Tính:
2 5 + 5 6
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a: \(=\dfrac{4}{5}+\dfrac{1}{5}\cdot\dfrac{5}{2}=\dfrac{4}{5}+\dfrac{1}{2}=\dfrac{8}{10}+\dfrac{5}{10}=\dfrac{13}{10}\)
b: \(=\dfrac{5}{6}\cdot\dfrac{1}{5}\cdot\dfrac{2}{5}=\dfrac{1}{6}\cdot\dfrac{2}{5}=\dfrac{2}{30}=\dfrac{1}{15}\)
2) -3(4 - 7) + 5(-3 + 2)
= -3.4 + 3.7 - 5.3 + 5.2
= -12 + 21 -15 + 10
= 31 - 27
= 4
4) -5(2 - 7) + 4(2 - 5)
= -5.2 + 5.7 + 4.2 - 4.5
= -10 + 35 + 8 - 20
= 38 - 30
= 8
3: \(=20-12-8+12=20-8=12\)
5: \(=-18-42-21-35=-116\)
3: \(=-15+18-12+8=-27+26=-1\)
2: \(=-12+21-15+10=9-5=4\)
a: =5/30-12/30=-7/30
b: =-2-5/8=-16/8-5/8=-21/8
c: =6/13-14/39=18/39-14/39=4/39
d: =18/30-25/30=-7/30
e: =-5/9+5/12=-20/36+15/36=-5/36
a) \(\dfrac{-7}{30}\)
b) \(\dfrac{-21}{8}\)
c) \(\dfrac{-7}{30}\)
d) \(\dfrac{-5}{36}\)
Lời giải:
1.
$3\frac{1}{4}-2\frac{1}{3}=3+\frac{1}{4}-(2+\frac{1}{3})$
$=3-2+\frac{1}{4}-\frac{1}{3}$
$=1+\frac{1}{4}-\frac{1}{3}=\frac{5}{4}-\frac{1}{3}=\frac{11}{12}$
2.
$6\frac{5}{9}+2\frac{5}{6}=6+\frac{5}{9}+2+\frac{5}{6}=8+\frac{5}{6}+\frac{5}{9}=8+\frac{25}{18}=8+1+\frac{7}{18}=9+\frac{7}{18}=9\frac{7}{18}$
3.
$6\frac{5}{9}-2\frac{5}{6}=6+\frac{5}{9}-(2+\frac{5}{6})$
$=6+\frac{5}{9}-2-\frac{5}{6}$
$=(6-2)+\frac{5}{9}-\frac{5}{6}$
$=4+\frac{5}{9}-\frac{5}{6}=\frac{41}{9}-\frac{5}{6}=\frac{67}{8}$
\(\dfrac{4}{5}\)+\(\dfrac{-5}{4}\)=\(\dfrac{0}{4}\)
\(\dfrac{-1}{3}\)+\(\dfrac{2}{5}-\dfrac{5}{6}\)=\(\dfrac{-10}{30}+\dfrac{12}{30}-\dfrac{25}{30}\)=\(\dfrac{-23}{30}\)
\(\dfrac{2}{3}-\dfrac{5}{7}.\dfrac{14}{25}\)=\(\dfrac{2}{3}-\dfrac{2}{5}\)=\(\dfrac{10}{15}-\dfrac{6}{15}\)=\(\dfrac{4}{15}\)
Lời giải chi tiết:
3 + 4 – 5 = 2 | 8 – 6 + 3 = 5 | 10 – 3 – 2 = 5 |
5 + 1 + 2 = 8 | 4 + 4 – 6 = 2 | 5 + 5 – 7 = 3 |
6 – 4 + 8 = 10 | 9 – 6 + 5 = 8 | 4 + 3 – 3 = 4 |
\(=\dfrac{2}{35}\cdot\dfrac{5}{6}\cdot7+\dfrac{5}{2}\cdot\dfrac{7}{6}\cdot\dfrac{8}{9}\cdot\dfrac{7}{2}=\dfrac{1}{3}+\dfrac{245}{27}=\dfrac{245+9}{27}=\dfrac{254}{27}\)