac{27}{2}\cdot2,5-150\)
\(=\dfrac{27}{2}\cdot\left(7,5+2,5\right)-150\)
\(=\dfrac{27}{2}\cdot10-150\)
\(=135-150\)
\(=-15\)
b) \(3^3\cdot\dfrac{18}{5}-3^3\cdot2\dfrac{2}{5}-3^3\cdot\dfrac{6}{5}\)
\(=3^3\cdot\dfrac{18}{5}-3^3\cdot\dfrac{12}{5}-3^3\cdot\dfrac{6}{5}\)
\(=3^3\cdot\left(\dfrac{18}{5}-\dfrac{12}{5}-\dfrac{6}{5}\right)\)
\(=3^3\cdot\left(\dfrac{18}{5}-\dfrac{18}{5}\right)\)
\(=3^3\cdot0\)
\(=0\)
a) x2 + 5x + 6
= x2 + 2x + 3x + 6
= (x2 + 2x) + (3x + 6)
= x(x + 2) + 3 (x + 2)
= (x + 2) (x + 3)
b) x2 + 6x + 8
= x2 + 2x + 4x + 8
= (x2 + 2x) + (4x + 8)
= x(x + 2) + 4(x + 2)
= (x + 2)(x + 4)
c) x2 - 5x - 14
= x2 + 2x - 7x - 14
= (x2 + 2x) - (7x + 14)
= x(x + 2) - 7(x + 2)
= (x + 2)(x - 7)
d) x2 - 9x + 18
= x2 - 3x - 6x + 18
= (x2 - 3x) - (6x + 18)
= x(x - 3) - 6 (x - 3)
= (x - 3)(x - 6)
e) x2 - 7x + 12
= x2 -3x - 4x + 12
= (x2 - 3x) - (4x + 12)
= x(x - 3) - 4(x - 3)
= (x - 3)(x - 4)
f) 3x2 + 9x - 30
= 3(x2 + 3x - 10)
= 3\(\left[\left(x^2+5x-2x-10\right)\right]\)
= 3\(\left[\left(x^2+5x\right)-\left(2x-10\right)\right]\)
= 3\(\left[x\left(x+5\right)-2\left(x+5\right)\right]\)
= 3(x + 5)(x - 2)
Chuc ban hoc tot
a) \(x^2+5x+6=\left(x+2\right)\left(x+3\right)\)
b) \(x^2+6x+8=\left(x+2\right)\left(x+4\right)\)
c) \(x^2-5x-14=\left(x-7\right)\left(x+2\right)\)
d) \(x^2-9x+18=\left(x-3\right)\left(x-6\right)\)
e) \(x^2-7x+12=\left(x-3\right)\left(x-4\right)\)
f) \(3x^2+9x-30=3\left(x^2+3x-10\right)=3\left(x+5\right)\left(x-2\right)\)
B2:tìm x biết
1)x+18=6-2x
<=> 3x=-12
<=> x= -4
2)17-x=7-6x
<=>5x=-10
<=>x=-2
3)x+15=20-4x
<=>5x=5
<=>x=1
4)7x-4=20+3x
<=> 4x=24
<=>x=6
5)-12+x=5x-20
<=>4x=8
<=>x=2
6)4x-18=x+27
<=>3x=45
<=>x=9
7) 2.(x-5)-3.(x+7)=14
<=>2x-10-3x-21=14
<=>-x=14+10+21=45
<=>x=-45
8)5.(x-6)-2.(x+3)=12
<=>5x-30-2x-6=12
<=>3x=48
<=>x=12
9)-7.(5-x)-2.(x-10)=15
<=>-35+7x-2x+20=15
<=>5x=30
<=>x=6
10)3. ( x - 4 ) - ( 8 - x )=12
<=>3x-12-8+x=12
<=>4x=32
<=>x=8
11)4.(x-5)-(x+7)=-19
<=>4x-20-x-7=-19
<=>3x=8
<=>x=8/3
12)7.(x-3)-5.(3-x)=11x-5
<=>7x-21-15+5x=11x-5
<=>x=31
b1:bỏ ngoặc rồi tinh hợp lí
1) -( -66)+34+(-73)-27+99=66+34-73-27+99 =100-100+99=99
2)54-(45-30+54)-30+5=54-45+30-54-30+5=-45+5=-40
3)42-56+33-(33-56+42)=42-56+33-33+56-42=0
4)50-(47+50-18)+(47-18)=50-47-50+18+47-18=0
5) |25-24-10|-(28-30+4)=9-28+30-4=39-32=7
6)-(-73)+(44-94+27)+94=73+44-94+27+94=100+44=144
7) (-33+180-75)-(180+25)=-33+180-75-180-25=-100-33=-133
8)120-(-92+120-18)-92=120+92-120+18=108
a) 5x6x20 - 30x14
= 5x6x20 - 5x6x14
= (5x6)(20 - 14)
= 30x6
= 180
b) 9x350x2 - 6x50x3 - 200x18
= 9x7x50x2 - 2x3x50x3 - 4x50x2x9
= 2x9x50x7 - 2x9x50 - 2x9x50x4
= (2x9x50)(7 - 1 - 4)
= 900x2
= 1800
(với các bài này thì tìm thừa số chung rồi đặt nhân tử chung lại rồi tính thôi, không khó đâu ;)
~chuc em hoc tot