Một cửa hàng lần đầu bán được 28kg đường, lần sau bán được nhiều hơn lần đầu 13kg đường. Hỏi lần sau cửa hàng đó bán được bao nhiêu ki-lô-gam đường ?
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Buổi chiều cửa hàng bán được số ki-lô-gam đường là:
78 + 13 = 91 (kg)
Đáp số: 91kg đường
1 tấn = 1000 kg
Ngày thứ hai bán được : 300 x 2 = 600 (kg)
Hai ngày đầu bán được : 300 + 600 = 900 (kg)
Ngày thứ ba bán được : 1000 - 900 = 100 (kg)
Đáp số: 100kg đường.
1 tấn = 1000 kg
Ngày thứ hai bán được : 300 x 2 = 600 (kg)
Hai ngày đầu bán được : 300 + 600 = 900 (kg)
Ngày thứ ba bán được : 1000 - 900 = 100 (kg)
Đáp số: 100kg đường.
Phương pháp giải:
Tóm tắt
Muốn tìm lời giải ta lấy số ki-lô-gam đường bán được ở buổi sáng trừ đi 28kg.
Lời giải chi tiết:
Buổi chiều cửa hàng đó bán được số ki-lô-gam đường là:
72 – 28 = 44 (kg)
Đáp số: 44 kg.
bài giải
1 tấn =1000 kg
: 300 x 2 = 600 [ kg]
1000 - [300 + 600] =100 [ kg]
đáp số :100 kg đường
Ta có :1 tấn=1000kg
Ngày thứ 2 bán đc số đường là :300x2=600(kg)
=>Ngày thứ 3 bán đc số đường là:1000-300-600=100(kg)
Đáp số:100kg đường.
1 tấn = 1000 kg đường
Ngày thứ 2 bán được: 300 x 2 = 600 ( kg )
Ngày thứ 3 bán được: 1000 - 600 - 300 =100 (kg)
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Đổi 300 kg = 0,3 tấn
Ngày thứ hai bán được số tấn là:
0,3 x 2 = 0,6 ( tấn )
Ngày thứ ba bán số tán là:
1 - 0,3 - 0,6 = 0,1 ( tấn )
Đổi 0,1 tấn = 100 kg
Đáp số: 100 kg
đổi 1 tấn =1000kg
ngày thứ 2 bán được số kg đường là:
300*2=600{kg}
ngày thứ 3 bán được số kg đường là:
1000-{600+300}=100{kg}
đáp số:100 kg đường
Bài giải
Ngày thứ hai cửa hàng bán được số kg đường là: (0,25 điểm)
150 x 3 = 450 (kg) (0,5 điểm)
Cả hai ngày cửa hàng đó bán được số kg đường là: (0,25 điểm)
150 + 450 = 600 (kg) (0,75 điểm)
Đáp số: 600 kg đường (0,25 điểm)
Phương pháp giải:
Tóm tắt :
Muốn tìm lời giải ta lấy khối lượng đường bán được trong lần đầu cộng với 13kg.
Lời giải chi tiết:
Lần sau cửa hàng đó bán được số ki-lô-gam đường là:
28 + 13 = 41 (kg)
Đáp số: 41 kg.