a) Tìm y
b) Tính bằng cách thuận tiện nhất
23 x 83 + 15 x 23 + 23 x 2
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`x : 5/2 = 7/3`
`=> x= 7/3 xx 5/2`
`=>x= 35/6`
__
`23,7 xx 49 +23,7 xx 51`
`= 23,7 xx (49+51)`
`= 23,7 xx 100`
`=2370`
Lời giải:
a.
$x=\frac{7}{3}\times \frac{5}{2}=\frac{35}{6}$
b.
$23,7\times 49+23,7\times 51=23,7\times (49+51)=23,7\times 100=2370$
\(5\dfrac{3}{4}:3+2\dfrac{1}{4}\times\dfrac{1}{3}-\dfrac{1}{8}=\left(5\dfrac{3}{4}+2\dfrac{1}{4}\right)\times\dfrac{1}{3}-\dfrac{1}{8}\\ =8\times\dfrac{1}{3}-\dfrac{1}{8}=\dfrac{8}{3}-\dfrac{1}{8}=\dfrac{61}{24}\\ ----\\ \dfrac{3}{5}:\dfrac{5}{6}:\dfrac{6}{7}:\dfrac{7}{8}+\dfrac{2}{5}+\dfrac{23}{35}\\ =\dfrac{3}{5}\times\dfrac{6}{5}\times\dfrac{7}{6}\times\dfrac{8}{7}+\dfrac{2}{5}+\dfrac{23}{35}=\dfrac{18}{25}\times\dfrac{4}{3}+\dfrac{2}{5}+\dfrac{23}{35}=\dfrac{353}{175}\)
\(\frac{11}{6}\times\frac{15}{23}-\frac{11}{6}\times\frac{7}{23}\)= \(\frac{11}{6}\times\left(\frac{15}{23}-\frac{7}{23}\right)\)
=\(\frac{11}{6}\times\frac{8}{23}\)
= \(\frac{44}{69}\)
TL:
a)25 x 12 x 30 x 4
= (25 x 5) x (12 x 30)
= 100 x 360
= 36000
b)23 + 23 x 2 + 23 x 3 +23 x 4
= 23 x 1 + 23 x 2 + 23 x 3 +23 x 4
= 23 x (1 + 2 + 3 + 4)
= 23 x 10
= 230
c)248 x 2005 - 2005 x 148
= (248 - 148) x 2005
= 100 x 2005
= 200500
HT
tính bằng cách thuận tiện nhất
a,4/15 x 7/8 + 4/15 x 2/9
b, 13/29 x 23/11 -13/19 x 8/11 - 13/19 x 4/11
a, 25+35+76+65+22
=(65+35)+(76+22)+25
=100+100+25
=225
c , 78-23-25
=78-(23+25)
=78-48
=30
a , x-45=20
x=20+45
x=65
b , 45 - x=20
x =45-20
x= 25
TL:
8/15 x 5/6 = 40/90 = 4/9
41/20 x 3/4 = 123/80
(11/23 + 9/23) + (18/23 + 2/23) = 20/23 + 20/23 = 40/43
HT
\(\left(\frac{2}{3}\times\frac{4}{5}\right)\times\frac{5}{6}\) = \(\frac{2}{3}\times\frac{4}{5}\times\frac{5}{6}\)=\(\frac{2\times4\times5}{3\times5\times6}\)=\(\frac{2\times4\times5}{3\times5\times2\times3}\)=\(\frac{4}{9}\)
\(\frac{11}{23}+\frac{2}{23}+\frac{9}{23}+\frac{18}{23}\)=\(\frac{\left(11+9\right)+\left(18+2\right)}{23}\)=\(\frac{20+20}{23}\)=\(\frac{40}{23}\)
\(\frac{27}{12}+\frac{17}{6}-\frac{25}{36}-\frac{15}{6}\)=\(\left(\frac{27}{12}-\frac{25}{36}\right)+\left(\frac{17}{6}-\frac{15}{6}\right)\)=\(\frac{14}{9}+\frac{2}{6}\)=\(\frac{17}{9}\)
/HT\
( 20,33 + 35,12) x 33 – 45,45 x 23 – 10 x 23
= 55,45 x 33 - (45,45 + 10) x 23
= 55,45 x 33 - 55,45 x 77
= 55,45 x ( 33 - 23)
= 55, 45 x 10 = 554,5
\(\dfrac{1}{2}\) xy=\(\dfrac{17}{42}\)
=\(\dfrac{17}{42}\):\(\dfrac{1}{2}\)
= \(\dfrac{34}{42}\)