[-8]+[-6]=-[8+6]=-14
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a) \(\left(15-x\right)+\left(x-12\right)=7-\left(-8+x\right)\)
\(15-x+x-12=7+8-x\)
\(x=12\)
b) \(x-\left\{55-\left[49+\left(-28-x\right)\right]\right\}=13-\left\{47+\left[25-\left(32-x\right)\right]\right\}\)
\(x-55+49-28-x=13-47-25+32-x\)
\(x=7\)
\(a,\left(15-x\right)+\left(x-12\right)=7-\left(-8+x\right)\)
\(15-x+x-12=7+8-x\)
\(15-x=3\)
\(x=12\)
\(b,x-\left\{55-\left[49+\left(-28-x\right)\right]\right\}=13-\left\{47+\left[25-\left(32-x\right)\right]\right\}\)
\(x-\left[55-\left(49-28-x\right)\right]=13-\left[47+\left(25-32+x\right)\right]\)
\(x-\left(55-49+28+x\right)=13-\left(47+25-32+x\right)\)
\(x-\left(34+x\right)=13-\left(40+x\right)\)
\(x-34-x=13-40-x\)
\(-27-x=-34\)
\(x=-27--34\)
\(x=7\)
\(c,\left|x-10\right|-\left|-12\right|=4\)
\(\left|x-10\right|-12=4\)
\(\left|x-10\right|=16\)
\(\Rightarrow x-10=16\)hoặc \(x-10=-16\)
\(x=26\)hoặc \(x=-6\)
1) \(\frac{5}{8}.\frac{7}{3}-\frac{5}{2}.\frac{1}{8}=\frac{5}{8}.\frac{7}{3}-\frac{5}{8}.\frac{1}{2}=\frac{5}{8}\left(\frac{7}{3}-\frac{1}{2}\right)=\frac{5}{8}.\frac{11}{6}=\frac{55}{48}\)
2) \(\frac{21}{10}.\frac{3}{4}-\frac{21}{10}.\frac{3}{4}=\frac{21}{10}\left(\frac{3}{4}-\frac{3}{4}\right)=\frac{21}{10}.0=0\)
3) \(\frac{-4}{11}:\frac{-6}{11}=\frac{-4}{11}.\frac{-11}{6}=\frac{-4.\left(-11\right)}{11.6}=\frac{-4.\left(-1\right)}{1.6}=\frac{4}{6}=\frac{2}{3}\)
4)\(\frac{2}{7}.\frac{14}{3}-1=\frac{2.14}{7.3}-1=\frac{2.2}{1.3}-1=\frac{4}{3}-1=\frac{1}{3}\)
5)\(\frac{4}{7}:\left(\frac{1}{5}.\frac{4}{7}\right)=\frac{4}{7}:\frac{4}{35}=\frac{4}{7}.\frac{35}{4}=\frac{4.35}{7.4}=\frac{1.5}{1.1}=5\)
6) \(\frac{12}{7}.\frac{7}{4}+\frac{35}{11}:\frac{245}{121}=\frac{12.7}{7.4}+\frac{35}{11}.\frac{121}{245}=\frac{3.1}{1.1}+\frac{35}{11}.\frac{121}{245}=3+\frac{35}{11}.\frac{121}{245}=3+\frac{35.121}{11.245}=\frac{1.11}{1.7}=\frac{11}{7}\)
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