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\(a,\dfrac{3}{5}+\dfrac{-5}{9}=\dfrac{27-25}{45}=\dfrac{2}{49}.\)
\(c,\dfrac{-27}{23}+\dfrac{5}{21}+\dfrac{4}{23}+\dfrac{16}{21}+\dfrac{1}{2}=\dfrac{-23}{23}+\dfrac{21}{21}+\dfrac{1}{2}=-1+1+\dfrac{1}{2}=\dfrac{1}{2}.\)
\(d,\dfrac{-8}{9}+\dfrac{1}{9}.\dfrac{2}{9}+\dfrac{1}{9}.\dfrac{7}{9}=\dfrac{-8}{9}+\dfrac{1}{9}.\left(\dfrac{2}{9}+\dfrac{7}{9}\right)=\dfrac{-8}{9}+\dfrac{1}{9}.1=\dfrac{-8+1}{9}=\dfrac{-7}{9}.\)
A = 2/1*5 + 2/5*9 + ... + 2/101*105
= 1/2(4/1*5 + 4/5*9 + ... + 4/101*105)
= 1/2(1 - 1/5 + 1/5 - 1/9 + ... + 1/101 - 1/105)
= 1/2(1 - 1/105)
= 1/2 * 104/105 = 52/105
Sửa câu b. Phân số thứ 2 phải là 4/5*8
B = 4/2*5 + 4/5*8 + ... + 4/47*50
= 4/3(3/2*5 + 3/5*8 + ... + 3/47*50)
= 4/3(1/2 - 1/5 + 1/5 - 1/8 + ... + 1/47 - 1/50)
= 4/3(1/2 - 1/50)
= 4/3 * 24/50 = 16/25
có rút gọn phân số 35/6 về phân số đc ko ? Nếu có thì mn rút gọn cho mik nhé !
Ai xong tr tui k cho
a: =-1/3+1/3=0
b: \(=\dfrac{4}{11}\left(-\dfrac{2}{7}-\dfrac{4}{7}-\dfrac{1}{7}\right)=\dfrac{4}{11}\cdot\left(-1\right)=-\dfrac{4}{11}\)
c: \(=10+\dfrac{5}{9}-3-\dfrac{5}{7}-4-\dfrac{5}{9}=3-\dfrac{5}{7}=\dfrac{16}{7}\)
d: \(=\dfrac{1}{3}+\dfrac{7}{4}-\dfrac{7}{4}+\dfrac{4}{5}=\dfrac{1}{3}+\dfrac{4}{5}=\dfrac{5+12}{15}=\dfrac{17}{15}\)
a: =-1/3+1/3=0
b: =411(−27−47−17)=411⋅(−1)=−411=411(−27−47−17)=411⋅(−1)=−411
c: =10+59−3−57−4−59=3−57=167=10+59−3−57−4−59=3−57=167
d: =13+74−74+45=13+45=5+1215=1715
a) \(\left(\frac{1}{5}+\frac{3}{5}\right)\times\frac{1}{4}\)
\(=\frac{4}{5}\times\frac{1}{4}\)
\(=\frac{4}{20}=\frac{1}{5}\)
\(\left(\frac{1}{5}+\frac{3}{5}\right)\times\frac{1}{4}=\frac{1}{5}\times\frac{1}{4}+\frac{3}{5}\times\frac{1}{4}\)
\(=\frac{1}{20}+\frac{3}{20}\)
\(=\frac{4}{20}=\frac{1}{5}\)
b) \(\left(\frac{7}{9}-\frac{2}{9}\right)\times\frac{3}{2}\)
\(=\frac{5}{9}\times\frac{3}{2}\)
\(=\frac{15}{18}=\frac{5}{6}\)
\(\left(\frac{7}{9}-\frac{2}{9}\right)\times\frac{3}{2}=\frac{7}{9}\times\frac{3}{2}-\frac{2}{9}\times\frac{3}{2}\)
\(=\frac{21}{18}-\frac{6}{18}\)
\(=\frac{15}{18}=\frac{5}{6}\)
c) \(\left(\frac{11}{13}-\frac{9}{13}\right)\times\frac{39}{21}\)
\(=\frac{2}{13}\times\frac{39}{21}\)
\(=\frac{78}{273}=\frac{2}{7}\)
\(\left(\frac{11}{13}-\frac{9}{13}\right)\times\frac{39}{21}=\frac{11}{13}\times\frac{39}{21}-\frac{9}{13}\times\frac{39}{21}\)
\(=\frac{429}{273}-\frac{351}{273}\)
\(=\frac{78}{273}=\frac{2}{7}\)
a,\(\left(\frac{1}{5}+\frac{3}{5}\right)x\frac{1}{4}\)
=\(\frac{4}{5}x\frac{1}{4}\)
=\(\frac{4}{20}\)
=\(\frac{1}{5}\)
,\(\left(\frac{1}{5}+\frac{3}{5}\right)x\frac{1}{4}\)
=\(\frac{4}{5}x\frac{1}{4}\)
=\(\frac{4x1}{5x4}\)
=\(\frac{1x1}{5x1}\)
=\(\frac{1}{5}\)
a: =1/8-1/8+2/5=2/5
b: =(-1/15-14/15)+(23/27+31/27)=2-1=1
c: \(=\dfrac{3}{7}\left(\dfrac{22}{21}+\dfrac{5}{21}+\dfrac{15}{21}\right)=\dfrac{3}{7}\cdot2=\dfrac{6}{7}\)
d: \(=\dfrac{-8}{9}\cdot\dfrac{3}{2}+\dfrac{1}{9}\cdot\dfrac{-3}{2}=-\dfrac{3}{2}\)
a) S
⇒ \(\dfrac{3}{5}+\dfrac{1}{4}=\dfrac{12}{20}+\dfrac{5}{20}=\dfrac{17}{20}\)
b) \(\)Đ
c) Đ
d) S
⇒ \(\dfrac{3}{4}:\dfrac{4}{9}=\dfrac{3}{4}\times\dfrac{9}{4}=\dfrac{27}{16}\)
* Mình chỉ giải thích những câu sai thôi nha
Chúc bạn học tốt
Giải:
a) \(M=21^9+21^8+21^7+...+21+1\)
Do \(21^n\) luôn có tận cùng là 1
\(\Rightarrow M=21^9+21^8+21^7+...+21+1\)
Tân cùng của M là:
\(1+1+1+1+1+1+1+1+1+1=10\) tận cùng là 0
\(\Rightarrow M⋮10\)
\(\Leftrightarrow M⋮2;5\)
b) \(N=6+6^2+6^3+...+6^{2020}\)
\(N=6.\left(1+6\right)+6^3.\left(1+6\right)+...+6^{2019}.\left(1+6\right)\)
\(N=6.7+6^3.7+...+6^{2019}.7\)
\(N=7.\left(6+6^3+...+6^{2019}\right)⋮7\)
\(\Rightarrow N⋮7\)
Ta thấy: \(N=6+6^2+6^3+...+6^{2020}⋮6\)
Mà \(6⋮̸9\)
\(\Rightarrow N⋮̸9\)
c) \(P=4+4^2+4^3+...+4^{23}+4^{24}\)
\(P=1.\left(4+4^2\right)+4^2.\left(4+4^2\right)+...+4^{20}.\left(4+4^2\right)+4^{22}.\left(4+4^2\right)\)
\(P=1.20+4^2.20+...+4^{20}.20+4^{22}.20\)
\(P=20.\left(1+4^2+...+4^{20}+4^{22}\right)⋮20\)
\(\Rightarrow P⋮20\)
\(P=4+4^2+4^3+...+4^{23}+4^{24}\)
\(P=4.\left(1+4+4^2\right)+...+4^{22}.\left(1+4+4^2\right)\)
\(P=4.21+...+4^{22}.21\)
\(P=21.\left(4+...+4^{22}\right)⋮21\)
\(\Rightarrow P⋮21\)
d) \(Q=6+6^2+6^3+...+6^{99}\)
\(Q=6.\left(1+6+6^2\right)+...+6^{97}.\left(1+6+6^2\right)\)
\(Q=6.43+...+6^{97}.43\)
\(Q=43.\left(6+...+6^{97}\right)⋮43\)
\(\Rightarrow Q⋮43\)
Chúc bạn học tốt!
a) \(2\frac{1}{3}-\sqrt{\frac{4}{9}}+\frac{-21}{9}\)
\(=\frac{7}{3}-\frac{2}{3}+\frac{-21}{9}\)
\(=\frac{5}{3}-\frac{21}{9}=\frac{-2}{3}\)